\(C=\frac{1.5.6+2.10.12+24.8.10}{1.3.5+2.6.10+8.6.20}\)

\(C=\frac{1.5.6.\left(1^3+2^3+8^2\right)}{1.3.5.\left(1^3+2^3+8^2\right)}=\frac{6}{3}=2\)

Bạn nên tách tử số và mẫu số ra thì sẽ tính được .                                                                                                                                            

toán lop may the

1/2.3+1/3.4+1/4.5+1/5.6+1/6.7+1/7.8+1/8.9+1/9.10

=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6+1/7-1/7+1/8-1/8+1/9+1/9-1/10

=1/2-1/10

=5/10-1/10

=4/10=2/5

\(\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+\frac{1}{5x6}+\frac{1}{6x7}+\frac{1}{8x9}+\frac{1}{9x10}\)

\(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(\frac{1}{2}-\frac{1}{10}\)

\(\frac{2}{5}\)

= 1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10

= 1/2-0-0-0-0-0-0-0-0-1/10

=1/2 - 1/10 

=2/5

tớ trước nhé

:V Làm sai hết rồi sai ngay từ bước đầu tiên.

\(\frac{1}{3.4}-\frac{1}{4.5}-\frac{1}{5.6}-....-\frac{1}{9.10}\)

\(=\frac{1}{3.4}-\left(\frac{1}{4.5}+\frac{1}{5.6}+....+\frac{1}{9.10}\right)\)

\(=\frac{1}{12}-\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+....+\frac{1}{9}-\frac{1}{10}\right)\)

\(=\frac{1}{12}-\left(\frac{1}{4}-\frac{1}{10}\right)\)

\(=\frac{1}{12}-\frac{3}{20}\)

\(=\frac{-11}{12}\)

\(\frac{1}{3.4}-\frac{1}{4.5}-...-\frac{1}{9.10}\)

= \(-\left(\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{9.10}\right)\)

= \(-\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{10}\right)\)

= \(-\left(\frac{1}{3}-\frac{1}{10}\right)\)

= \(-\frac{7}{30}\)

\(=-(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{9}-\frac{1}{10})\)

\(=-\left(\frac{1}{3}-\frac{1}{10}\right)\)

\(=-\frac{7}{30}\)

~ Hok tốt ~

Đặt A=............(đề bài)

=>2A=\(2\left(\frac{1}{1.3}+\frac{1}{2.4}+...+\frac{1}{8.10}\right)\)

=>2A=\(\frac{2}{1.3}+\frac{2}{2.4}+...+\frac{2}{8.10}\)

=>2A=\(\left(\frac{2}{1.3}+...+\frac{2}{7.9}\right)+\left(\frac{2}{2.4}+...+\frac{2}{8.10}\right)\)

=>2A=\(\left(\frac{1}{1}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{9}\right)+\left(\frac{1}{2}-\frac{1}{4}+...+\frac{1}{8}-\frac{1}{10}\right)\)

=>2A=\(\left(1-\frac{1}{9}\right)+\left(\frac{1}{2}-\frac{1}{10}\right)\)

=>2A=\(\frac{8}{9}+\frac{2}{5}\)

=>2A=\(\frac{58}{45}\)

=>A=\(\frac{58}{45}:2\)

=>A=\(\frac{29}{45}\)

\(\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{8.9.10}=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}\right)+\frac{1}{2}.\left(\frac{1}{2.3}-\frac{1}{3.4}\right)+...+\frac{1}{2}.\left(\frac{1}{8.9}-\frac{1}{9.10}\right)\)

\(=\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{8.9}-\frac{1}{9.10}\right)\)

\(\frac{1}{2}.\left(\frac{1}{1.2}-\frac{1}{9.10}\right)=\frac{1}{2}.\frac{22}{45}=\frac{11}{45}\)

=1-1/186 bạn tự tính nha 

k mình

=1/8-1/10+1/10-1/12+....+1/184-1/186

=1/8-1/186

Hok tốt

.................................{+++++}...................................

Đặt \(A=\frac{1}{8\times10}+\frac{1}{10\times12}+...+\frac{1}{184\times186}\)

\(\Rightarrow A=\frac{1}{2}\times\left(\frac{2}{8\times10}+\frac{2}{10\times12}+...+\frac{2}{184\times186}\right)\)

\(\Rightarrow A=\frac{1}{2}\times\left(\frac{1}{8}-\frac{1}{10}+\frac{1}{10}-\frac{1}{12}+...+\frac{1}{184}-\frac{1}{186}\right)\)

\(\Rightarrow A=\frac{1}{2}\times\frac{89}{774}\)

\(\Rightarrow A=\frac{89}{1488}\)

Đáp số to qá nên sợ sai T.T

~Std well~

#Mina

A và B dễ 

Bài 2:

sai đề bài vì ngay từ cái phép tính đầu đã ko theo quy luật rồi 

\(A=\frac{-3}{5}-\frac{2}{5}+2\)

\(A=-1+2=1\)

\(B=\left(6-\frac{14}{5}\right).\frac{25}{8}-\frac{8}{5}=\frac{1}{4}\)

nÀ NÍ sao lại = đây là dấu trừ hay cộng 1/4

;1/4 nha