rewrite the sentence using adverb phrase in brackets

1,I see her parents every Sunday morning.(last Sunday)

=> Last Sunday I see her parents.

2,My friend John alwways asks a lot of questions.(this morning)

=>This morning my friend John asks a lot of questions.

3,They go to the mountain in the winter.(last winter)

=>Last winter,they went to the mountain.

4,Julie meets Tom from schooll every afternoon.(this afternoon)

=>This afternoon Tom met Julie .

5,He eat a lot in the evenings.(last night)

=>Last night,he ates a lot.

6,I love cycling at the weekend.(when I was a child)

=>When I was a child,I loved cycling.

7,That TV programme starts at 7:30 every Friday.(this morning)

=>TV programme started in this morning.

8,We always have a nice time with them. (on holiday)

=>On holiday, we had a nice time with them.

9,The garden looks lovely in the spring.(last spring)

=>Last spring ,the garden looked lovely.rewrite the sentence using adverb phrase in brackets

10,The sun rises at 6 a.m every morning.(yesterday)

=>Yesterday, the sun rose at 6 a.m .

Ngày 13 tháng 3 năm 1954

☘ Trả lời : 

- Từ ngày 13 tháng 3 năm 1954 đến ngày 7 tháng 5 năm 1954 . 

EX7. Rewrite the sentences using adverb phrases in brackets.

1. I see her parents every Sunday morning. (last Sunday)

=> I saw her parent last Sunday morning.
2. My friend, John always asks a lot of questions . (this morning)
=> My friend John asked a lot of questions this morning.

3. They go to the mountain in the winter. (last winter)
=> They went to the mountain last winter.
4. Julie meets Tom from school every afternoon. (this afternoon)
=> Julie met Tom from school this afternoon.
5. He eats a lot in the evening. (last night)
=> He ate a lot last night.
6. I love cycling at the weekend. (when I was a child)
=> I loved cycling when I was a child.

7. That TV programme starts at 7:30 every Friday (this morning)
=> That TV programme started at 7.30 this Friday morning.
8. We always have a nice time with them. (on holiday)
=> We had a nice time with them on holiday.
9. The garden looks lovely in the spring. (last spring)
=> The garden looked lovely last spring.
10. The sun rises at 6 a.m every morning. (yesterday)
=> The sun rose at 6 a.m yesterday morning.

1 send - will receive 

2 do - will improve

3 find - will give

4 will go - has

5 will go- gets

6 doesn't phone - will leave

7 don't study - won't pass

8 rains - won't have to

9 won't be able - watch

10 can't move - isn't

11 study - will pass

Lỗi r, xem lại nhé

a: Xét tứ giác ABQN có

\(\widehat{BQN}=\widehat{QNA}=\widehat{NAB}=90^0\)

=>ABQN là hình chữ nhật

b: Xét ΔCAD có

DN,CH là các đường cao

DN cắt CH tại M

Do đó: M là trực tâm của ΔCAD

=>AM\(\perp\)CD

c: Xét ΔHAB vuông tại H và ΔHCA vuông tại H có

\(\widehat{HAB}=\widehat{HCA}\left(=90^0-\widehat{ABC}\right)\)

Do đó: ΔHAB đồng dạng với ΔHCA

=>\(\dfrac{HA}{HC}=\dfrac{HB}{HA}\)

=>\(HA^2=HB\cdot HC\)

=>\(HA=\sqrt{HB\cdot HC}\)

 1.It is a- six hour drive from London to Edinburgh.

2.There is an eight- o'clock train every morning. 

Bài 4

a/ \(x=\widehat{ABC};y=\widehat{ADC}\)

Ta có a//b; \(a\perp c\Rightarrow b\perp c\Rightarrow x=\widehat{ABC}=90^o\)

Xét tứ giác ABCD

\(y=\widehat{ADC}=360^o-\widehat{BAD}-\widehat{ABC}-\widehat{BCD}\) (tổng các góc trong của tứ giác = 360 độ)

\(\Rightarrow y=\widehat{ADC}=360^o-90^o-90^o-130^o=50^o\)

b/ Kéo dài n về phí B cắt AC tại D

\(\Rightarrow\widehat{CBD}=180^o-\widehat{nBC}=180^o-105^o=75^o\)

Xét tg BCD có

\(\widehat{BDC}=180^o-\widehat{CBD}-\widehat{BCD}=180^o-75^o-60^o=45^o=\widehat{mAC}\)

=> Am//Bn (Hai đường thẳng bị cắt bởi đường thẳng thứ 3 tạo thành hai góc đồng vị bằng nhau thì chúng // với nhau)

Bài 5

\(\frac{a}{3b}=\frac{b}{3c}=\frac{c}{3a}=\frac{a+b+c}{3\left(a+b+c\right)}=\frac{1}{3}\)

Ta có \(\frac{a}{3b}=\frac{b}{3c}=\frac{a+b}{3\left(b+c\right)}=\frac{1}{3}\Rightarrow\frac{a+b}{b+c}=1\Rightarrow a+b=b+c\)

\(\frac{b}{3c}=\frac{c}{3a}=\frac{b+c}{3\left(c+a\right)}=\frac{1}{3}\Rightarrow\frac{b+c}{c+a}=1\Rightarrow b+c=c+a\)

\(\Rightarrow a+b=b+c=c+a\)

\(\frac{c}{3a}=\frac{a}{3b}=\frac{c+a}{3\left(a+b\right)}=\frac{1}{3}\Rightarrow\frac{c+a}{a+b}=1\)

Từ \(\frac{a+b}{b+c}=\frac{a}{b+c}+\frac{b}{b+c}=\frac{a}{b+c}+\frac{b}{c+a}=1\) (1)

Từ \(\frac{b+c}{c+a}=\frac{b}{c+a}+\frac{c}{c+a}=\frac{b}{c+a}+\frac{c}{a+b}=1\) (2)

Từ \(\frac{c+a}{a+b}=\frac{c}{a+b}+\frac{a}{a+b}=\frac{c}{a+b}+\frac{a}{b+c}=1\) (3)

Công 2 vế của (1) (2) và (3)

\(\Rightarrow\frac{a}{b+c}+\frac{b}{c+a}+\frac{b}{c+a}+\frac{c}{a+b}+\frac{c}{a+b}+\frac{a}{b+c}=3\)

\(\Rightarrow2\left(\frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}\right)=3.\)

\(\Rightarrow\frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}=\frac{3}{2}\)

\(\Rightarrow M=2018\left(\frac{a}{b+c}+\frac{b}{c+a}+\frac{c}{a+b}\right)=\frac{2018.3}{2}=3027\)

4:

a: Xét ΔADH vuông tại D và ΔHEA vuông tại E có

AH chung

góc HAD=góc AHE

=>ΔADH=ΔHEA

=>DH=EA

b: góc ADH=góc AEH=góc DAE=90 độ

=>ADHE là hình chữ nhật

mà AH cắt DE tại I

nên IA=IH=ID=IE

c: ADHE là hình chữ nhật
=>góc ADE=góc AHE

mà góc AHE=góc ACB

nên góc ADE=góc ACB