Hả... 1+1=2

=2

2 nha ultr

đây mà là câu hỏi lớp 6 á hả

Bài 1:

a) \(=\dfrac{\sqrt{5}.\sqrt{7}}{5}=\dfrac{\sqrt{35}}{5}\)

b) \(=\dfrac{\left|y\right|}{\sqrt{3}}=\dfrac{\sqrt{3}y}{3}\)

c) \(=\dfrac{\sqrt{2}}{\sqrt{t}}=\dfrac{\sqrt{2t}}{t}\)

d) \(=\sqrt{\dfrac{7p^2-3p^2}{7}}=\sqrt{\dfrac{4p^2}{7}}=\dfrac{2\left|p\right|}{\sqrt{7}}=\dfrac{-2\sqrt{7}p}{7}\)

Bài 2:

a) \(=\dfrac{\sqrt{21}-\sqrt{15}}{3}\)

b) \(=\dfrac{10\left(4+3\sqrt{2}\right)}{16-18}=-20-15\sqrt{2}\)

c) \(=\dfrac{\left(3\sqrt{10}-5\right)\left(6+\sqrt{10}\right)}{36-10}=\dfrac{18\sqrt{10}+30-30-5\sqrt{10}}{26}=\dfrac{13\sqrt{10}}{26}=\dfrac{\sqrt{10}}{2}\)

a) 0,63 x 8 + 0,63 + 0,63 x 9,89

= 0.63 x ( 8+1+9.89 ) = 0.63 x 18.98 = 11.9

b) 9,89 x 99 + 9,89

= 9.89 x ( 99 + 1) = 9.89 x 100 = 989

a) 0,63 x 8 + 0,63 + 0,63 x 9,89

= 0,63 x 8 + 0,63 x 1 + 0,63 x 9,89

= 0,63 x ( 8 + 1 + 9,89 )

= 0,63 x 18,89

= 11,9007

b) 9,89 x 99 + 9,89

= 9,89 x 99 + 9,89 x 1

= 9,89 x ( 99 + 1 )

= 9,89 x 100

= 989

\(2x-5+x=2^0\)

\(2x+x-5=2^0\)

\(3x-5=2^0=1\)

\(3x=1+5=6\)

\(x=6:3\)

\(x=2\)

Vậy \(x=3\)

2x - 5 + x = 2^0

2x - 5 + x  = 1

2x + x - 5 = 1

3x - 5 =1

3x = 6

x = 2

ta có

2x-5+x=\(2^0\)=1

=>2x+x-5=1

=3x-5=1

=>3x=5+1=6

=>x=2

a) 6.(x + 11) - 7.(2 - x) = 26

6x + 66 - 14 + 7x = 26

13x + 52 = 26

13x = 26 - 52

13x = -26

x = -26 : 13

x = -2

b) 2.(x - 1) - 3.(2x + 2) - 4.(2x + 3) = -2016

2x - 2 - 6x - 6 - 8x - 12 = -2016

-12x - 20 = -2016

-12x = -2016 + 20

-12x = -1996

x = (-1996) : (-12)

x = 49/3