Tính bằng cách thuận tiện nhất:

a ) 

3,24 x 2,6 + 3,24 x 0,74 

= 3,24 x ( 2,6 + 0,74 ) 

= 3,24 x 3,34

= 10,8216 

nhưng theo mình nghĩ nếu là thuận như vầy nè:

 a ) 3,24 x 2,6 + 3,24 x 0,4 

= 3,24 x ( 2,6 + 0,4 ) 

= 3,24 x 3 

= 9,72 

tk và kb vs mk nha! Cách đấy là theo mk nghĩ nhá!!!!!!!!!!!

0,25+ 3/4=80+1/5+2000

1/4+3/4+8/5=1/5+2000

 \(=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+...+\frac{1}{10}\)có 9 p/số

\(=\frac{1}{10}.9=\frac{9}{10}\)

= 1/10 + 1/10 + ...................... + 1/10 có 9 phân số

= 1/10 x 9

= 9/10

ai tk mình mình đang bị âm điểm

9 / 12 bn nha

tk mk nha các bn

thanks nhiêu

\(17\cdot\frac{3}{4}-17\cdot0,25+17\cdot\frac{1}{2}\)

\(=17\cdot0,75-17\cdot0,25+17\cdot0,5\)

\(=17\cdot\left(0,75-0,25+0,5\right)\)

\(=17\cdot1\)

\(=17\)

\(17\times\frac{3}{4}-17\times0,25+17\times\frac{1}{2}\)\(=17\times\frac{3}{4}-17\times\frac{1}{4}+17\times\frac{1}{2}\)\(=17\times\left(\frac{3}{4}-\frac{1}{4}+\frac{1}{2}\right)\)

\(=17\times\left(1\right)\)\(=17\)

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

=17,5 x(1 -3/4 +1/2)

=17,5x(1-0,75+0,5)

=17,5 x 0,75

=13,125

17,5.3/4-17,5.0,25+17,5.1/2

=17,5.(3/4-25/100+1/2)

=17,5.(3/4-1/4+1/2)

=17,5.4/4

=17,5.1

=17,5

\(=\frac{1}{10}+\)\(\frac{1}{10}+\)\(\frac{1}{10}+\)\(\frac{1}{10}+\)\(\frac{1}{10}+\)\(\frac{1}{10}+\)\(\frac{1}{10}+\)\(\frac{1}{10}+\)\(\frac{1}{10}\)

\(=\frac{1}{10}.9\)

\(=\frac{9}{10}\)

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\(\frac{1}{10}+\frac{2}{20}+\frac{3}{30}+\frac{4}{40}+\frac{5}{50}+\frac{6}{60}+\frac{7}{70}+\frac{8}{80}+\frac{9}{90}\)

\(=\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}+\frac{1}{10}\)

\(=\frac{1}{10}\times9\)

\(=\frac{9}{10}\)

x + 1= 1

x= 1- 1

x= 0 

= x=0

 k cho 

\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)

\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)

\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)

\(=4-1\frac{3}{4}\)

\(=2\frac{1}{4}\)

\(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)

\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)

\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)

\(=4-\frac{7}{4}\)

\(=\frac{16}{4}-\frac{7}{4}\)

\(=\frac{9}{4}\)

=   \(6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}=6\frac{5}{7}-2\frac{5}{7}\)\(-1\frac{3}{4}\)=   \(4-1\frac{3}{4}\)=\(\frac{9}{4}\)

47/7 - (7/4 + 19/7) =47/7 -125/28 =gomen =tao xin lỗi chịu rùi = <3

\(6\frac{5}{7}- \left(1\frac{3}{4}+2\frac{5}{7}\right)\)

\(=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}\)

\(=\left(6\frac{5}{7}-2\frac{5}{7}\right)-1\frac{3}{4}\)

\(=\left(\frac{47}{7}-\frac{19}{7}\right)-\frac{7}{4}\)

\(=\frac{28}{7}-\frac{7}{4}\)

\(=4-\frac{7}{4}\)

\(=\frac{16}{4}-\frac{7}{4}\)

\(=\frac{9}{4}\)

\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{4}{6}+\frac{9}{12}+\frac{16}{20}=\left(\frac{1}{3}+\frac{4}{6}\right)+\left(\frac{1}{4}+\frac{9}{12}\right)+\left(\frac{1}{5}+\frac{16}{20}\right)\)

\(=1+1+1=3\)

Ta có\(\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{4}{6}+\frac{9}{12}+\frac{16}{20}=\left(\frac{1}{3}+\frac{4}{6}\right)+\left(\frac{1}{4}+\frac{9}{12}\right)+\left(\frac{1}{5}+\frac{16}{20}\right)\)

\(=\left(\frac{2+4}{6}\right)+\left(\frac{3+9}{12}\right)+\left(\frac{4+16}{20}\right)\)

\(=\frac{6}{6}+\frac{12}{12}+\frac{20}{20}\)

\(=1+1+1\)

\(=3\)