lớp 6 đọc bài lớp 3 kiểu :)?

k hok hành j mà cứ ní nhiều 

người ta trả lời thế nào thì kệ người t đúng hay sai thì người t cx biết cần j m nhắc làm j cho mệt k hok hành hẳn noi đi r doots đắc

\(=14-14\sqrt{2}+7+14\sqrt{2}=21\)

\(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right)\sqrt{7}+7\sqrt{8}=\left(2\sqrt{7}-2\sqrt{2}\sqrt{7}+\sqrt{7}\right)\sqrt{7}+7\sqrt{8}=2.7-2\sqrt{2}.7+7+14\sqrt{2}=21-14\sqrt{2}+14\sqrt{2}=21\)

a) \(\dfrac{4}{7}+\dfrac{2}{8}=\dfrac{32}{56}+\dfrac{14}{56}=\dfrac{46}{56}=\dfrac{23}{28}\)

b) \(\dfrac{8}{6}-\dfrac{8}{24}=\dfrac{32}{24}-\dfrac{8}{24}=\dfrac{24}{24}=1\)

c) \(\dfrac{9}{28}\times\dfrac{14}{9}=\dfrac{126}{252}=\dfrac{1}{2}\)

d) \(\dfrac{7}{6}\div\dfrac{2}{3}=\dfrac{7}{6}\times\dfrac{3}{2}=\dfrac{21}{12}\)

1. \(\dfrac{4}{7}+\dfrac{2}{8}=\dfrac{32}{56}+\dfrac{14}{56}=\dfrac{32+14}{56}=\dfrac{46}{56}=\dfrac{23}{28}\)

2. \(\dfrac{8}{6}-\dfrac{8}{24}=\dfrac{32}{24}-\dfrac{8}{24}=\dfrac{32-8}{24}=\dfrac{24}{24}=1\)

3. \(\dfrac{9}{28}\text{×}\dfrac{14}{9}=\dfrac{9\text{×}14}{28\text{×}9}=\dfrac{126}{252}=\dfrac{7}{14}\)

4. \(\dfrac{7}{6}:\dfrac{2}{3}=\dfrac{7}{6}\text{×}\dfrac{3}{2}=\dfrac{7\text{×}3}{6\text{×}2}=\dfrac{21}{12}=\dfrac{7}{4}\)

= 23/28

= 1

= 1/2

= 21/12

a) 7 x 5 = 35       7 x 6 = 42       7 x 8 = 56       7 x 4 = 28

    35 : 7 = 5       42 : 7 = 6       56 : 7 = 8       28 : 7 = 4

b) 42 : 7 = 6       35 : 7 = 5       63 : 7 = 9       16 : 2 = 8

    14 : 7 = 2       49 : 7 = 7       7 : 7 = 1       48 : 6 = 8

    28 : 7 = 4       70 : =10       21 : 7 = 3       56 : 7 = 8

 7 X 5 = 35

\(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right)\cdot\sqrt{7}+7\sqrt{8}\)

\(=\left(3\sqrt{7}-2\sqrt{14}\right)\cdot\sqrt{7}+14\sqrt{2}\)

\(=21-14\sqrt{2}+14\sqrt{2}\)

=21