Ta có: 870 = 29.30

Nên suy ra: 870 – 29.30 = 29.30 – 29.30 = 0

G = 0.

SAI RỒI, HẾT.

\(\text{(870 – 1.2).(870 – 2.3).(870 – 3.4) … (870 – 99.100)}\)

\(\text{Ta có: 870 = 29.30}\)

\(\Rightarrow\text{870 – 29.30 = 29.30 – 29.30 = 0}\)

\(\Rightarrow=0\)

a)C= (-124)+ (36 + 124 - 99 ) - ( 136 - 1 ) = (-124) +36 +124 -99 - 136 +1

= -198

b) D = { 115+[ 32 - ( 132 -5 )] } +(-25) +(-25)

= {115+[32-132+5]} +(-25) + (-25)

= {115+(-95)} + (-25)+ (-25)

= 20 +(-25) +(-25) = -30

c)F = [(123 - 17 ) - (123 + 33 ) ] - { 34 - [ 34 + ( 57 -50 ) -7 ] }

= [123 -17 -123 -33 ] - {34- [34 + 57-50 -7]}

= -50 - {34-34} = -50 - 34 +34 = -50

d) mik bo nha

e) E = (-7) +( -2020) -(-7) +2020

= [(-7)-(-7)]+[(-2020) +2020]= 0

g)B= (-2019)-( 29 - 2019) = (-2019) - 29 +2019 = -29

co moi cau d mik ko biet lam :v

(124.137+152):(870+235.122)

=17140:29540

=\(\frac{857}{1477}\)

   2+4+6+........+2n=870

2.(2+4+6+.......+2n)=870

    2+4+6+........+2n=870:2

    2+4+6+....... +2n=435

=>n.(n+1):2=435

n.(n+1)=435.2

n.(n+1)=870

Vì 29.30=870=>n=29

\(2\left(1+2+3+...+n\right)=870\)

\(\leftrightarrow2.\frac{n\left(n-1\right)}{2}=870\)

\(\leftrightarrow n\left(n-1\right)=870=30.29\)

\(\rightarrow n=30\)

2+4+6+...+2n=870

=>2(1+2+3+...+n)=870

=>1+2+3+...+n=870:2

=>1+2+3+...+n=435

=>(n+1).n:2=435

=>(n+1).n=435.2

=>(n+1).n=870

=>(n+1).n=29.30

=>n=29

free fire

liên quân

yamatecuraxai

a) 1990.1990 - 1992.1988

= 1990.1990 - (1990 + 2)(1990 - 2)

= 1990.1990 - 1990.1990 + 4 = 4

b) (1374.57 + 687.86) : (870 + 235.122)

= (1374.57 + 687.2.43) : (10.87 + 5.47.2.61)

= (1374.57 + 1374.43) : (10.87 + 10.47.61)

= [1374(57 + 43)] : [10(87 + 47.61)]

= (1374.100) : [10(87 + 47.61)] (đoạn này mẫu số xấu quá, hetcuu)

c) (124.237 + 152) : (870 + 235.122)

= (124.235 + 124.2 + 152) : (870 + 235.122)

= (122.235 + 2.235 + 2.124 + 152) : (870 + 235.122)

= (122.235 + 470 + 248 + 152) : (235.122 + 870)

= (122.235 + 870) : (235.122 + 870) = 1

d) \(\dfrac{423134\cdot846267-423133}{846267\cdot423133+423134}=\dfrac{423133\cdot846267+846267-423133}{846267\cdot423133+423134}\)

\(=\dfrac{423133\cdot846267+423134}{846267\cdot423133+423134}=1\)