\(x^3+3x+7x^3+2x^2+5x+1\)

\(=8x^3+2x^2+8x+1\)

tham khảo nhé~

=(x^3+7x^3)+2x^2+(3x+5x)+1

=8x^3+2x^2+8x+1

Hok tot!!!!

7x³ + x³ + 2x² + 5x + 3x + 1

= (7x³ + x³) + 2x² + (5x + 3x) + 1

= 8x³ + 2x² + 8x + 1

= 2x.(4x² + x + 4) + 1

Chúc em học tốt!!!

help voi a

a: \(\left(3x+2\right)^2+4x-3x^2+2\left(5x-2\right)\left(5x+2\right)-75x^2\)

\(=9x^2+12x+4+4x-3x^2+50x^2-8-75x^2\)

\(=-19x^2+16x-4\)

19 22 25 28 5(3x + 2) – 4(2x +3) x*(1 + 2x) 4(1 + x) – 3(2x-5) 4x–8(6) - X) 23/ ... 2x” – 4x + 3x – 6 = 2x” – X-6 (b) (x-3) = (x-3)(x-3) (c) (2x+y)(2x–y) = x* = x* – 3x ... (x - 6)” 7 (3x + 5)(x-6) 8 (8x + 2)(3x + 4) (4x – 1)(2x – 3) 10 (2x +5)* 11 (8x – 3)(2x + ... 27 (4x + 3y)(x + y) 28 (2x + 5)(5x – 2) (4x – 3y)(4x + y) 30 (7x + 2y)(3x + 4y) 24/ ...

\(a)=3x\cdot\left(2x-7-4x+5\right)=3x\cdot\left(-2x-2\right)=3x\cdot\left[-2\cdot\left(x+1\right)\right]\)

a: \(=2x^3:\dfrac{-3}{2}x+4x:\dfrac{3}{2}x-5:\dfrac{3}{2}\)

=-4/3x^2+8/3-10/3

=-4/3x^2-2/3

d: \(\dfrac{3x^3-5x+2}{x-3}=\dfrac{3x^3-9x^2+9x^2-27x+22x-66+68}{x-3}\)

\(=3x^2+9x+22+\dfrac{68}{x-3}\)

\(P\left(x\right)=5+x^3-2x+4x^3+3x^2-10=\left(x^3+4x^3\right)+3x^2+2x-\left(10-5\right)=5x^3+3x^2+2x-5\)

\(Q\left(x\right)=4-5x^3+2x^2-x^3+6x-11x^3-8x=-\left(5x^3+x^3+11x^3\right)+2x^2-\left(8x-6x\right)+4=-17x^3+2x^2-2x+4\)

\(P\left(x\right)-Q\left(x\right)=\left(5x^3+3x^2+2x-5\right)-\left(-17x^3+2x^2-2x+4\right)=5x^3+3x^2+2x-5+17x^3-2x^2+2x-4\)

                             \(=\left(5x^3+17x^3\right)+\left(3x^2-2x^2\right)+\left(2x+2x\right)-\left(5+4\right)=22x^3+x^2+4x-9\)

Ta có 2x(2x + 1)² - 3x(x + 3)(x - 3) - 4x(x + 1)²

= 2x(4x² + 4x + 1) - 3x(x² - 9) - 4x(x² + 2x + 1) 

= 8x³ + 8x² + 2x - 3x³ + 27x - 4x³ - 8x² - 4x

= 8x³ - 3x³ - 4x³ + 8x² - 8x² + 2x + 27x - 4x

= x³ + 25x 

a oi hinh nhu sai r con +16x² nua co a , anh tinh lai ho e duoc kh

Kiều Trinh Vũ ko có + 16x² nhá vì 8x² - 8x² = 0 nhá