a)b) Bạn nhân cả tử và mẫu với 2. Mình làm luôn, ko ghi lại đề bài

a)\(\frac{2}{4.9}+\frac{2}{9.14}+\frac{2}{14.19}+...+\frac{2}{504.509}\)

=\(\frac{2}{5}.\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+\frac{1}{14}-\frac{1}{19}+...+\frac{1}{504}-\frac{1}{509}\right)\)

=\(\frac{2}{5}.\left(\frac{1}{4}-\frac{1}{509}\right)\)

=\(\frac{2}{5}.\frac{505}{2036}=\frac{101}{1018}\)

b)\(\frac{2}{10.18}+\frac{2}{18.26}+\frac{2}{26.34}+...+\frac{2}{802.810}\)

=\(\frac{1}{4}\left(\frac{1}{10}-\frac{1}{18}+\frac{1}{18}-\frac{1}{26}+\frac{1}{26}-\frac{1}{34}+...+\frac{1}{802}-\frac{1}{810}\right)\)

=\(\frac{1}{4}.\left(\frac{1}{10}-\frac{1}{810}\right)\)

=\(\frac{1}{4}.\frac{8}{81}=\frac{2}{81}\)

c) Mình biết làm, ddoiwtj tí nữa mình làm cho. Giờ đang mỏi tay

Thẳng Nobita kun có chép bài thì đừng t..i..c..k cho nó

Đề bài của bạn thật là khó hiểu 

cũng khó đó

A=\(\frac{1}{2.9}+\frac{1}{9.7}+\frac{1}{7.19}+...+\frac{1}{252.509}\)

 =\(\frac{1}{2}-\frac{1}{509}\)

 =\(\frac{507}{1018}\)

b)\(\dfrac{1}{7}B=\dfrac{1}{10.18}+\dfrac{1}{18.26}+\dfrac{1}{26.34}+...+\dfrac{1}{802.810}\)

\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{8}{10.18}+\dfrac{8}{18.26}+\dfrac{8}{26.34}+...+\dfrac{8}{802.810}\right)\)

\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{1}{10}-\dfrac{1}{18}+\dfrac{1}{18}-\dfrac{1}{26}+\dfrac{1}{26}-\dfrac{1}{34}+...+\dfrac{1}{802}-\dfrac{1}{810}\right)\)

\(\dfrac{1}{7}B=\dfrac{1}{8}\left(\dfrac{1}{10}-\dfrac{1}{810}\right)\)

\(\dfrac{1}{7}B=\dfrac{1}{8}.\dfrac{8}{81}\)

\(\dfrac{1}{7}B=\dfrac{1.8}{8.81}\)

\(\dfrac{1}{7}B=\dfrac{1}{81}\)

\(B=\dfrac{1}{81}:\dfrac{1}{7}\)

\(B=\dfrac{7}{81}\)

28373822839999999999999399393393933939939393393939393939393939933939393939393939393993939393939399393

C= 24.7 - 35.9 +27.10 - 39.13 +...+2301.304 - 

564564654546544444444444444444444444444444456456

a)Ta có: 

A= 1/2.9 + 1/9.7 +...+1/252.509

  = 2/5.(5/4.9 + 5/9.14 + 5/14.19 +...+ 1/504.509)

  = 2/5.(1/4 - 1/9 + 1/9 - 1/14 + 1/14 - 1/19 +...+ 1/504 - 1/509)

  = 2/5.(1/4 - 1/509)

  = 101/1018

Vậy A = 101/1018

b)Ta có:

B= 1/10.9 +1/18.13 + 1/26.17 +...+ 1/802.405)

  = 1/4.(8/10.18 + 8/18.26 + 8/26.34 +...+ 8/802.810)

  = 1/4.(1/10 - 1/18 + 1/18 - 1/26 + 1/26 - 1/34 +...+ 1/802 - 1/810)

  = 1/4.(1/10 - 1/810)

  = 2/81

Vậy B= 2/81

Tk mình nha!!!

a,A=101/1018 b,B=2/81

\(\frac{n}{n}\)

\(A=\dfrac{2}{4.7}-\dfrac{3}{5.9}+\dfrac{2}{7.10}-\dfrac{3}{9.13}+...+\dfrac{2}{301.304}-\dfrac{3}{401.405}\)

\(A=\dfrac{2}{4.7}+\dfrac{2}{7.10}+\dfrac{2}{301.304}...-\left(\dfrac{3}{5.9}+\dfrac{3}{9.13}+...+\dfrac{3}{401.405}\right)\)

\(A=2\left(\dfrac{1}{4.7}+\dfrac{1}{7.10}+\dfrac{1}{301.304}\right)...-3\left(\dfrac{1}{5.9}+\dfrac{1}{9.13}+...+\dfrac{1}{401.405}\right)\)

\(A=2\left(\dfrac{1}{4}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{10}+\dfrac{1}{301}-\dfrac{1}{304}\right)...-3\left(\dfrac{1}{5}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{13}+...+\dfrac{1}{401}-\dfrac{1}{405}\right)\)

\(A=2\left(\dfrac{1}{4}-\dfrac{1}{304}\right)-3\left(\dfrac{1}{5}-\dfrac{1}{405}\right)\)

\(A=2\left(\dfrac{76}{304}-\dfrac{1}{304}\right)-3\left(\dfrac{81}{5}-\dfrac{1}{405}\right)\)

\(A=2.\dfrac{75}{304}-3.\dfrac{80}{405}=\dfrac{75}{152}-\dfrac{80}{135}=\dfrac{10125-12160}{152.135}=-\dfrac{2035}{152.135}=-\dfrac{407}{4104}\)