Tìm x :
a) (x+11)+(x+13)+(x+15)+....+(x+25)+(x+27)=189
b) (x+1)+(x+4)+(x+7)+....+(x+31)+(x+34)= 222
tìm x biết [x+1] + [x+4] +[x+7] + ........+[x+31]+[x +34] = 222
x = 1 nha bạn
Tìm x
[x+1]+[x+4]+[x+7]+...+[x+31]+[x+34]=222
ta có : (x + 1) + (x + 4) + (x + 7) +.........+ ( x + 31) + (x +34) =222.
(x + x +....+ x) + (1+ 4+ 7 + ...+ 31 + 34) =222
12x + 12.(1+34) :2 = 222
12x + 210 = 222 => 12x=12 => x =1
k mình nha!
1. 27/5 x 91/12 x 125/9 x 96/13
2. 2539/35 x 7/90 + 561/35 x 7/90
3. 31/7 : (2/5 x 31/7)
4. (29 x 15/23 x 36/29) : 5/23
5. 4/3 x 5/4 x 6/5 x ... x 12/11
6. 34/11 x 27/46 x 23/17 x 22/9
7. 4/3 x 9/8 x 16/15 x 25/24 x ... x 100/99
a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)
1. 27/5 x 91/12 x 125/9 x 96/13
2. 2539/35 x 7/90 + 561/35 x 7/90
3. 31/7 : (2/5 x 31/7)
4. (29 x 15/23 x 36/29) : 5/23
3)\(\dfrac{31}{7}\) : (\(\dfrac{2}{5}\times\dfrac{31}{7}\) )
=\(\dfrac{31}{7}\) : \(\dfrac{2}{5}\times\dfrac{31}{7}\)
= \(\dfrac{31}{7}:\dfrac{31}{7}\times\dfrac{2}{5}\)
= \(\dfrac{2}{5}\)
4) (\(29\times\dfrac{15}{23}\times\dfrac{31}{7}\)) : \(\dfrac{5}{23}\)
=\(29\times\dfrac{15}{23}\times\dfrac{31}{7}:\dfrac{5}{23}\)
= \(29\times\dfrac{31}{7}\times\dfrac{15}{23}:\dfrac{5}{23}\)
= 29 x \(\dfrac{31}{7}\times\dfrac{15}{23}\times\dfrac{23}{5}\)
= 29 x \(\dfrac{31}{7}\times3\)
= 29 x 3 x \(\dfrac{31}{7}\)
= 87 x \(\dfrac{31}{7}\)
= \(\dfrac{2697}{7}\)
Tìm chữ số tận cùng: 11 x 13 x 15 x 17 + 23 x 25 x 27 x 29 + 31 x 33 x 35 x 37 + 45 x 47 x 49 x 51
11 x 13 x 15 x 17 + 23 x 25 x 27 x 29 + 31 x 33 x 35 x 37 + 45 x 47 x 49 x 51
=7096860
#Hok tốt!#
tính giá trị các biểu thức:
1) A=7/10 x11 + 7/11 x 12 + 7/12 x 13 + ...... +7/69 x 70
2)B= 1/25 x 27 + 1/ 27 x 29 + 1/29 x 31 + ... + 1/ 73 x 75
3) C= 4/2 x4 +4/4 x 6 + 4/6 x 8 + ... + 4/ 2008 x 2010
1) \(A=\frac{7}{10\times11}+\frac{7}{11\times12}+\frac{7}{12\times13}+...+\frac{7}{69\times70}\)
\(A=7\times\left(\frac{1}{10\times11}+\frac{1}{11\times12}+\frac{1}{12\times13}+...+\frac{1}{69\times70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{69}-\frac{1}{70}\right)\)
\(A=7\times\left(\frac{1}{10}-\frac{1}{70}\right)\)
\(A=7\times\frac{3}{35}\)
\(A=\frac{3}{5}\)
2) \(B=\frac{1}{25\times27}+\frac{1}{27\times29}+\frac{1}{29\times31}+...+\frac{1}{73\times75}\)
\(B=\frac{1}{2}\times\left(\frac{2}{25\times27}+\frac{2}{27\times29}+\frac{2}{29\times31}+...+\frac{2}{73\times75}\right)\).
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{27}+\frac{1}{27}-\frac{1}{29}+\frac{1}{29}-\frac{1}{31}+...+\frac{1}{73}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\left(\frac{1}{25}-\frac{1}{75}\right)\)
\(B=\frac{1}{2}\times\frac{2}{75}\)
\(B=\frac{1}{75}\)
3) \(C=\frac{4}{2\times4}+\frac{4}{4\times6}+\frac{4}{6\times8}+...+\frac{4}{2008\times2010}\)
\(C=\frac{4}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{2008\times2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2008}-\frac{1}{2010}\right)\)
\(C=2\times\left(\frac{1}{2}-\frac{1}{2010}\right)\)
\(C=2\times\frac{502}{1005}\)
\(C=\frac{1004}{1005}\)
_Chúc bạn học tốt_
a) x - = b) . c)
) : e) f) .
x
x
d x x x x x
3 13 2 4 3 7 2
1 3
5 25 3 5 10 15 3
4 5 1 7 2 11 1 1
3 15 1 3
5 7 6 5 5 2 3 2
Tìm x, biết:
(x+1) + (x+4) + (x+7) + ... + (x+31) + (x+34) = 222
LÀM ƠN GIÚP MÌNH
Câu này dễ x = 1
Không biết thì đừng chat
Bài 1: Tìm x [GIÚPPPPPPPPPPPPPPPPPPP]
1) 5 – (10 – x) = 7
2) - 32 - (x – 5) = 0
3) -12 + (2x – 9) + x= 0
4) 11 + (15 - x) = 1
5) 4 - (27 - 3) = x - (13 - 4)
6) 8 - (x - 10) = 23 - (- 4 +12)
7) 105 – 5(10 – 5x) = -20
8) (x -1)(8-2x)(3x+123) = 0
9) (x2 - 25)(x+ 10) = 0
10) x(x2+5) = 0
\(1\)) \(5-\left(10-x\right)=7\)
\(10-x=5-7\)
\(10-x=-2\)
\(x=10-\left(-2\right)\)
\(x=12\)
\(2\)) \(-32-\left(x-5\right)=0\)
\(x-5=-32-0\)
\(x-5=-32\)
\(x=-32+5\)
\(x=-27\)
1)10-x=5-7
x=10-(-2)
x=12
2)x+5=0+32
x=32-5
x=27
3) -12+2x-9+x=0
-12+(2x+x-9)=0
3x-9=0+12
3x=12+9
x=21:3
x=7
4) 15-x=1-11
x=15-(-10)
x=25
5) 4-(27+3)=x-9
4-30=x-9
-26+9=x
x=-17
tìm x
< x+1>+<x+4>+<x+7>+ .....+<x+31> + < x+34>=222
Dãy số 1,4,7,..........,31,34 có số số hạng là:
( 34 - 1 ) : 3 + 1 = 12 ( số )
Tổng dãy số 1,4,7,..............,31,34 là:
( 34 + 1 ) x 12 : 2 = 210
Sau đó bạn tự làm tiếp nha
Ta có : (x + 1) + (x + 4) + ..... + (x + 34) = 222
<=> (x + x + ..... + x) + (1 + 4 + ..... + 34) = 222
<=> 12x + 210 = 222
=> 12x = 12
=> x = 1