Phân tích thành nhân tử
1, a^4+a^2+1
2,a^4+4b^4
3,64x^4+1
4, x^5+x^4+1
5, x^7+x^2+1
6, x^8+x+1
7, x^4-4x^2+4x-1
8, a^16+a^8b^8+b^16
Những câu hỏi liên quan
Phân tích thành nhân tử ( thêm bớt hạng tử)
1, a^4+a^2+1
2,a^4+4b^4
3,64x^4+1
4, x^5+x^4+1
5, x^7+x^2+1
6, x^8+x+1
7, x^4-4x^2+4x-1
8, a^16+a^8b^8+b^16
1, a4 + a2 + 1
= a4 + 2a2 + 1 - a2
= (a2)2 + 2a2 + 1 - a2
= (a2 + 1)2 - a2
= (a2 + 1 - a)(a2 + 1 + a)
2, a4 + 4b4
= (a2)2 + 2. a2 . b2 + (2b)2 - a2 . b2
= (a2 + 2b)2 - (ab)2
= (a2 + 2b - ab)(a2 + 2b + ab)
3, 64x4 + 1
= (8x2)2 + 16x2 + 1 - 16x2
= (8x2 + 1)2 - (4x)2
= (8x2 + 1 - 4x)(8x2 + 1 + 4x)
4, x5 + x4 + 1
= x5 + x4 + x3 - x3 - x2 - x + x + x2 + 1
= (x5 + x4 + x3) - (x3 + x2 + x) + (x + x2 + 1)
= x3(x2 + x + 1) - x(x2 + x + 1) + (x2 + x + 1)
= (x2 + x + 1)(x3 - x + 1)
5, x7 + x2 + 1
= x7 – x + x2 + x + 1
= x(x6 – 1) + (x2 + x + 1)
= x(x3 – 1)(x3 + 1) + (x2 + x + 1)
= x(x3 + 1)(x – 1) (x2 + x + 1) + (x2 + x + 1)
= (x2 + x + 1)[ x(x3 + 1)(x – 1) + 1]
= (x2 + x + 1)(x5 – x4 + x3 – x2 + x – 1)
6, x8 + x + 1
= x8 + x7 + x6 - x7 - x6 - x5 + x5 + x4 + x3 - x4 - x3 - x2 + x2 + x + 1
= (x8 + x7 + x6) - (x7 + x6 + x5) + (x5 + x4 + x3 ) - (x4 + x3 + x2) + (x2 + x + 1)
= x6(x2 + x + 1) - x5(x2 + x + 1) + x3(x2 + x + 1) - x2(x2 + x + 1) + (x2 + x + 1)
= (x2 + x + 1)(x6 - x5 + x3 - x2 + 1)
7, x4 - 4x2 + 4x - 1
= x4 - (4x2 - 4x + 1)
= (x2)2 - (2x - 1)2
= (x2 - 2x + 1)(x2 + 2x - 1)
= (x - 1)2 (x2 + 2x - 1)
8, a16 + a8b8 + b16
= (a16 + 2a8b8 + b16) - a8b8
= (a8 + b8)2 - (a4b4)2
= (a8 + b8 - a4b4)(a8 + b8 + a4b4)
= (a8 + b8 - a4b4)[(a8 + b8 + 2a4b4) - a4b4]
= (a8 + b8 - a4b4)[(a4 + b4)2 - (a2b2)2]
= (a8 + b8 - a4b4)(a4 + b4 - a2b2)(a4 + b4 + a2b2)
= (a8 + b8 - a4b4)(a4 + b4 - a2b2)[(a4 + b4 + 2a2b2) - a2b2]
= (a8 + b8 - a4b4)(a4 + b4 - a2b2)[(a2 + b2) - (ab)2]
= (a8 + b8 - a4b4)(a4 + b4 - a2b2)(a2 + b2 - ab)(a2 + b2 + ab)
a) 16 - 18/x| = -8 -14|x|
b) 5 x|+7.(2/x|-3) =4.(x-4)+25
e) 15-3|4x +2| = 3 8) 18 -4.(6-2|x|) = - 3.(4|x|+5)+29
8) 27-5/x -10 = 4|x-10| - 18
h) 510 + 3x|-21 = 7- 2|15+3x|
c) 43x +2|-16= 20
d) 8|x - 1|-4 = 12+6|x-1|
giúp em với
Phân tích đa thức thành nhân tử1) x^3 - 7x + 62) x^3 - 9x^2 + 6x + 163) x^3 - 6x^2 - x + 304) 2x^3 - x^2 + 5x + 35) 27x^3 - 27x^2 + 18x - 46) x^2 + 2xy + y^2 - x - y - 127) (x + 2)(x +3)(x + 4)(x + 5) - 248) 4x^4 - 32x^2 + 19) 3(x^4 + x^2 + 1) - (x^2 + x + 1)^210) 64x^4 + y^411) a^6 + a^4 + a^2b^2 + b^4 - b^612) x^3 + 3xy + y^3 - 113) 4x^4 + 4x^3 + 5x^2 + 2x + 114) x^8 + x + 115) x^8 + 3x^4 + 416) 3x^2 + 22xy + 11x + 37y + 7y^2 +1017) x^4 - 8x + 63 đúng nhiều nhất sẽ đc tick
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Phân tích đa thức thành nhân tử
1) x^3 - 7x + 6
2) x^3 - 9x^2 + 6x + 16
3) x^3 - 6x^2 - x + 30
4) 2x^3 - x^2 + 5x + 3
5) 27x^3 - 27x^2 + 18x - 4
6) x^2 + 2xy + y^2 - x - y - 12
7) (x + 2)(x +3)(x + 4)(x + 5) - 24
8) 4x^4 - 32x^2 + 1
9) 3(x^4 + x^2 + 1) - (x^2 + x + 1)^2
10) 64x^4 + y^4
11) a^6 + a^4 + a^2b^2 + b^4 - b^6
12) x^3 + 3xy + y^3 - 1
13) 4x^4 + 4x^3 + 5x^2 + 2x + 1
14) x^8 + x + 1
15) x^8 + 3x^4 + 4
16) 3x^2 + 22xy + 11x + 37y + 7y^2 +10
17) x^4 - 8x + 63
đúng nhiều nhất sẽ đc tick
Ta có : x3 - 7x + 6
= x3 - x - 6x + 6
= x(x2 - 1) - 6(x - 1)
= x(x + 1)(x - 1) - 6(x - 1)
= (x - 1) [x(x + 1) - 6]
= (x - 1) (x2 + x - 6) .
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x3 - 7x + 6
= x3 - x - 6x + 6
= x(x2 - 1) - 6(x - 1)
= x(x + 1)(x - 1) - 6(x - 1)
= (x - 1) [x(x + 1) - 6]
= (x - 1) (x2 + x - 6) .
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Phân tích các đa thức sau thành nhân tử.
1) a^2+ab+2b-4 2) x^3-x 3) x^2-6x+8 4) ab+b^2-3a-3b 5) x^3-4x^2-8x+8
6)9x^2+6x-8 7)x^2-y^2-4x+4 8)5x^3-10x^2+5x 9) 3x^2-8x+4 10) 4x^2-4x-3
11) x^2-7x+12 12)x^2-5x-14 13) 3x^2-7x+2 14) a.(x^2+1)-x.(a^2-1) 15) x^4+4
16) (x+2).(x+3).(x+4).(x+5)-24 17) (a+1).(a+3).(a+5).(a+7...
Đọc tiếp
Phân tích các đa thức sau thành nhân tử.
1) a^2+ab+2b-4 2) x^3-x 3) x^2-6x+8 4) ab+b^2-3a-3b 5) x^3-4x^2-8x+8
6)9x^2+6x-8 7)x^2-y^2-4x+4 8)5x^3-10x^2+5x 9) 3x^2-8x+4 10) 4x^2-4x-3
11) x^2-7x+12 12)x^2-5x-14 13) 3x^2-7x+2 14) a.(x^2+1)-x.(a^2-1) 15) x^4+4
16) (x+2).(x+3).(x+4).(x+5)-24 17) (a+1).(a+3).(a+5).(a+7)+15
tìm x,bt:
a,16-18/x/=-8-14/x/
b,5./x/+7.(2/x/-3)=4.(/x/-4)+25
c,4/3x+2/-16=20
d,8/x-1/-4=12+6/x-1/
e,15-3/4x+2/=3
i,18-4.(6-2/x/)=3.(4/x/+5+29
g,27-5/x-10/=4/x-10/-18
h,5/10+3x/-21-7-2/15+3x/
mn ơi,giúp mk với T^T
Tìm x biết:
a) 4(18-5x) - 12(3x-7) = 15(2x-16) - 6(x+14)
b) 5(3x+5) - 4(2x-3) = 5x+3(2x+12)+1
c)2(5x-8) - 3(4x-5) = 4(3x-4) + 11
d) 5x-3 {4x-2 [4x-3(5x-2)]}=182
3,26 + 4/5 =?
làm nhanh lên giúp mình nhé
3,26+4/5=3,26+0,8=3,34
K cho mình cái
\(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x+16+11\)
\(\Leftrightarrow-2x-1=12x+27\Leftrightarrow-14x-28=0\Leftrightarrow x=-2\)
Phân tích đa thức thành nhân tử :
a) x^2 -x-12
b) 4x^4 + 4x^2y^2 - 8y^4
c) x^2 + 7x + 12
d) x^2 +6x + 8
e) x^2 - 10x +16
f) x^2 -8x + 15
g) x^4 + 4
h) 4x^8 +1
i) x^2 - 8x -9
k) x^2 + 14x +48
\(x^2-x-12\)
\(=x^2+3x-4x-12\)
\(=x\left(x+3\right)-4\left(x+3\right)\)
\(=\left(x+3\right)\left(x-4\right)\)
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Phân tích thành nhân tử :
1 . x ( 2x - 7 ) - 4x - 14
2 . x^2 + ( a + b ) xy - aby^2
3 . a^2 ( b - c ) + b^2 ( c - a ) + c^2 ( a - b )
4 . 15 x^4 - 10 x^2 y^2 + y^2
5 . x^4 + 4
6 . 64 x^4 + 1
7 . 81 x^4 + 1
8 . -16 a^4 b^6 - 24 a^5 b^5 - 9 a^6 b^4
* GIÚP TỚ VỚI . ĐƯỢC CÂU NÀO HAY CÂU ẤY <.> TỚ ĐANG CẦN GẤP
Tìm x:
a) 4(18 - 5x) - 12(3x - 7) = 15(2x - 16) - 6(x + 14)
b) 5(3x + 5) - 4(2x - 3) = 5x + 3(2x + 12) + 1
c) 2(5x - 8) - 3(4x - 5) = 4(3x - 4) +11
d) 5x - 3{4x - 2[4x - 3(5x - 2)]} = 182
a, \(4\left(18-5x\right)-12\left(3x-7\right)=15\left(2x-16\right)-6\left(x+14\right)\)
\(\Leftrightarrow72-20x-36x+84=30x-240-6x-84\)
\(\Leftrightarrow156-56x=24x-324\)
\(\Leftrightarrow-80x+480=0\Leftrightarrow x=-6\)
b, \(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x-12\right)+1\)
\(\Leftrightarrow15x+25-8x+12=5x+6x-36+1\)
\(\Leftrightarrow7x+37=11x-35\)
\(\Leftrightarrow-4x+72=0\Leftrightarrow x=18\)
c, \(2\left(5x-8\right)-3\left(4x-5\right)=4\left(3x-4\right)+11\)
\(\Leftrightarrow10x-16-12x+15=12x-16+11\)
\(\Leftrightarrow-2x-1=12x-5\)
\(\Leftrightarrow-14x+4=0\Leftrightarrow x=\frac{2}{7}\)
d, \(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}=182\)
\(\Leftrightarrow5x-3\left[4x-15x+6\right]=182\)
\(\Leftrightarrow5x-3\left(-11x+6\right)=182\)
\(\Leftrightarrow5x+33x-18-182=0\)
\(\Leftrightarrow38x-200=0\Leftrightarrow x=\frac{100}{19}\)
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