\(7^{2x}+7^{2x+2}=2450\)

\(\Rightarrow7^{2x}\left(1+7^2\right)=2450\)

\(\Rightarrow7^{2x}\cdot50=2450\)

\(\Rightarrow7^{2x}=49=7^2\)

\(\Rightarrow2x=2\Rightarrow x=1\)

7^2x(1+ 49) = 2450

7^2x = 2450/50 = 49 = 7²

2x = 2

x = 1

không có x vì 7²⁺7²⁺²⁼2450

7^2x + 7^2x+2= 2450

1.7^2x + 7^2x+7²=2450

7^2x.(1+7²)=2450

7^2x.(1+49)=2450

7^2x.50 = 2450

7^2x=2450:50

7^2x=49

49=7²

2x=2

x=2:2

x=1

\(7^{2x}+7^{2x+2}=2450\)

\(\Rightarrow7^{2x}+7^{2x}\times7^2=2450\)

\(\Rightarrow7^{2x}\times\left(1+7^2\right)=2450\)

\(\Rightarrow7^{2x}\times50=2450\)

\(\Rightarrow7^{2x}=49\)

\(\Rightarrow7^{2x}=7^2\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=2:2\)

\(\Rightarrow x=1\)

Vậy x = 1

_Chúc bạn học tốt_

7^2x + 7^2x+2 = 2450
1.7^2x + 7^2x.7² = 2450
7^2x.(1+7²) = 2450
7^2x.(1+49) = 2450
7^2x.50       = 2450
7^2x            = 2450 : 50
7^2x            = 49
7^2x            = 7²
  2x           = 2
    x           = ... (Tự tính)
Vậy x = ...
 

\(7^{2x}+7^{2x+2}=2450\)

\(1\times7^{2x}+7^{2x}\times7^2=2450\)

\(7^{2x}\left(1+7^2\right)=2450\)

\(\frac{7^{2x}\left(1+7^2\right)}{1+7^2}=\frac{2450}{1+7^2}\)

\(7^{2x}=\frac{2450}{1+49}\)

\(7^{2x}=\frac{2450}{50}\)

\(7^{2x}=49\)

\(7^{2x}=7^2\)

\(2x=2\)

\(x=2\div2\)

\(x=1\)

Học tốt nha.

\(7^{2x}+7^{2x+2}=2450\)

\(7^{2x}+7^{2x}\cdot7^2=2450\)

\(7^{2x}\cdot\left(1+49\right)=2450\)

\(7^{2x}=2450:50=49\)

\(7^{2x}=7^2\)

\(2x=2\)

\(x=1\)

TL:

 \(x=1\)

*Hok tốt

\(7^{2x}+7^{2x+2}=2450\)

\(7^{2x}+7^{2x}.7^2=2450\)

\(7^{2x}.\left(1+49\right)=2450\)

\(7^{2x}.50=2450\)

\(7^{2x}=2450:50\)

\(7^{2x}=49\)

\(7^{2x}=7^2\)

\(2x=2\)

\(x=1\)

\(7^{2x}+7^{2x+2}=2450\)

\(7^{2x}.1+7^{2x}.7^2=2450\)

\(7^{2x}.\left(1+7^2\right)=2450\)

\(7^{2x}.\left(1+49\right)=2450\)

\(7^{2x}.50=2450\)

\(7^{2x}=2450:50\)

\(7^{2x}=49\)

\(7^{2x}=7^2\)

\(\Rightarrow2x=2\)

\(x=2:2\)

\(x=1\)

Vậy \(x=1\)

\(7^{2x}+7^{2x+2}=2450\)

\(\Leftrightarrow7^{2x}+7^{2x}.7^2=2450\)

\(\Leftrightarrow7^{2x}.\left(1+7^2\right)=2450\)

\(\Leftrightarrow7^{2x}.50=2450\)

\(\Leftrightarrow7^{2x}=2450:50\Leftrightarrow7^{2x}=49\)

\(\Leftrightarrow7^{2x}=7^2\Leftrightarrow2x=2\)

\(\Leftrightarrow x=1\)

Theo bài ra ta có

\(7^{2x}\)+\(7^{2x+2}\)=2450

<=>\(7^{2x}\)+\(7^{2x}\).\(7^2\)=2450

<=>\(7^{2x}\)(1+49)=2450

<=>\(7^{2x}\).50=2450

<=>\(7^{2x}\)=49=\(7^2\)

<=>2x=2

<=>x=1

Vậy x=1

a) \(\left(2x+1\right)\left(x-\frac{1}{7}\right)=0\Leftrightarrow\orbr{\begin{cases}2x+1=0\\x-\frac{1}{7}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=-\frac{1}{2}\\x=\frac{1}{7}\end{cases}}.\)

Vậy.....

b) \(7^{2x}+7^{2x+2}=2450\Leftrightarrow7^{2x}\left(1+7^2\right)=2450\Leftrightarrow7^{2x}\cdot50=2450\Leftrightarrow7^{2x}=49\Leftrightarrow2x=2\Leftrightarrow x=1.\)

Vậy....

Học tốt nhé ^3^

a) 2^x+2^x+3=144

2^x . 1 + 2^x . 2³ = 144

2^x . ( 1 + 2³ ) = 144

2^x . 9 = 144

2^x = 144 : 9

2^x = 16

2^x = 2⁴

=> x = 4

b) 7^2x + 7^2x+2 = 2450

7^2x . 1 + 7^2x . 7²= 2450

7^2x . ( 1 + 7² ) = 2450

7^2x . 50 = 2450

7^2x = 2450 : 50

7^2x = 49

7^2x = 7²

=> 2x = 2

=> x = 1

Ta có : 2^x + 2^{x + 3} = 144

=> 2^x (1 + 2³) = 144

=> 2^x . 9 = 144

=> 2^x = 144 : 9

=> 2^x = 16

=> 2^x = 2⁴

=> x = 4 

a) =4

b)1