Tìm x: 2016 - 3 . ( x - 6 ) = 1446
Tìm x:
a) 2 . x^3 - 2 = 52
b) 2016 - 3 . ( x - 6 ) = 1446
Xin các bạn, hãy giúp mình với!!! T_T
a) 2 . x^3 - 2 = 52
=> 2 . x^3 = 52 + 2
=> 2 . x^3 = 54
=> x^3 = 54 :2
=> x^3 = 27
=> x =3
b) 2016 - 3 . ( x - 6 ) = 1446
\(\text{a)}2.x^3-2=52\)
\(\Rightarrow2.x^3=52+2\)
\(\Rightarrow2.x^3=54\)
\(\Rightarrow x=3\)
\(\text{b)2016-3.(x-6)=1446}\)
\(\Rightarrow3.x-6=2016-1446\)
\(\Rightarrow3.x-6=570\)
\(\Rightarrow x-6=570:3\)
\(\Rightarrow x-6=190\)
\(\Rightarrow x=190+6\)
\(\Rightarrow x=196\)
Vậy x= 196
Câu1: tìm số nguyên x mà -35/6<x>-18/5
Câu2 : so sánh A=2015/2016+2016/2017 và B= 2015+2016/2016+2017
Câu3 : tìm số nguyên x biết rằng : 1/3+1/6+1/10...+2/x(x+1) =2007/2009
câu 1. tìm x nguyên để \(\frac{-35}{6}\)<x<\(\frac{-18}{5}\)
<=> -4,375<x<-3,6
mà x\(\in\)Z nên x={-4}
câu 2. A=\(\frac{2015}{2016}\)+\(\frac{2016}{2017}\)
B=\(\frac{2015+2016}{2016+2017}\)=\(\frac{2015}{2016+2017}\)+\(\frac{2016}{2016+2017}\)
Vì \(\frac{2015}{2016+2017}\)<\(\frac{2015}{2016}\); \(\frac{2016}{2016+2017}\)<\(\frac{2016}{2017}\)
Vậy B<A
cau3:
\(\frac{1}{3}\)+\(\frac{1}{6}\)+\(\frac{1}{10}\)+.....+\(\frac{2}{x\left(x+1\right)}\)=\(\frac{2007}{2009}\)
2.(\(\frac{1}{6}\)+\(\frac{1}{12}\)+\(\frac{1}{20}\)+.....+\(\frac{1}{x\left(x+1\right)}\))=\(\frac{2007}{2009}\)
2.(\(\frac{1}{2.3}\)+\(\frac{1}{3.4}\)+\(\frac{1}{4.5}\)+.....+\(\frac{1}{x\left(x+1\right)}\))=\(\frac{2007}{2009}\)
2.(\(\frac{1}{2}\)-\(\frac{1}{3}\)+\(\frac{1}{3}\)-\(\frac{1}{4}\)+\(\frac{1}{4}\)-\(\frac{1}{5}\)+.....+\(\frac{1}{x}\)-\(\frac{1}{x+1}\))=\(\frac{2007}{2009}\)
2.(\(\frac{1}{2}\)-\(\frac{1}{x+1}\))=\(\frac{2007}{2009}\)
\(\frac{1}{2}\)-\(\frac{1}{x+1}\)=\(\frac{2007}{4018}\)
\(\frac{1}{x+1}\)=\(\frac{1}{2}\)-\(\frac{2007}{4018}\)
\(\frac{1}{x+1}\)=\(\frac{1}{2009}\)
x+1=2009
x=2009-1
x=2008
Tìm x biet x*(6-x)^2016=(x-6)^2016
tìm x : (2015+1 phần 2015 - 2016+ 1 phần 2016)= 1 phần 3 + 1 phần 6 - 1 phần 2
Xin nỗi mik ghi nhầm ko phải tìm x đâu :(
tìm x,y biết :
a, 3 - 2x = 3.(5-x) + 4
b, 4 - ( 7x + 2017 ) = 6 . ( 5-x) - 2017
c, 15 - x (x+1) = 4 - x^2 + 2x
d, -4.(x-5) + 2016 = 3.(8-x)-(2x - 2016)
a, 3 - 2x = 3 . (5 - x) + 4
3 - 2x = 15 - 3x + 4
-2x + 3x = 15 + 4 - 3
x = 16
b, 4 - (7x + 2017) = 6 . (5 - x) - 2017
4 - 7x - 2017 = 30 - 6x - 2017
-7x + 6x = 30 - 2017 - 4 + 2017
-x = 26
x = -26
c, 15 - x . (x + 1) = 4 - x^2 + 2x
15 - x^2 - x = 4 - x^2 + 2x
-x^2 - x + x^2 - 2x = 4 - 15
-3x = -11
x = 11/3
d, -4 . (x - 5) + 2016 = 3 . (8 - x) - (2x - 2016)
-4x + 20 + 2016 = 24 - 3x - 2x + 2016
-4x + 3x +2x = 24 + 2016 - 20 - 2016
x = 4
đúng 100%
tìm số tự nhiên x,biết:1/3+1/6+...+1/x*(x+1)/2=2016/2018
cái đề j mk khó hỉu vậy viết đòang hoàng xem nào
Tìm số tự nhiên x biết
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{1}{x\cdot\left(x+1\right):2}=\frac{2016}{2018}\)
tìm x biết
1/3 + 1/6 + 1/10 + .....+ 1/x{x+1} = 2014 /2016
1/3 + 1/6 + 1/10 + 2/x.(x + 1) = 2014/2016
Tìm số tự nhiên x
Tính 2016 * 105 - 2016 * 4 - 2016=
Tìm x biết : x * 24 + x * 6 = 240
Tìm x biết : x -167 * 15 = 167 * 185
Tính 173* 105 + 173 * 96 - 173 =
\(2016\times105-2016\times4-2016\)
\(=2016\times\left(105-4-1\right)\)
\(=2016\times100\)
\(=201600\)
\(x\times24+x\times6=240\)
\(x\times\left(24+6\right)=240\)
\(x\times30=240\)
\(x=240:30\)
\(x=8\)
\(x-167\times15=167\times185\)
\(x-2505=30895\)
\(x=30895+2505\)
\(x=33400\)
\(173\times105+173\times96-173\)
\(=173\times\left(105+96-1\right)\)
\(=173\times200\)
\(=34600\)
1. 2016 x 105 - 2016 x 4 - 2016
= 211680 - 8064 - 2016
= 203616 - 2016
= 201600
2. X x 24 + X x 6 = 240
X x (24 + 6) = 240
X x 30 = 240
X = 240 : 30
X = 8
3. X - 167 x 15 = 167 x 185
X - 2505 = 30895
X = 30895 - 2505
X = 28390
4. 173 x 105 + 173 x 96 - 173
= 18165 + 16608 - 173
= 34773 - 173
= 34600