(x-8).2=24
105-5.(x+1)=70
20-|x|=18
7020 x 17-7020x3-7020-4
7020 x 17 - 7020 x 3 - 7020 - 4
= 7020 x 17 - 7020 x 3 - 7020 x 1 - 4
= 7020 x ( 17 - 3 - 1 ) - 4
= 7020 x 13 - 4
= 91260 - 4
= 91256
X x 3 + x x 6 = 7020
X * 3 + x * 6 = 7020
X *(3 + 6 ) = 7020
X * 9 = 7020
X = 7020 : 9
X = 780
X x ( 3 + 6 ) = 7020
X x 9 = 7020
X = 7020 : 9
X = 780
X x 3 + x x 6 = 7020
X x ( 3+ 6 ) = 7020
X x 9 = 7020
X = 7020 : 9
X = 780
Hok tốt
# HarryNguyen #
6/x-5+2/x-8=18/(x-5)(8-x)-1
Bài 1: ( 45316 x 27 - 24105 ) : 45316 x 26 + 21211
Bài 2: tìm 2 số có tích bằng 3250, biết rằng nếu ta tăng thừa số thứ 2 thêm 7 đon vị và giữ nguyên thừa số thứ 1 thì đc tích mới là 4125
Giải pt 6/x-5+x+2/x-8=18/(x-5)(8-x)-1
\(ĐKXĐ:x\ne5,8\)
\(\frac{6}{x-5}+\frac{x+2}{x-8}=\frac{18}{\left(x-5\right)\left(8-x\right)}-1\)
\(\Rightarrow\frac{6}{x-5}+\frac{x+2}{x-8}=-\frac{18}{\left(x-5\right)\left(x-8\right)}-1\)
\(\Rightarrow6\left(x-8\right)+\left(x+2\right)\left(x-5\right)=-18-\left(x-5\right)\left(x-8\right)\)
\(\Rightarrow x^2+3x-58=-x^2+13x-58\)
\(\Rightarrow2x^2-10x=0\)
\(\Rightarrow2x\left(x-5\right)=0\)
\(\Rightarrow x\in\left\{0,5\right\}\)
a) 16 - 18/x| = -8 -14|x|
b) 5 x|+7.(2/x|-3) =4.(x-4)+25
e) 15-3|4x +2| = 3 8) 18 -4.(6-2|x|) = - 3.(4|x|+5)+29
8) 27-5/x -10 = 4|x-10| - 18
h) 510 + 3x|-21 = 7- 2|15+3x|
c) 43x +2|-16= 20
d) 8|x - 1|-4 = 12+6|x-1|
giúp em với
Bài 3: Rút gọn biểu thức (Dùng hằng đẳng thức)
1, (x+y)\(^2\)-(x-y)\(^2\)
2, (x+y)\(^3\)-(x-y)\(^3\)-2y\(^3\)
3,(x+y)\(^2\)-2(x+y)(x-y)+(x-y)\(^2\)
4,(2x+3)\(^2\)-2(2x+3)(2x+5)+(2x+5)\(^2\)
5, 9\(^8\). 2\(^8\)-(18\(^4\)+1)(18\(^4\)-1)
\(1,\left(x+y\right)^2-\left(x-y\right)^2=\left[\left(x+y\right)-\left(x-y\right)\right]\left[\left(x+y\right)+\left(x-y\right)\right]=\left(x+y-x+y\right)\left(x+y+x-y\right)=2y.2x=4xy\)
\(2,\left(x+y\right)^3-\left(x-y\right)^3-2y^3\)
\(=x^3+3x^2y+3xy^2+y^3-x^3+3x^2y-3xy^2+y^3-2y^3\)
\(=6x^2y\)
\(3,\left(x+y\right)^2-2\left(x+y\right)\left(x-y\right)+\left(x-y\right)^2\\ =\left[\left(x+y\right)-\left(x-y\right)\right]^2\\ =\left(x+y-x+y\right)^2\\ =4y^2\)
\(4,\left(2x+3\right)^2-2\left(2x+3\right)\left(2x+5\right)+\left(2x+5\right)^2\\ =\left[\left(2x+3\right)-\left(2x+5\right)\right]^2\\ =\left(2x+3-2x-5\right)^2\\ =\left(-2\right)^2\\ =4\)
\(5,9^8.2^8-\left(18^4+1\right)\left(18^4-1\right)\\ =18^8-\left[\left(18^4\right)^2-1\right]\\ =18^8-18^8+1\\ =1\)
1: =x^2+2xy+y^2-x^2+2xy-y^2=4xy
2: =x^3+3x^2y+3xy^2+y^3-x^3+3x^2y-3xy^2+y^3-2y^3
=6x^2y
3: =(x+y-x+y)^2=(2y)^2=4y^2
4: =(2x+3-2x-5)^2=(-2)^2=4
5: =18^8-18^8+1=1
tìm x biết
1) x=-1/2 + 3/4 2) x - 1/5 = 2/11 3) x - 5/6 = 16/42 + -8/56
4) x/5 = 5/6 + -19/30 5) |x| - 1/4 = 6/18 6)x = -1/2 +3/4
7) x/15 = 3/5 + -2/3 8)11/8 + 13/6 = 85/x 9) x - 7/8 = 13/12
10) x - -6/15 = 4/27 11) -\(\dfrac{-6}{12}\)+ x = 9/48 12) x - 4/6 = 5/25 + -7/15
1: x=3/4-1/2=3/4-2/4=1/4
2: x-1/5=2/11
=>x=2/11+1/5=21/55
3: x-5/6=16/42-8/56
=>x-5/6=8/21-4/28=5/21
=>x=5/21+5/6=15/14
4: x/5=5/6-19/30
=>x/5=25/30-19/30=6/30=1/5
=>x=1
5: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
6: x=-1/2+3/4
=>x=3/4-1/2=1/4
11: x-(-6/12)=9/48
=>x+1/2=3/16
=>x=3/16-1/2=-5/16
1)x= 1/4
2)x= 2/11+ 1/5
x= 21/55
3)x - 5/6 = 5/21
x = 5/21+5/6
x = 15/14
4)x/5 = 5/6 + -19/30
x:5 = 1/5
x = 1/5.5
x = 1
5) |x| - 1/4 = 6/18
|x| = 6/18 - 1/4
|x| =7/12
⇒x= 7/12 hoặc -7/12
6)x = -1/2 +3/4
x= 1/4
7) x/15 = 3/5 + -2/3
x:15 = -1/15
x = -1/15. 15
x = -1
8)11/8 + 13/6 = 85/x
85/24 = 85/x
⇒ x = 24
9) x - 7/8 = 13/12
x = 13/12 + 7/8
x = 47/24
10)x - -6/15 = 4/27
x = 4/27 + (-6/15)
x = -34/135
11) -(-6/12)+x = 9/48
x= 9/48 - 6/12
x = -5/16
12) x - 4/6 = 5/25 + -7/15
x -4/6 = -4/15
x = -4/15 + 4/6
x = 2/5
Bài 8. Tìm số nguyên x
1) x – 12 = (-8) + (-17) 2) (7 – x) – 5 = - 13 3) 7 – 3x = 28 4) 2(x + 1) + 18 = - 4 | 5) 37 – x = 12 6) x + 5 = -18 7) 27 – (x + 1) = 2. (52 – 24) 8) (x – 3)(x + 3) = 0
|
1) x-12=(-8)+(-17)
x-12=(-25)
x = (-25)+12
x = (-13)
\(\dfrac{6}{x-5}+\dfrac{2}{x-8}=\dfrac{18}{\left(x-5\right)\left(8-x\right)}-1\)
Ta có: \(\dfrac{6}{x-5}+\dfrac{2}{x-8}=\dfrac{18}{\left(x-5\right)\left(8-x\right)}-1\)
\(\Leftrightarrow6x-48+2x-10=-18-\left(x-5\right)\left(x-8\right)\)
\(\Leftrightarrow8x-58+18+x^2-13x+40=0\)
\(\Leftrightarrow x^2-5x=0\)
\(\Leftrightarrow x\left(x-5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(nhận\right)\\x=5\left(loại\right)\end{matrix}\right.\)