\(=\frac{\left(2^{20}-1^{20}+3^{20}\right)\cdot2^{20}}{\left(2^{20}-1^{20}+3^{20}\right)\cdot3^{20}}\left(\text{Mình làm hơi tắt, xin bạn thông cảm}\right)\)

\(=\frac{2^{20}}{3^{20}}=\left(\frac{2}{3}\right)^{20}\)

Uk mk nhận nha

\(\frac{4^{20}-2^{20}-6^{20}}{6^{20}-3^{20}-9^{20}}=\frac{2^{20}.2^{20}-2^{20}-2^{20}.3^{20}}{3^{20}.2^{20}-3^{20}-3^{20}.3^{20}}\)

\(=\frac{2^{20}\left(2^{20}-1-3^{20}\right)}{3^{20}\left(2^{20}-1-3^{20}\right)}=\frac{2^{20}}{3^{20}}\)

\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)=\(\frac{2^{40}-2^{20}+2^{20}.3^{20}}{3^{20}.2^{20}-3^{20}+3^{40}}\)=\(\frac{2^{20}.\left(2^{20}-1+3^{20}\right)}{3^{20}.\left(2^{20}-1+3^{20}\right)}\)=\(\frac{2^{20}}{3^{20}}\)

Nhớ k nhá

\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}=\frac{\left(2^2\right)^{20}-2^{20}+\left(3.2\right)^{20}}{\left(3.2\right)^{20}-3^{20}+\left(3^2\right)^{20}}=\frac{2^{20}.2^{20}-2^{20}.1+3^{20}.2^{20}}{3^{20}.2^{20}-3^{20}.1+3^{20}.3^{20}}=\frac{2^{20}.\left(2^{20}-1+3^{20}\right)}{3^{20}.\left(2^{20}-1+3^{20}\right)}=\frac{2^{20}}{3^{20}}=\left(\frac{2}{3}\right)^{20}=\frac{40}{60}=\frac{2}{3}\)

trả lời hộ mình nha

Tính:

\(\frac{4^{20}-2^{20}+6^{20}}{6^{20}-3^{20}+9^{20}}\)

\(=\frac{\left(2.2\right)^{20}-2^{20}+\left(2.3\right)^{20}}{\left(3.2\right)^{20}-3^{20}+\left(3.3\right)^{20}}\)

\(=\frac{2^{20}.2^{20}-2^{20}+2^{20}.3^{20}}{3^{20}.2^{20}-3^{20}+3^{20}.3^{20}}\)

\(=\frac{2^{20}.2^{20}-2^{20}.1+2^{20}.3^{20}}{3^{20}.2^{20}-3^{20}.1+3^{20}.3^{20}}\)

\(=\frac{2^{20}.\left(2^{20}-1+3^{20}\right)}{3^{20}.\left(2^{20}-1+3^{20}\right)}\)

\(=\frac{2^{20}}{3^{20}}\)

\(=\left(\frac{2}{3}\right)^{20}.\)

Chúc bạn học tốt!