\(-x-\frac{9}{2004}=-\frac{1}{2003}\)

\(\Rightarrow-x=\frac{-1}{2003}+\frac{9}{2004}\)

\(\Rightarrow-x=\frac{-1}{2003}+\frac{9}{2004}\)

\(\frac{5}{9}-x=1-2004\)

\(\Rightarrow\frac{5}{9}-x=-2003\)

\(\Rightarrow x=\frac{5}{9}-\left(-2003\right)\)

\(\Rightarrow x=\frac{18032}{9}\)

a )

\(-x-\frac{9}{2004}=-\frac{1}{2003}\)

\(-x=-\frac{1}{2003}+\frac{9}{2004}\)

Số lớn quá 

b ) \(\frac{5}{9}-x=\frac{1}{2004}\)

\(x=\frac{5}{9}-\frac{1}{2004}\)

\(x=\frac{3337}{6012}\)

a) \(A=\left(1-\dfrac{1}{2}\right).\left(1-\dfrac{1}{3}\right).\left(1-\dfrac{1}{4}\right).\left(1-\dfrac{1}{5}\right)...\left(1-\dfrac{1}{2003}\right).\left(1-\dfrac{1}{2004}\right)\)

\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}...\dfrac{2002}{2003}.\dfrac{2003}{2004}\)

\(=\dfrac{1}{2004}\)

b) \(B=5\dfrac{9}{10}:\dfrac{3}{2}-\left(2\dfrac{1}{3}.4\dfrac{1}{2}-2.2\dfrac{1}{3}\right):\dfrac{7}{4}\)

\(=\dfrac{59}{10}:\dfrac{3}{2}-\left(\dfrac{7}{3}.\dfrac{9}{2}-2.\dfrac{7}{3}\right).\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\left(\dfrac{21}{2}-\dfrac{14}{3}\right).\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\dfrac{35}{6}.\dfrac{4}{7}\)

\(=\dfrac{59}{15}-\dfrac{10}{3}\)

\(=\dfrac{3}{5}\)

ai trả lời đúng thì mình sẽ tick cho

Giúp mình nhanh nha! Mình sẽ thick người đó