a) Vì \(-45< -16\) nên \(\left(-\dfrac{45}{17}\right)^{15}< \left(\dfrac{-16}{17}\right)^{15}\)

b) Vì \(21< 23\) nên \(\left(-\dfrac{8}{9}\right)^{21}< \left(-\dfrac{8}{9}\right)^{23}\)

c) \(27^{40}=3^{3^{40}}=3^{120}\)

\(64^{60}=8^{2^{60}}=8^{120}\)

Vì \(3< 8\) nên \(3^{120}< 8^{120}\) hay \(27^{40}< 64^{60}\)

con ai kooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

co don quaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

c 1 :64¹⁵⁰=(4³)¹⁵⁰=4⁴⁵⁰

4⁴⁵⁰>4³⁰⁰

=>64^150>4³⁰⁰

c 2 :4³⁰⁰=(4³)¹⁰⁰=64¹⁰⁰

64^100<64¹⁵⁰

^=>4^300<64¹⁵⁰

k cho mình nha!

Ta có : \(64^{150}\) (1)

\(4^{300}\) = \(\left(4^2\right)^{150}\) = \(16^{150}\) (2)

Từ (1) và ( 2 ) => 64 > 16 => \(64^{150}\) > \(16^{150}\)

Hay \(64^{150}\) > \(4^{300}\)

Tk mk nha

=(64-4)mũ 150 + 300

=60 mũ 450

a/ 26176

b/ 8

c/472392

d/ Ko tính dc

Thấy mình đẳng cấp ko

Cho mình 10 k nhé

clgt???

Đặt B =\(32^{17}.8^{19}\)

So sánh :\(A=64^{11}.16^{11}\)và  \(B=32^{17}.8^{19}\)

TA có :\(A=64^{11}.16^{11}=\left(64.16\right)^{11}=1024^{11}=\left(2^{10}\right)^{11}\)\(=2^{110}\)

            \(B=32^{17}.8^{19}=\left(2^5\right)^{17}.\left(2^3\right)^{19}=2^{85}.2^{57}\)\(=2^{142}\)

 VÌ  A < B ( 2¹¹⁰< 2¹⁴²)

 Nên A < 32¹⁷.8¹⁹

chỉ cần lấy máy tính thôi nhé

\(105-\left[\left(2x+7\right)-13\right]=\left(-15\right)^{10}:\left(9^5.5^8\right)\\ 105-\left[\left(2x+7\right)-13\right]=25\\ \left(2x+7\right)-13=105-25\\ \left(2x+7\right)-13=80\\ 2x+7=80+13\\ 2x+7=93\\ 2x=93-7\\ 2x=86\\ x=\dfrac{86}{2}\\ x=43\)

\(105-\left[\left(2x+7\right)-13\right]=\left(-15\right)^{10}:\left(9^5.5^8\right)\\ 105-\left[\left(2x+7\right)-13\right]=15^{10}:3^{10}:5^8\\ 105-\left[\left(2x+7\right)-13\right]=5^{10}:5^8\\ 105-\left[\left(2x+7\right)-13\right]=25\\ \left(2x+7\right)-13=105-25\\ \left(2x+7\right)-13=80\\ 2x+7=80+13\\ 2x+7=93\\ 2x=93-7\\ 2x=86\\ x=86:2\\ x=43\)

a, \(2^{15}=\left(2^3\right)^5=8^5\)

Vì \(8^5< 27^5\Rightarrow2^{15}< 27^5\)

b, \(4^8=\left(2^2\right)^8=2^{16}\)

\(8^6=\left(2^3\right)^6=2^{18}\)

Vì \(2^{16}< 2^{18}\Rightarrow4^8< 8^6\)

c, \(25^6=\left(5^2\right)^6=5^{12}\)

\(125^5=\left(5^3\right)^5=5^{15}\)

Vì \(5^{12}< 5^{15}\Rightarrow25^6< 125^5\)