làm 1 bài mẫu nha

a) \(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{25}{6}\)

\(\Rightarrow\frac{1}{3}x=\frac{25}{9}\)

\(\Rightarrow x=\frac{25}{9}:\frac{1}{3}\)

\(\Rightarrow x=\frac{25}{3}\)

các bài sau dễ lắm

a) \(\left(\frac{1}{3}x\right):\frac{2}{3}=1\frac{2}{3}:\frac{2}{5}\)

\(\Rightarrow\frac{1}{3}x:\frac{2}{3}=\frac{25}{6}\)

\(\Rightarrow\frac{1}{3}x=\frac{5}{3}\)

\(\Rightarrow x=\frac{5}{3}:\frac{1}{3}\)

\(\Rightarrow x=5\)

a) \(\left(\frac{1}{3}\cdot x\right):\frac{2}{3}=1\frac{2}{3}:\frac{2}{5}\)

\(\left(\frac{1}{3}\cdot x\right):\frac{2}{3}=\frac{25}{6}\)

\(\frac{1}{3}x=\frac{25}{6}\cdot\frac{2}{3}\)

\(\frac{1}{3}x=\frac{25}{9}\)

\(x=\frac{25}{9}:\frac{1}{3}\)

\(x=\frac{25}{3}\)

b) \(4,5:0,3=2,25:\left(0,1x\right)\)

\(15=2,25:\left(0,1x\right)\)

\(2,25:15=0,1x\)

\(0,15=0,1x\)

\(0,15:0,1=x\)

\(1,5=x\)

c) \(8:\left(\frac{1}{4}\cdot x\right)=2:0,02\)

\(8:\left(\frac{1}{4}\cdot x\right)=100\)

\(\frac{1}{4}\cdot x=8:100\)

\(\frac{1}{4}\cdot x=0,08\)

\(x=0,08:\frac{1}{4}\)

\(x=0,32\)

d) \(3:2\frac{1}{4}=\frac{3}{4}:\left(6\cdot x\right)\)

\(\frac{4}{3}=\frac{3}{4}:\left(6\cdot x\right)\)

\(\frac{3}{4}:\frac{4}{3}=6\cdot x\)

\(\frac{9}{16}=6\cdot x\)

\(\frac{9}{16}:6=x\)

\(\frac{3}{32}=x\)

e) \(3,8:\left(2\cdot x\right)=\frac{1}{4}:2\frac{2}{3}\)

\(3,8:\left(2\cdot x\right)=\frac{3}{32}\)

\(2\cdot x=3,8:\frac{3}{32}\)

\(2\cdot x=\frac{608}{15}\)

\(x=\frac{608}{15}:2\)

\(x=\frac{304}{15}\)

f) \(\left(0,25\cdot x\right):3=\frac{5}{6}:0,125\)

\(\left(0,25\cdot x\right):3=\frac{20}{3}\)

\(0,25\cdot x=\frac{20}{3}\cdot3\)

\(0,25\cdot x=20\)

\(x=20:0,25\)

\(x=80\)

g) \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1\cdot x\right)\)

\(\frac{5}{3}=\frac{2}{3}:\left(0,1\cdot x\right)\)

\(\frac{2}{3}:\frac{5}{3}=0,1\cdot x\)

\(\frac{2}{5}=0,1x\)

\(\frac{2}{5}:0,1=x\)

\(4=x\)

(Nhớ thử lại kết quả nhé)

sao bạn tự đăng tự giải thế? hay là bạn giải cho ai à?

ukm bn

a) \({\left( {\frac{8}{9}} \right)^3} \cdot \frac{4}{3} \cdot \frac{2}{3} = {\left( {\frac{8}{9}} \right)^3}.\frac{8}{9} = {\left( {\frac{8}{9}} \right)^{3+1}}={\left( {\frac{8}{9}} \right)^4}\)

b) \({\left( {\frac{1}{4}} \right)^7} \cdot 0,25 = {\left( {0,25} \right)^7}.0,25 ={\left( {0,25} \right)^{7+1}}= {\left( {0,25} \right)^8}\)

c) \({( - 0,125)^6}:\frac{{ - 1}}{8} = {\left( {\frac{{ - 1}}{8}} \right)^6}:\frac{{ - 1}}{8} = {\left( {\frac{{ - 1}}{8}} \right)^{6-1}}= {\left( {\frac{{ - 1}}{8}} \right)^5}\)

d) \({\left[ {{{\left( {\frac{{ - 3}}{2}} \right)}^3}} \right]^2} = {\left( {\frac{{ - 3}}{2}} \right)^{3.2}} = {\left( {\frac{{ - 3}}{2}} \right)^6}\)

a) (1,5 . 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125

=> (2,85 - x - 0,5) : 0,25 = 60

=> (2,85 - 0,5) - x = 60 . 0,25

=> 2,35 - x = 15

=> x = 2,35 - 15

=> x = -12,65

Vậy x = -12,65

b) \(1-\left(5\frac{2}{9}+x-7\frac{7}{18}\right)\div2\frac{1}{6}=0\)

\(\Rightarrow\left(5\frac{2}{9}-7\frac{7}{18}+x\right)\div2\frac{1}{6}=1-0\)

\(\Rightarrow\left(\frac{47}{9}-\frac{133}{18}+x\right)\div2\frac{1}{6}=1\)

\(\Rightarrow\frac{-13}{6}+x=2\frac{1}{6}\)

\(\Rightarrow x=2\frac{1}{6}-\frac{-13}{6}\)

\(\Rightarrow x=\frac{13}{6}+\frac{13}{6}\)

\(\Rightarrow x=\frac{26}{6}\)

\(\Rightarrow x=\frac{13}{3}\)

Vậy \(x=\frac{13}{3}\)

c) \(35\left(2\frac{1}{5}-x\right)=32\)

\(\Rightarrow2\frac{1}{5}-x=32\div35\)

\(\Rightarrow\frac{11}{5}-x=\frac{32}{35}\)

\(\Rightarrow x=\frac{11}{5}-\frac{32}{35}\)

\(\Rightarrow x=\frac{9}{7}\)

Vậy \(x=\frac{9}{7}\)

d) \(\frac{4}{3}+\left(x\div2\frac{2}{3}-0,5\right).1\frac{35}{55}=0,6\)

\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{3}{5}-\frac{4}{3}\)

\(\Rightarrow\left(x\div\frac{8}{3}-\frac{1}{2}\right).\frac{18}{11}=\frac{-11}{15}\)

\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-11}{15}\div\frac{18}{11}\)

\(\Rightarrow x\div\frac{8}{3}-\frac{1}{2}=\frac{-121}{270}\)

\(\Rightarrow x\div\frac{8}{3}=\frac{-121}{270}+\frac{1}{2}\)

\(\Rightarrow x\div\frac{8}{3}=\frac{7}{135}\)

\(\Rightarrow x=\frac{7}{135}.\frac{8}{3}\)

\(\Rightarrow x=\frac{56}{405}\)

Vậy \(x=\frac{56}{405}\)

e) \(1\frac{1}{3}.2\frac{2}{4}\div\frac{5}{6}.1\frac{1}{11}=11-5\div x\)

\(\Rightarrow\frac{4}{3}.\frac{5}{2}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)

\(\Rightarrow\frac{10}{3}\div\frac{5}{6}.\frac{12}{11}=11-5\div x\)

\(\Rightarrow4.\frac{12}{11}=11-5\div x\)

\(\Rightarrow11-5\div x=\frac{48}{11}\)

\(\Rightarrow5\div x=11-\frac{48}{11}\)

\(\Rightarrow5\div x=\frac{73}{11}\)

\(\Rightarrow x=5\div\frac{73}{11}\)

\(\Rightarrow x=\frac{55}{73}\)

Vậy \(x=\frac{55}{73}\)

a) (1,5 * 1,9 - x - 0,5) : 0,25 = 7,5 : 0,125

(2,85 - x - 0,5) : 0,25 = 60

(2,85 - x - 0,5) = 60 x 0,25

(2,85 - x - 0,5) = 15

2,35 - x = 15

x = 2,35 - 15

x = -12,65

b) 1 - \(\left(5\frac{2}{9}+x-7\frac{7}{18}\right):2\frac{1}{6}=0\)

1 - \(\left(\frac{47}{9}+x-\frac{133}{18}\right):\frac{13}{6}=0\)

1 - \(\left(\frac{47}{9}+x-\frac{133}{18}\right)=0\)

\(\frac{47}{9}+x-\frac{133}{18}=1\)

\(x-\frac{13}{6}=1\)

\(x=1+\frac{13}{6}\)

\(x=\frac{19}{6}\)

A= 7/8:(4/18-1/18)+7/8:(1/36-15/36)

=7/8:1/6+7/8:(-7/18)

=7/8:(1/6+-7/18)=7/8:(3/18+-7/18)=7/8:(-2/9)=-63/18=-7/2

còn ý b thì sao bạn??????

a)

\(7,5.\left(\frac{-2}{5}\right).\left(-2,5\right)\)

\(=7,5.\left[\left(\frac{-2}{5}\right).\left(-2,5\right)\right]\)

\(=7,5.1\)

\(=7,5\)

b) 

\(\left(-50,5\right).8.\left(-0,25\right)\)

\(=\left(-50,5\right).\left[8.\left(-0,25\right)\right]\)

\(=\left(-50,5\right).\left(-2\right)\)

\(=101\)

c)

\(\left(0,125\right).\left(-3,7\right).\left(-2\right)^3\)

\(=\left(0,125\right).\left(-3,7\right).\left(-8\right)\)

\(=\left[\left(-8\right).\left(0,125\right)\right].\left(-3,7\right)\)

\(=\left(-1\right).\left(-3,7\right)\)

\(=3,7\)

Chúc cậu học tốt !!!