y x 1,3 + y x 8,7 = 1,5. Tìm y
Những câu hỏi liên quan
Bài 2. Tìm Ya) Y x 8,7 – 2,02 264,2 b) Y x 6,9 + 8,1 x Y 187,5........................................................................................................................... ............................................................................................................................. ........................................................................................................................... .................................................................
Đọc tiếp
Bài 2. Tìm Y
a) Y x 8,7 – 2,02 = 264,2 b) Y x 6,9 + 8,1 x Y = 187,5
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c) 42,55 : ( Y + 1,5 ) = 2,3 d) 10,6 x ( Y – 7,94 ) = 12,72 ...........................................................................................................................
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Bài 2. Tìm Ya) Y x 8,7 – 2,02 264,2 b) Y x 6,9 + 8,1 x Y 187,5........................................................................................................................... ............................................................................................................................. ........................................................................................................................... .................................................................
Đọc tiếp
Bài 2. Tìm Y
a) Y x 8,7 – 2,02 = 264,2 b) Y x 6,9 + 8,1 x Y = 187,5
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c) 42,55 : ( Y + 1,5 ) = 2,3 d) 10,6 x ( Y – 7,94 ) = 12,72 ...........................................................................................................................
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cho dãy số 1,-2,3,-5,5,-8,7,x,y. tìm x, y
8,3+1,7+1,5+8,5+1,3+8,7
\(8,3+1,7+1,5+8,5+1,3+8,7\)
\(=\left(8,3+1,7\right)+\left(1,5+8,5\right)+\left(1,3+8,7\right)\)
\(=10+10+10\)
\(=10\times3\)
\(=30\)
_HT_
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8,3 + 1,7 + 1.5 + 8,5 + 1,3 + 8,7
= (8,3 + 1,7) + (1,5 + 8,5) + (8,7 + 1,3)
= 10 + 10 + 10
= 30
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Bài 1:
a) \(\left(x-1,3\right)^2=9\)
b) \(2^{4-x}=32\)
c) \(\left(x+1,5\right)^2+\left(y-2,5\right)^{10}=0\)
a) \(\left(x-1,3\right)^2=9\Leftrightarrow\left[{}\begin{matrix}x-1,3=3\\x-1,3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4,3\\x=-1,7\end{matrix}\right.\)
b) 24-x = 32
⇔ 24-x = 25
⇔ 4-x=5
⇔ x=-1
c) (x+1,5)2+(y-2,5)10=0
\(\Leftrightarrow\left\{{}\begin{matrix}x+1,5=0\\y-2,5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=-1,5\\y=2,5\end{matrix}\right.\)
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\(a,\left(x-1,3\right)^2=9\\ \Leftrightarrow\left(x-1,3+9\right)\left(x-1,3-9\right)=0\\ \Leftrightarrow\left(x-7,7\right)\left(x-10,3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=7,7=\dfrac{77}{10}\\x=10,3=\dfrac{103}{10}\end{matrix}\right.\)
\(b,2^{4-x}=32=2^5\\ \Leftrightarrow4-x=5\\ \Leftrightarrow x=-1\)
\(c,\left(x+1,5\right)^2+\left(y-2,5\right)^{10}=0\\ \Leftrightarrow\left\{{}\begin{matrix}x+1,5=0\\y-2,5=0\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}x=-1,5=-\dfrac{3}{2}\\y=2,5=\dfrac{5}{2}\end{matrix}\right.\)
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a. (x - 1,3)2 = 9
<=> (x - 1,3)2 - 9 = 0
<=> (x - 1,3)2 - 32 = 0
<=> (x - 1,3 - 3)(x - 1,3 + 3) = 0
<=> (x - 4,3)(x + 1,7) = 0
<=> \(\left[{}\begin{matrix}x-4,3=0\\x+1,7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=4,3\\x=-1,7\end{matrix}\right.\)
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Cho hàm số y = f(x) = x2.
Tính các giá trị f(-8); f(-1,3); f(-0,75); f(1,5).
f(-8) = (-8)2 = 64
f(-1,3) = (-1,3)2 = 1,69
f(-0,75) = (-0,75)2 = 0,5625
f(1,5) = (1,5)2 = 2,25.
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tìm y
a] 8,7 - y = 5,3 + 2
b] y x 5,3 = 9,01 x 4
ghi rỏ ràng nha 3 tick !!!
a) 8,7 - y = 5,3 + 2
8,7 - y = 7,3
y = 8,7 - 7,3
y = 1,4
b) y x 5,3 = 9,01 x 4
y x 5,3 = 36,04
y = 36,04 : 5,3
y = 6,8
k mk nha
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8,7-y=5,3+2
=>8,7-x=7,3
=>x=8,7-7,3=1,4
cau khac truong tu nhe
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tìm x,y biết:x,y*3=y,x-1,3
tìm y: 7,75 - (0,5 x y : 5 -6,2) = 5
y : 6 x 7,2 + 1,3 x y + y : 2 + 15 = 19,95
\(7,75-\left(0,5\times y\div5-6,2\right)=5\)
\(0,5\times y\div5-6,2=7,75-5=2,75\)
\(0,5\div5\times y-6,2=2,75\)
\(0,1\times y=2,75+6,2=8,95\)
\(\dfrac{1}{10}y=8,95\)
\(y=8,95\times10=89,5\)
\(y\div6\times7,2+1,3\times y+y\div2+15=19,95\)
\(1,2\times y+1,3\times y+0,5y=19,95-15=4,95\)
\(y\left(1,2+1,3+0,5\right)=4,95\)
\(2y=4,95\)
\(y=4,95\div2=2,475\)
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