\(115-x\div5=20\)

               \(x\div5=115-20\)

               \(x\div5=95\)

                        \(x=95\times5\)

                        \(x=475\)

115 - x : 5 = 20

x : 5 = 115 - 20

x : 5 = 95

x = 95 x 5

x = 475

Hok tốt

\(115-x:5=20\)

\(< =>115-\frac{x}{5}=20\)

\(< =>\frac{x}{5}=115-20=95\)

\(< =>x=95.5=475\)

a, (-115)+(-40)+115+|-35|

=[(-115) +115] + [(-40) +35]

=-5

b)[ 189 - (34+20-5)] : 20

= (189-49) :20

= 140:20 =7

2.a) x-15= 20.2²

<=> x-15 = 80

<=> x=80 + 15

<=> x=95

VẬy x=95

b) 48 +5(x-3) = 63

<=> 5(x-3) = 63-48

<=> 5(x-3) =15

<=> x-3 = 15:5

<=>x-3 = 3

<=> x=6

Vậy x=6

c) |x| -2 = 7-(-8)

<=> |x| -2 = 15

<=> |x| =15+2

<=> |x| = 17

<=>\(\left[{}\begin{matrix}x=17\\x=-17\end{matrix}\right.\)

Vậy x=17 hoặc x=-17

a, 200 - 3( x - 16 ) = 20

        3( x - 16 )     = 200 - 20 = 180

             x - 16     = 180 : 3 = 60 

                 x        = 60 + 16  =  76

b, 5 + 10 + 15 + .............. + 95 + 100 + 105 = 1200

c, x + ( 99 - 97 + 95 - 93 + ............ + 7 - 5 + 3 - 1 ) = 100

       x + ( 2 . 25 ) = 100

         x + 50       = 100

             x           = 100 - 50 = 50

****, thks 

(617/191+29/33-115/117)*(1/4-1/5-1/20)

= (617/191+29/33-115/117)*(5/20-4/20-1/20)

=(617/191+29/33-115/117)*0

=0

\(\left(\dfrac{617}{191}+\dfrac{29}{33}-\dfrac{115}{117}\right)\times\left(\dfrac{1}{4}-\dfrac{1}{5}-\dfrac{1}{20}\right)\\ =\left(\dfrac{617}{191}+\dfrac{29}{33}-\dfrac{115}{117}\right)\times0\\ =0\)

1. 15 + 4.(x-2) = 95

4.(x-2) = 95-15

4.(x-2) = 80

x - 2 = 80 : 4

x- 2 = 20

x=18

2. 20 - (x+14)=5

x+14=20-5

x+14=15

x =15-14

x= 1

- 15+4(x-2)=95

      4(x-2)=95-15

      4(x-2)=80

         x-2 =80:4

         x-2 =20

        x     =20+2

       x      =22

- 20-(x+14)=5

       (x+14)=20-5

        x+14=15

        x      =15-14

       x       =1

\(4.\left(x-2\right)=95-15\)

\(4.\left(x-2\right)=80\)

\(x-2=80:4\)

\(x-2=20\)

\(x=20+2\)

\(x=22\)

\(x+14=20-5\)

\(x+14=15\)

\(x=15-14\)

\(x=1\)

Bài 1: 

\(101\cdot125+101\cdot25-101\cdot50\)

\(=101\cdot\left(125+25-50\right)\)

\(=101\cdot100\)

\(=10100\)

Bài 2: 

\(76\cdot115+56\cdot24+59\cdot24\)
\(=76\cdot115+24\cdot\left(56+59\right)\)

\(=76\cdot115+24\cdot115\)

\(=115\cdot\left(76+24\right)\)

\(=115\cdot100\)

\(=11500\)

5:

a: =>15x=165

=>x=11

b: =>x(x+1)/2=55

=>x^2+x=110

=>x=10

4: =>7x=56

=>x=8

Bài 1:

101•125+101•25+101•50

= 101•(125+25-50)

=101•100

=10100

Bài 2:

76•115+56•24+59•24

= 76•115+24•(56+59)

= 76•115+24•115

= 115•(76+24)

= 115•100

= 11500

\(\frac{x+5}{95}+\frac{x+10}{90}+\frac{x+15}{85}+\frac{x+20}{80}=-4\)

<=>  \(\frac{x+5}{95}+1+\frac{x+10}{90}+1+\frac{x+15}{85}+1+\frac{x+20}{80}+1=0\)

<=>  \(\frac{x+100}{95}+\frac{x+100}{90}+\frac{x+100}{85}+\frac{x+100}{80}=0\)

<=>  \(\left(x+100\right)\left(\frac{1}{95}+\frac{1}{90}+\frac{1}{85}+\frac{1}{80}\right)=0\)

<=>   \(x+100=0\)   (do 1/95 + 1/90 + 1/85 + 1/80 khác 0)

<=>   \(x=-100\)

Vậy...

a. 12x5+12x95=12x(5+95)=12x100=1200

b. 10x20x5x10=(10x10)x(20x5)=100x100=10000

tk nha

a, 12.5+12.95=12.(5+95)

                       =12.100

                       =1200

b,10.20.5.10=(10.10).(20.5)

                    =100.100

                     =10000

a)  \(12\times5+12\times95\)

\(=12\times\left(5+95\right)\)

\(=12\times100\)

\(=1200\)

chúc bạn học tốt