104,5 x X - 14,1 x X + 9,6 x X = 25

X x ( 104,5 - 14,1 + 9,6 ) = 25

X x 100 = 25

X           = 25 : 100

X           = 0,25

104,5 x X - 14,1 x X + 9,6 x X = 25

X x ( 104,5 - 14,1 + 9,6 ) = 25\(^{^{ }x}\)

X x 100 = 25

X = 25 : 100

  = 0,25

1km=1000m,1hm=100m ,1dam=10m,1hm=10dam. 

toan lop may vay chi oi

huhu tinh nay gio ko ra! Thua lun

ai thi đấu với mình ko

\(104,5.x-14,1.1+9,6.x=25,6.9,6\)

\(\left(104,5-14,1+9,6\right).x=245,76\)

\(100.x=245,76\)

\(x=245,76:100\)

\(x=2,4576\)

Vậy \(x=2,4576\)

Chú ý dấu . là nhân

k mình nha

k mình nha

a,

104,4 . x -14,1 . x + 9,6 . x =25 

x(104,4 - 14,1 + 9,6 ) = 25

x.99,9 = 25

x = \(\frac{250}{999}\)

b)

\(\frac{2009.2010+2000}{2011.2010-2020}=\frac{2009.2010+2000}{\left(2009+2\right).2010-2020}\)

                                    \(=\frac{2009.2010+2000}{2009.2010+2.2010-2020}\)

                                    \(=\frac{2009.2010+2000}{2009.2010+4020-2020}\)

                                    \(=\frac{2009.2010+2000}{2009.2010+2000}\)         

                                     \(=1\)

Thanh you 

#)Giải :

a) \(\frac{2xX-4,36}{0,125}=\)0,25 x 42,9 - 11,7 x 0,25 + 0,25 x 0,8

\(\frac{2xX-4,36}{0,125}=\)0,25 x ( 42,9 - 11,7 + 0,8 )

\(\frac{2xX-4,36}{0,125}=\)0,25 x 32

\(\frac{2xX-4,36}{0,125}=8\)

\(2xX-4,36=8x0,125\)

\(2xX-4,36=1\)

\(2xX=1+4,36\)

\(2xX=5,36\)

\(X=5,36:2\)

\(X=2,68\)

              #~Will~be~Pens~#

#)Next : 

b) 104,5 x X - 14,1 x X + 9,6 x X = 25

   ( 104,5 - 14,1 + 9,6 ) x X          = 25

   100 x X                                   = 25

            X                                   = 25 : 100

            X                                   = 0,25

                #~Will~be~Pens~#

b,

104,5.x-14,1.x+9,6.x=25

x(104,5-14,1+9,6)=25

x.100=25

x=25:100

x=0,25

\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)

\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)

\(\Leftrightarrow2x-4,36=1\)

\(\Leftrightarrow2x=5,36\)

\(\Leftrightarrow x=2,68\)

b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)

\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)

Bài 1:

a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)

\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)

\(\frac{2\cdot x-4,36}{0,125}=8\)

\(2\cdot x-4,36=8\cdot0,125\)

\(2\cdot x-4,36=1\)

\(2\cdot x=1+4,36\)

\(2\cdot x=5,36\)

\(x=\frac{5,36}{2}=2,68\)

b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)

\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)

\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)

\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)

\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)

Bài 2:

a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )

\(x+5,2=4,7\cdot3,2+0,5\)

\(x+5,2=15,54\)

\(x=15,54-5,2=10,34\)

b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)

\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)

Bài 3:

a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)

\(x\cdot\left(104,5-14,1+9,6\right)=25\)

\(x\cdot100=25\)

\(x=\frac{25}{100}=\frac{1}{4}=0,25\)

b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)

\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)

#)Giải :

1. 

Ta có : \(\frac{n+1}{n+2}>\frac{n}{n+2}>\frac{n}{n+3}\)

\(\Rightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)

2. 

a) \(x\left(104,5-14,1+9,6\right)=25\)

\(x\times100=25\)

\(x=25\div100\)

\(x=0,25\)

Bài 1 : Ta có :\(\frac{n+1}{n+2}>\frac{n}{n+2}>\frac{n}{n+3}\)

\(\Leftrightarrow\frac{n+1}{n+2}>\frac{n}{n+3}\)

Bài 2 : \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)

\(\Leftrightarrow\left[104,5-14,1+9,6\right]\cdot x=25\)

\(\Leftrightarrow100\cdot x=25\)

\(\Leftrightarrow x=\frac{1}{4}\)

\(1+2+3+4+...+x=210\)

Số số hạng của dãy là : \((x-1):1+1=x\) số

Cho nên tổng của dãy đó là : \(\frac{x(x+1)}{2}=210\)

\(\Leftrightarrow x(x+1)=420\)

\(\Leftrightarrow x(x+1)=20\cdot21\)

\(\Leftrightarrow x=20\)

\(x-\frac{3}{4}=1-\frac{5}{6}\)

\(\Leftrightarrow x-\frac{3}{4}=\frac{1}{6}\)

\(\Leftrightarrow x=\frac{1}{6}+\frac{3}{4}=\frac{11}{12}\)

\(104,6\cdot x-14,2\cdot x+9,6\cdot x=25\\ x\left(104,6-14,2+9,6\right)=25\\ x\cdot100=25\\ x=\dfrac{25}{100}\\ x=0,25\)

104,6.\(x\) - 14,2.\(x\) + 9,6.\(x\) = 25

(104,6 - 14,2 + 9,6)\(x\) = 25

100\(x\) = 25

\(x\)       = 25: 100

\(x\) = 0,25

0,25

a, 9,6 + x : 3,2 = 12,12

x : 3,2 = 12,12 - 9,6

x : 3,2 = 3,6

       x = 3,6 x 3,2

       x = 11,52

nhanh hộ mình với

x=11,52

k cho mk nha