A<B

A = \(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{217.218}\)

A = \(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{217}-\dfrac{1}{218}\)

A = 1 - \(\dfrac{1}{218}\)

B = \(\dfrac{1}{110}\) + \(\dfrac{1}{111}\) + \(\dfrac{1}{112}\) + ... + \(\dfrac{1}{218}\)

Xét dãy số 110; 111; 112; ...; 218, dãy số này có số số hạng là:

         (218 - 110) : 1 + 1  =  109 (số)

Mặt khác \(\dfrac{1}{110}\) > \(\dfrac{1}{111}>\dfrac{1}{112}>...>\dfrac{1}{218}\)

⇒ B = \(\dfrac{1}{110}\) + \(\dfrac{1}{111}\) + \(\dfrac{1}{112}+...+\dfrac{1}{218}\) < \(\dfrac{1}{110}\) + \(\dfrac{1}{110}\)+ ... +\(\dfrac{1}{110}\)  

   B < \(\dfrac{1}{110}\) x 109

B  <  1 - \(\dfrac{1}{110}\)

\(\dfrac{1}{128}\) < \(\dfrac{1}{110}\) ⇒ A =  1 - \(\dfrac{1}{128}\) > 1 - \(\dfrac{1}{110}\)  > B 

A > B 

\(A=\frac{1\times111+2\times110+3\times109+...+111\times1}{1+\left(1+2\right)+\left(1+2+3\right)+...+\left(1+2+3+...+111\right)}\)

\(A=\frac{1\times111+2\times110+3\times109+...+111\times1}{\left(1+1+...+1\right)+\left(2+2+...+2\right)+...+111}\)(\(111\)số hạng \(1\), \(110\)số hạng \(2\),...)

\(A=\frac{1\times111+2\times110+3\times109+...+111\times1}{1\times111+2\times110+3\times109+...+111\times1}\)

\(A=1\)

a) 4⁵

b) 110⁹⁹

a) 4⁵

b) 111⁹⁹

C = 1 10 + 1 11 + 1 12 + ... + 1 99 + 1 100 > 1 ⇔ C = 1 10 + 1 11 + 1 12 + ... + 1 20 + 1 21 + 1 22 + ... + 1 30 + ... + 1 91 + 1 92 + ... + 1 100 C > 1 10 + 10 20 + 10 30 + ... + 10 100 > 10 20 + 10 30 + 10 60 = 1 2 + 1 3 + 1 6 = 1

C = 1 10 + 1 11 + ... + 1 100 > 1 10 + 1 100 = ... + 1 100 ⏟ 90 s o = 1 10 + 90 100 = 1

a) A > 1 20 + 1 20 + ... + 1 20 ⏟ 10 s o = 10 20 = 1 2 .

b)  B = 1 5 + ... 1 9 + 1 10 + ... + 1 17 < 1 5 + ... + 1 5 ⏟ 5s o + 1 8 + ... + 1 8 ⏟ 8s o = 2

c)  C = 1 10 + 1 11 + 1 12 ... + 1 18 + 1 19 < 1 10 + 1 10 + ... 1 10 ⏟ 9 s o = 1