(x+5 ) + (x+10 ) + (x+15) + ... +(x+100) = 1110
(x+5)+(x+10)+(x+15)+…+(x+100)=1110
3. cái này tớ thi trong violympic rồi. đảm bảo luôn
tk cho tớ nhé
(x+5)+(x+10)+(x+15)+...(x+100)=1110
\(20x+5+10+15+..+100=1110\)
\(20x+1050=1110\)
\(20x=50\)
\(x=2,5\)
Ai tích mk mk tích lại cho
sai rui . lop 4 da hoc so thap phan dau ha ban
( x+5 ) + ( x+10) + ( x+15) + ........ + ( x+ 100) = 1110. Tìm x
( x + 5 ) + ( x + 10 ) + ...+ ( x + 100 ) = 1110
=> ( x+x+x+...+x) + ( 5+10+15+...+100) = 1110
=> x . 20 + 1050
=> x . 20 = 60
=> x = 3
vậy x = 3
( x + 5 ) + ( x + 10 ) + ( x + 15 ) + ........ + ( x + 100 ) = 1110. Tìm x
=> ( x + x + x + ... + x ) + ( 5 + 10 + 15 + ... + 100 ) = 1110
=> X x 20 + 1050
=> X x 20 = 60
=> X = 3
Vậy x bằng : 3
(x+5)+(X+10)+(x+15)+....+(x+100)=1110
20x+(5+10+15+...+100)=1110
20x+1050=1110
20x=1110-1050
20x=60
x=60:20
x=3
tìm x biết : (x+5) + (x+10) + (x+15) +...+ (+100)= 1110
( x + 5 ) + ( x + 10 ) + ( x + 15 ) + ...... + ( x + 100 ) = 1110
20x + ( 5 + 10 + 15 + ..... + 100 ) = 1110
20x + ( 105 x 10 ) = 1110
20x + 1050 = 1110
20x = 1110 - 1050
20x = 60
x = 60 : 20
x = 3
Vậy x = 3
Tra loi:
(x+5)+(x+10)+x+15+.....+(x+100)=1110
=>( x+x+.....+x) + (5+10+...+100)=1110
=> 20x +1050=1110
=> 20x=60
=> x=3
( x + 5 ) + ( x + 10 ) + ( x + 15 ) +...................+ ( x + 100 ) = 1110
( x + 5 ) + ( x + 10 ) + ( x + 15 ) +...................+ ( x + 100 ) = 1110:
(100-5): 5 + 1=20
= x+ ( 5+ 10)x20:2)= 1110
=x+ 150=1110
x= 1110 - 150
x= 960
1.Tìm x,biết:
(x + 5) + (x +10) + (x +15) + ... + (x +100) = 1110
( x + 5 ) + ( x + 10 ) + . . . + ( x + 100 ) = 1110
=> x × 20 + ( 5 + 10 + . . . + 100 ) = 1110
=> x × 20 + 1050 = 1110
=> x × 20 = 60
=> x = 60 : 20
=> x = 3
Số số hạng của dãy là:(100-5):5+1=20
(x+x+...+x)+(5+10+15+...+100)=1110
x × 20+(100+5)×20:2=1110
x×20+1050=1110
x×20=1110-1050
x×20=60
x=60:20
x=3
( x + 5 ) + ( x + 10 ) + ( x + 15 ) + ... + ( x + 100 ) = 1110
Trả lời : Tìm x = ?
( x + 5 ) + ( x + 10 ) + ...+ ( x + 100 ) = 1110
=> ( x+x+x+...+x) + ( 5+10+15+...+100) = 1110
=> x . 20 + 1050
=> x . 20 = 60
=> x = 3
vậy x = 3
<=>(x+x+x+...+x)+(5+10+...+100)=1110
=>20x+1050=1110
=>20x=1110-1050
=>20x=60
=>x=3
( x + 5 ) + ( x + 10 ) + ...+ ( x + 100 ) = 1110
=> ( x+x+x+...+x) + ( 5+10+15+...+100) = 1110
=> x . 20 + 1050
=> x . 20 = 60
=> x = 3
vậy x = 3
Tìm x biết
∣∣∣x−35∣∣∣=12|x−35|=12
a.
x=−1110x=−1110
b.
x=110;x=−110x=110;x=−110
c.
x=−1110;x=−110x=−1110;x=−110
d.
x=1110;x=110x=1110;x=110
Giải các phương trình:
a) \(\dfrac{x+2001}{5}+\dfrac{x+1999}{7}+\dfrac{x+1997}{9}+\dfrac{x+1995}{11}=-4;\)
b) \(\dfrac{x-15}{100}+\dfrac{x-10}{105}+\dfrac{x-100}{110}=\dfrac{x-100}{15}+\dfrac{x-105}{10}+\dfrac{x-110}{5}.\)
a: \(\Leftrightarrow\left(\dfrac{x+2001}{5}+1\right)+\left(\dfrac{x+1999}{7}+1\right)+\left(\dfrac{x+1997}{9}+1\right)+\left(\dfrac{x+1995}{11}+1\right)=0\)
=>x+2006=0
=>x=-2006
b: \(\Leftrightarrow\left(\dfrac{x-15}{100}-1\right)+\left(\dfrac{x-10}{105}-1\right)+\left(\dfrac{x-100}{5}-1\right)=\left(\dfrac{x-100}{15}-1\right)+\left(\dfrac{x-105}{10}-1\right)+\left(\dfrac{x-110}{5}-1\right)\)
=>x-105=0
=>x=105