\(A=3+3^2+....+3^{99}\)

\(3A=3^2+3^3+...+3^{100}\)

\(3A-A=3^2+3^3+...+3^{100}-3-3^2-...-3^{99}\)

\(2A=3^{100}-3\)

\(A=\dfrac{3^{100}-3}{2}\)

\(\Rightarrow2A+3=9^{2x+6}\)

\(\Rightarrow2\cdot\dfrac{3^{100}-3}{2}+3=\left(3^2\right)^{2x+6}\)

\(\Rightarrow3^{100}-3+3=3^{2\left(2x+6\right)}\)

\(\Rightarrow3^{100}=3^{4x+12}\)

\(\Rightarrow4x+12=100\)

\(\Rightarrow4x=88\)

\(\Rightarrow x=22\)

\(a.3x^2-50=142\)

\(3x^2=142+50\)

\(3x^2=192\)

\(x^2=192:3\)

\(x^2=64\)

\(\Rightarrow x=8\)

vậy: x=8.

\(b.3x^2=192\)

\(x^2=192:3\)

\(x^2=64\)

\(\Rightarrow x=8\)

Vậy: x=8.

\(c.4x^2=100\)

\(x^2=100:4\)

\(x^2=25\)

\(\Rightarrow x=5\)

vậy: x=5.

\(d.x^2+7=56\)

\(x^2=56-7\)

\(x^2=49\)

\(\Rightarrow x=7\)

Vậy: x=7.

<câu e bạn xem lại cho mk có phải sai đầu bài không nha,tại mk thấy kết quả là 21 nhưng mà không có cái nào bình phương =21 cả> 

$a.3{}^{}-50=142$

$3{}^{}=142+50$

$3{}^{}=192$

${}^{}=192:3$

${}^{}=64$

$\Rightarrow x=8$

vậy: x=8.

$b.3{}^{}=192$

${}^{}=192:3$

${}^{}=64$

$\Rightarrow x=8$

Vậy: x=8.

$c.4{}^{}=100$

${}^{}=100:4$

${}^{}=25$

$\Rightarrow x=5$

Bài 6 :

a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)

b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)

c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)

d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)

Bài 7 :

a) \(3^x+3^{x+2}=9^{17}+27^{12}\)

\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)

\(\Rightarrow10.3^x=3^{34}+3^{36}\)

\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)

\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)

b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)

\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)

\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)

c) Bài C bạn xem lại đề

d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)

\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)

\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)

\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)

\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)

\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)

5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha5 ha 4 dm² = 5,000004 ha

  Bài 1:

2^\(x\) = 4

2\(^x\) = 2²

 \(x=2\)

Vậy \(x=2\)

Bài 2:

2\(^x\) = 8

2\(^x\) = 2³

\(x=3\)

Vậy \(x=3\)

Bài 3

2\(^x\) = 16

2\(^x\) = 2⁴

  \(x=4\)

Vậy \(x=4\)

Câu a mình ko bt trình bày thông cảm

b) \(^{2^x.\left(2^2\right)^2=\left(2^3\right)^2}\)

\(2^x.2^4=2^6\)

\(2^x=2^6:2^4\)

\(2^x=2^2\)

\(x=2\)

a)(x^5)^10=x<=>x=0 hoặc 1

các bạn ơi cho minh hoi cai:

10 mũ x+4y=2013 

Hãy cho minh dap an chinh xac 

Cam on cac ban da xem bai viet cua minh 

và mình cũng cảm ơn những ai đã trả lời cho minh va hay cho minh nhe!

Bài 9,

6²x73+36x3³=36x73+36x27=36(73+27)=36x100=3600.

197-\([\)6x(5-1)²+2022⁰\(]\):5=197-\([\)6x16+1\(]\):5=197-97:5=197-97/5=888/5.

Bài 10,

21-4x=13

=>4x=21-13=8

=>x=8:4=2.

30:(x-3)+1=4⁵:4³=4²=16

=>30:(x-3)=16-1=15

=>x-3=30:15=2

=>x=2+3=5.

(x-1)³+5x6=38

=>(x-1)³+30=38

=>(x-1)³=38-30=8=2³

=>x-1=2

=>x=3.

AI NHANH MÌNH K , ĐANG CẦN GẤP

a)xét 2A =2+2^2+2^3+.....+2^2019

-A=1+2+2^2+...+2^2018

A=(2^2019)-1 <2^2019

b)theo câu a ta có A+1=2^2019-1+1=2^2019=2^(x+1)

2019=x+1 =>x=2018

c)theo câu b ta có A+1=2^2019=2.4^x=2^(1+2x)

=>2019=1+2x

tự làm nốt

a) 25+x=0

   x=0-25

  x=-25

b)\(2^x:2^{19}=2^{25}\)

\(2^x=2^{25}.2^{19}\)

\(2^x=2^{44}\)

=>x=44

c)\(5^x.5^{18}=5^{54}\)

\(5^x=5^{54}:5^{18}\)

\(5^x=5^{36}\)

=>x=36

TL :

a) \(25+x=0\)

\(x=0-25\)

\(x=-25\)

b) \(2^x:2^{19}=2^{35}\)

\(2^x=2^{25}.2^{19}\)

\(2^x=2^{44}\)

\(\Rightarrow x=44\)

c) \(5^x.5^{18}=5^{54}\)

\(5^x=5^{54}:5^{18}\)

\(5^x=5^{36}\)

\(\Rightarrow x=36\)

Học tốt

a,25+x=0

\(\Rightarrow\)x= 0-25

\(\Rightarrow\)x= -25

Vậy x=-25

b, 2\(^x\): 2\(^{19}\)=2\(^{25}\)

\(\Rightarrow\)2\(^x\)= 2\(^{25}\). 2\(^{19}\)= 2\(^{25+19}\)

\(\Rightarrow\)2\(^x\)= 2\(^{44}\)

\(\Rightarrow\)x = 44

Vậy x=44

c, 5\(^x\). 5\(^{18}\)= 5\(^{54}\)

5\(^x\)= 5\(^{54}\): 5\(^{18}\)= 5\(^{54-18}\)

\(\Rightarrow\)5\(^x\)= 5 \(^{36}\)

\(\Rightarrow\)x= 36

vậy x = 36