Tìm x biết: 2015.|x-15|+(x-15)\(^2\) =2014.|15-x|
Tìm x,biết:
a)x . (2013 + 2014 + 2015) = 0
b) x . 125 = 10000
c)697 : [(15 . x + 364) : x] = 17
Trả lời:
a, x . ( 2013 + 2014 + 2015 ) = 0
=> x = 0 : ( 2013 + 2014 + 2015 )
=> x = 0
Vậy x = 0
b, x . 125 = 10000
=> x = 10000 : 125
=> x = 80
Vậy x = 80
c, 697 : [ ( 15 . x + 364 ) : x ] = 17
=> ( 15 . x + 364 ) : x = 697 : 17
=> ( 15 . x + 364 ) : x = 41
=> 15 . x + 364 = 41 . x
=> 41 . x - 15 . x = 364
=> ( 41 - 15 ) . x = 364
=> 26 . x = 364
=> x = 364 : 26
=> x = 14
Vậy x = 14
B = (5+10+15+.........+2015) x (20142014 x 2015-20152015 x 2014)
Giải:
\(B=\left(5+10+15+...+2015\right)\times\left(20142014\times2015-20152015\times2014\right)\)
\(B=\left(5+10+15+...+2015\right)\times\left(10001\times2014\times2015-10001\times2015\times2014\right)\)
\(B=\left(5+10+15+...+2015\right)\times0\)
\(B=0\)
Chúc em học tốt!
B = (5+10+15+.........+2015) x (20142014 x 2015-20152015 x 2014)
B = (5+10+15+.........+2015) x ( 2014 x 1001 x 2015 - 2015 x 1001 x 2014 ] B = (5+10+15+.........+2015) x 0B = 0 nhaCho f(x)=x^17-2015*x^16|+2015*x^15-2015*x^14+...+2015*x-1
Tinh f(2014)
Với x = 2014 => x + 1 = 2015
Ta có :
\(f\left(x\right)=x^{17}-2015x^{16}+2015x^{15}-2015x^{14}+....+2015x-1\)
<=> \(f\left(x\right)=x^{17}-\left(x+1\right)x^{16}+\left(x+1\right)x^{15}-\left(x+1\right)x^{14}+....+\left(x+1\right)x-1\)
<=> \(f\left(x\right)=x-1\)
<=> \(f\left(2014\right)=2014-1=2013\)
\(\dfrac{x+2}{2014}\)+\(\dfrac{x+1}{2015}\)=\(\dfrac{x+2001}{15}\)+\(\dfrac{2014}{12}\)
Giúp mình với, mình cảm ơn nhiều ạ
Sửa đề: \(\dfrac{x+2}{2014}+\dfrac{x+1}{2015}=\dfrac{x+2001}{15}+\dfrac{x+2014}{2}\)
Ta có: \(\dfrac{x+2}{2014}+\dfrac{x+1}{2015}=\dfrac{x+2001}{15}+\dfrac{x+2014}{2}\)
\(\Leftrightarrow\dfrac{x+2}{2014}+1+\dfrac{x+1}{2015}+1=\dfrac{x+2001}{15}+1+\dfrac{x+2014}{2}+1\)
\(\Leftrightarrow\dfrac{x+2016}{2014}+\dfrac{x+2016}{2015}=\dfrac{x+2016}{15}+\dfrac{x+2016}{2}\)
\(\Leftrightarrow\dfrac{x+2016}{2014}+\dfrac{x+2016}{2015}-\dfrac{x+2016}{15}-\dfrac{x+2016}{2}=0\)
\(\Leftrightarrow\left(x+2016\right)\left(\dfrac{1}{2014}+\dfrac{1}{2015}-\dfrac{1}{15}-\dfrac{1}{2}\right)=0\)
mà \(\dfrac{1}{2014}+\dfrac{1}{2015}-\dfrac{1}{15}-\dfrac{1}{2}\ne0\)
nên x+2016=0
hay x=-2016
Vậy: S={-2016}
( 2014 x 2015 - 15/1000 + 2015 x 2013 ) + 10
x-2014/14-x-2015/15=0
\(\frac{x-2014}{14}-\frac{x-2015}{15}=0\)
<=> \(\frac{15\left(x-2014\right)}{14\cdot15}-\frac{14\left(x-2015\right)}{14\cdot15}=0\)
<=> \(15x-30210-14x+28210=0\)
<=> \(x-2000=0\)
<=> \(x=2000\)
Vậy nghiệm của phương trình là S = { 2000 }
x-(2014/14-2015/15)=0
x-200/21=0
x=0+200/21
x=200/21
( 222222/101010 + 222222/404040 + 222222/888888 ) + x = ( 2014 x 2015 - 15 / 1000 + 2015 x 2013 ) + 10
câu 1: tìm x biết:
a, (4x-15)^2016=(4x-15)^2015
b,2^x+2^x+1+2^x+2+2^x+3-480=0
a) => (4x-15).(4x-15)2015=(4x-15)2015
=> 4x-15=1
=> x=4
b) => 4.2x+6-480= 0
=> 4.2x-474=0
=> 4.2x=474
=> 2x= 118,5
ko có gt x thoả mãn đề bài
chả biết câu b trình bày đúng hay sai, hay là đầu bài chép nhầm nữa. Nếu sai ai đó chữa lại hộ cái nhé
_HẾT_
b, 2x+2x+1+2x+2+2x+3-480=0
2^x.1+2^x.2+2^x.2^2+2^x.2^3=480
2^x.(1+2+2^2+2^3)=480
2^x.15=480
2^x=32
2^x=2^5
x=5
tìm số tự nhiên x biết
A,x^2015=x^2016
17.x là số nguyên tố
tìm số nguyên x biết
|x+1|-1=2015
x+15=|x|-15
|x|>x
(3x-2)chia hết cho (2x+1)
dua nao tra loi ma ngu the
viet ro cach lam ra chu