\(\left(x+1\right)\left(x+2\right)\left(x+5\right)-x^2\left(x+8\right)=27\)

\(\Leftrightarrow\left(x^2+3x+2\right)\left(x+5\right)-\left(x^3+8x^2\right)-27=0\)

\(\Leftrightarrow17x-17=0\\ \Leftrightarrow x=1\)

(x+1).(x+2).(x+5)-x^2.(x+8)= 27

\(\Leftrightarrow\left(x^2+2x+x+2\right)\left(x+5\right)-x^3-8x^2-27=0\)

\(\Leftrightarrow x^3+5x^2+2x^2+10x+x^2+5x+2x+10-x^3-8x^2-27=0\)

\(\Leftrightarrow17x-17=0\)

\(\Leftrightarrow x=1\)

(x + 1).(x + 2).(x + 5) - x².(x + 8) = 27

<=> x³ + 8x² + 17x + 10 - x² - 8x² = 27

<=> 17x + 10 = 27

<=> 17x = 27 - 10

<=> 17x = 17

<=> x = 1

=> x = 1

Mình cần giải thích cặn kẽ ạ !

a. \(\dfrac{x}{5}=\dfrac{8}{10}\)

\(\Rightarrow10x=8.5\)

\(\Rightarrow10x=40\)

\(\Rightarrow x=\dfrac{40}{10}=4\)

b. \(\dfrac{9}{x}=\dfrac{90}{100}\)

\(\Rightarrow9.100=90x\)

\(\Rightarrow900=90x\)

\(\Rightarrow x=\dfrac{900}{90}=10\)

c. \(17+\dfrac{x}{35}=\dfrac{5}{7}\)

\(\Rightarrow\dfrac{595+x}{35}=\dfrac{25}{35}\)

\(\Rightarrow595+x=25\)

\(\Rightarrow x=25-595=-570\)

d. \(x:\dfrac{5}{27}=\dfrac{2}{9}\)

\(\Rightarrow\dfrac{27x:5}{27}=\dfrac{6}{27}\)

\(\Rightarrow27x:5=6\)

\(\Rightarrow27x=5.6\)

\(\Rightarrow27x=30\)

\(\Rightarrow x=\dfrac{30}{27}=\dfrac{10}{9}\approx1,11\)

(x + 1)(x + 2)(x + 5) − x²(x + 8) = 27

x² + 2x + x + 2(x + 5) − x³ − 8x² = 27

x²(x + 5) + 2x(x + 5) + x(x + 5) + 2(x + 5) − x³ − 8x² = 27

x³ + 5x² + 2x² + 10x + x² + 5x + 2x + 10 − x³ − 8x² = 27

17x + 10 = 27

17x = 17

    x = 17 : 17

    x = 1

Vậy x = 1

1) x-12=(-8)+(-17)
    x-12=(-25)
    x      = (-25)+12
    x      = (-13)

a,2/5 = 2/5 ; 3/8=6/16 ; 1/9=3/27

b, 4/3=8/6 ; -1=-1 ; -4/-2=-8/4

tick cho mik nhé 

a) x= 2, x= 8.(6 : 3) = 16, x= 1. (27 : 9)= 3

b) x= 6 : (8 : 4) = 3, x= -1, x= -2 . -8 = x.x => 16 = x² => 4² = x² => x=4

        Tick cho mình đi 

\(8\left(x+2\right)^5=27\left(x+2\right)^8\)

\(2^3\left(x+2\right)^5=3^3\left(x+2\right)^8\)

\(3^3\left(x+2\right)^3=2^3\)

\(\left(x+2\right)^3=(\frac{2}{3})^3\)

\(x+2=\frac{2}{3}\)

\(x=\frac{2}{3}-2=-\frac{4}{3}\)