a) \(3^{39}\) và \(11^{21}\)

\(\Rightarrow3^{39}=3^{13.3}=1594323^3\)

\(\Rightarrow11^{21}=11^{7.3}=194487171^3\)

Nên \(3^{39}< 11^{21}\)

b) \(199^{20}\) và \(2003^{15}\)

\(\Rightarrow199^{20}=199^{4.5}=1568239201^5\)

\(\Rightarrow2003^{15}=8036054027^5\)

Nên \(199^{20}< 2003^{15}\)

339 và 1121

339< 342; 342=36.7=(36)7=7297

1121= 113.7=(113)7=13317

Vì 7297< 13317=> 342<1121

=>339<1121

CHUC HOK TOT

32 mũ 18 = 64 mũ 9

Vì 15 > 9 nên 63 mũ 15 > 64 mũ 9

thế thôi!

63 ^15 = 63^ 5.3 = ( 63^ 5 ) 3 = 992 436 543^ 3

34 ^18 = 34^ 6.3 = ( 34^ 6 ) 3 = 1 544 804 416 ^3

Vì : 992 436 543^ 3 < 1 544 804 416^ 3

Nên : 63 ^15 < 34^ 18 

63 mũ 15 >34 mũ 18

thanks

25^15>(-8)^10 x 3^30

k cho mình nhé

a) ta có: 7^10 < 7^14 = (7^2)^7 = 49^7 < 50^7

=> 7^10 < 50^7

b) ta có: 5^30 = (5^3)^10 = 125^10 > 124^10

=> 5^30 > 124^10

c) ta có: 9^21 = (9^3)^7=729^7

phần d thì mk ko bk, xl bn nha

a,<

b,>

c,=

^_^

a,

15^12=(3*5)^12=3^12*5^12

81^3*125^5=(3^4)^3*(5^3)^5=3^12*5^15

Vì 12<15 suy ra 5^12<5^15

Suy ra 3^12*5^12<3^12*5^15

\(a.81^3.125^5=\left(3^4\right)^3.\left(5^3\right)^5=3^{12}.5^{15}=3^{12}.5^{12}.5^3=\left(3.5\right)^{12}.5^3=15^{12}.5^3>15^{12}\)

\(b.4^{20}.81^{12}=\left(2^2\right)^{20}.\left(9^2\right)^{12}=2^{40}.9^{24}=2^{20}.2^{20}.9^{20}.9^4=\left(2.9\right)^{20}.2^{20}.9^4=18^{20}.2^{20}.9^4>18^{20}\)

\(c.73^{75}=\left(73^3\right)^{25}=389017^{25}\)

\(107^{50}=107^{2.50}=\left(107^2\right)^{25}=11449^{25}\)

Vì \(389017^{25}>11449^{25}\Rightarrow73^{75}>107^{50}\)

 Để tớ ghi đề giùm cho các bạn hiểu :

\(11^{21}+1\div11=121\)

\(4^{2x}+1=64\)

So sánh

\(10^{30}...2^{100}\)

\(2^{98}...9^{42}\)

bài 1

4^2x+1 = 64

=> 4^2x+1 = 4³

=> 2x + 1 = 3

=> 2x = 2

=> x = 1

bài 2

10³⁰ = ( 10³ )¹⁰ = 1000¹⁰

2¹⁰⁰ = ( 2¹⁰ )¹⁰ = 1024¹⁰

=> 1000¹⁰ < 1024¹⁰

=> 10³⁰ < 2¹⁰⁰

2⁹⁸ = ( 2⁷ )¹⁴ = 128¹⁴

9⁴² = ( 9³ )¹⁴ = 729¹⁴

=> 128¹⁴ < 729¹⁴

=> 2⁹⁸ < 9⁴²