b) 2x^2 + 7x - 15

2x^2 + 10x - 3x -15

2x(x+5) - 3(x+5)

(x+5)(2x-3)

a, 5x^3y - 10x^2y^2 + 5xy^3 = 5xy. ( x^2 - 2xy + y^2) = 5xy.( x-y)^2

b, 2x^2 + 7x -15 = 2x^2 + 10X - 3x -15

                       = 2x( x+5) - 3( x+5)

                 = ( 2x-3) (x+5) 

a)

\(5xy\left(x^2-2xy+y^2\right)=5xy\left(x-y\right)^2\)

b)

\(x\left(2x-3\right)+5\left(2x-3\right)=\left(2x-3\right)\left(x+5\right)\)

=(x-3y)(3x+y)

ok nhớ tích nha

\(3x^2-5xy-3y^2\)

\(\text{ Phân tích thành nhân tử}\)

\(-\left(3y^2+5xy-3x^2\right)\)

Chúc bạn học tốt

Ta có : 

2x^2-5xy-3y^2

 = 2^x + xy - 6xy - 3y^2  

= x(2x + y) - 3y(2x + y)  

= (2x + y)(x - 3y)

\(a,15x-5xy\\ =5x\left(3-y\right)\\ b,\left(x^2+1\right)^2-4x^2\\ =\left(x^2-x+1\right)\left(x^2+x+1\right)\\ c,x^2-10x-9y^2+25\\ =\left(x-5\right)^2-9y^2\\ =\left(x-9y-5\right)\left(x+9y-5\right)\)

hé lu ông zà

a) 5x(3 - y)

b) (x² - x + 1)(x² + x + 1)

c) (x - 9y - 5)(x + 9y - 5)

2x^2-5xy-3y^2

 = 2^x + xy - 6xy - 3y^2  

= x(2x + y) - 3y(2x + y)  

= (2x + y)(x - 3y)

a/ \(\left(x+3y\right)\left(2x-y\right)\)

b/ \(\left(x^2+2\right)\left(x^2-2\right)\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)

b/ \(x^8-16=\left(x^4+4\right)\left(x^4-4\right)\)

\(=\left[\left(x^4+4x^2+4\right)-4x^2\right]\left(x^2-2\right)\left(x^2+2\right)\)

\(=\left[\left(x^2+2\right)^2-4x^2\right]\left(x^2-2\right)\left(x^2+2\right)\)

\(=\left(x^2+2+2x\right)\left(x^2+2-2x\right)\left(x^2-2\right)\left(x^2+2\right)\)

\(\left(x^2-2xy+y^2\right)+81\)

em.........

bó tay