(x-5) x \(\frac{30}{100}\)= 200x : 100 + 5

(x-5) x \(\frac{3}{10}\)= 200x : 100 + 5

\(\frac{x.3-15}{10}\)= 2x + 5

\(\frac{x.3-15}{10}-2x=5\)

\(\frac{x.3-15}{10}-\frac{20x}{10}=5\)

\(\frac{3x-15-20x}{10}=5\)

3x - 20x - 15 = 50

-17x - 15 = 50

-17x = 65

x = 65 : -17

x = \(\frac{-65}{17}\)

=>3/10(x-5)=2x+5

=>3/10x-3/2=2x+5

=>-17/10x=5+3/2=6/2+3/2=11/2

=>x=-55/17

a) \(2^{x+2}-2^2=96\)

 <=> \(2^x.2^2-2^x=96\)

 <=> \(2^x\left(4-1\right)=96\)

<=> \(3.2^x=96\)

<=> \(2^x=32\)

<=> \(2^x=2^5\)

<=> x = 5 

b, \(x-\left(\frac{50x}{100}+\frac{25x}{200}\right)=11\frac{1}{4}\)

\(\Rightarrow x-\left(\frac{1x}{2}+\frac{1x}{8}\right)=\frac{45}{4}\)

\(\Rightarrow x-\left(\frac{4x}{8}+\frac{1x}{8}\right)=\frac{45}{4}\)

\(\Rightarrow x-\frac{5x}{8}=\frac{45}{4}\)

\(\Rightarrow\frac{8x}{8}-\frac{5x}{8}=\frac{45}{4}\)

\(\Rightarrow\frac{3x}{8}=\frac{45}{4}\Rightarrow x=\frac{45}{4}\div\frac{3}{8}=30\)

Vậy x = 30 

a) pt a <=> 3x+1=0     hoặc        x-2000=0         hoặc      3x+6000=0

           <=> x=-1/3      hoặc        x=2000            hoặc      x=-2000

uk

a, \(\left(x-5\right).30\%=\dfrac{20x}{100}+5\Rightarrow\left(x-5\right).\dfrac{3}{10}=\dfrac{x}{5}+5\)

\(\Rightarrow\dfrac{3}{10}x+\dfrac{3}{2}=\dfrac{x}{5}+5\Rightarrow\dfrac{3}{10}x-\dfrac{x}{5}=5-\dfrac{3}{2}\)

\(\Rightarrow x\left(\dfrac{3}{10}-\dfrac{1}{5}\right)=\dfrac{7}{2}\Rightarrow\dfrac{1}{10}x=\dfrac{7}{2}\Rightarrow x=35\)

b, \(\dfrac{x+3}{x-2}\in Z\)

Ta có: \(\dfrac{x-2+5}{x-2}=\dfrac{x-2}{x-2}+\dfrac{5}{x-2}=1+\dfrac{5}{x-2}\)

Để \(\dfrac{x+3}{x-2}\in Z\Leftrightarrow\dfrac{5}{x-2}\Leftrightarrow5⋮\left(x-2\right)\Rightarrow\left(x-2\right)\in U\left(5\right)\)

\(\Rightarrow\left(x-2\right)\in\left\{1;5\right\}\Rightarrow x\in\left\{-1;3\right\}\)

Kiến thức lâu k học :> sai gì bỏ qua giùm :<<