3+4+7+2+8+5+10x5:19
thuận tiện 19/20x2/100+19/20x2/100
75/76x102/100-75/76x2/100
3x7/10+7/10x5+2x7/10
giá trị biểu thức
2/5+2/3x3/4
1/2x1/3-1/8
(1/2+1/3):3/9
19/20x2/100+19/20x2/100
= [19/20+19/20]x2/100
= 38/20x2/100
= 19/500
75/76x102/100-75/76x2/100
= [102/100-2/100]x75/76
= 1x75/76
= 75/76
3x7/10+7/10x5+2x7/10
= [3+5+2]x7/10
= 10x7/10
= 7
giá trị biểu thức
2/5+2/3x3/4
= 2/5+1/6
= 17/30
1/2x1/3-1/8
= 1/6-1/8
= 1/24
[1/2+1/3]:3/9
= 5/6:3/9
= 5/2
nhớ tick cho tớ nhé
giúp mình giải bài này với:
so sánh các tích sau bằng cách hợp lí
A=(-43/51)x(-19/80)
B=(-7/13)x(-4/65)x(-8/31)
C=-5/10x-4/10x-3/10...3/10x4/10x5/10
b.8/3-x=9/10x5/3 c.x:5/9=2-11/8 d.Xx2/3+Xx7/3=11/4
b,8/3-x=9/10x5/3=3/2
=>x=8/3-3/2=7/6
c,x:5/9=2-11/8=5/8
=>x=5/8x5/9=25/72
d,x\(\cdot\)2/3+x\(\cdot\)7/3=11/4
=>x(2/3+7/3)=11/4
=>x=11/4:(2/3+7/3)=11/4:10/3=33/40.
\(b,\dfrac{8}{3}-x=\dfrac{9}{10}\times\dfrac{5}{3}\\ \Leftrightarrow x=\dfrac{7}{6}\)
\(c,x:\dfrac{5}{9}=2-\dfrac{11}{8}\\ \Leftrightarrow x=\dfrac{25}{72}\)
\(d,x\times\dfrac{2}{3}+x\times\dfrac{7}{3}=\dfrac{11}{4}\\ \Leftrightarrow3x=\dfrac{11}{4}\\ \Leftrightarrow x=\dfrac{11}{12}\)
1+34-45+12x3-4-5-6-7+8-9-10x5=??
ai nhanh có tk
1 + 34 - 45 + 12 x 3 - 4 - 5 - 6 - 7 + 8 - 9 - 10 x 5
= 1 + 34 - 45 + 36 - 4 - 5 - 6 - 7 + 8 - 9 - 50
= 35 - 45 + 36 - 4 - 5 - 6 - 7 + 8 - 9 - 50
= -10 + 36 - 4 - 5 - 6 - 7 + 8 - 9 - 50
= 26 - 4 - 5 - 6 - 7 + 8 - 9 - 50
= 22 - 5 - 6 - 7 + 8 - 9 - 50
= 17 - 6 - 7 + 8 - 9 - 50
= 11 - 7 + 8 - 9 - 50
= 4 + 8 - 9 - 50
= 12 - 9 - 50
= 3 - 50
= -47
Học tốt !!!
Tính hợp lý:
a) ( -5/6 + 2/5) : 3/8 + ( 4/5 - 11/30) : 3/8
b) (-3/4 + 2/5) : 3/7 + ( 3/5 + -1/4) : 3/7
c)-13/18 . 5/8 + -5/18 . 2/9 + -13/18 . 3/8 + -5/18 . 7/9
d) -11/19 . 4/9 + -8/19 . 3/7 + -11/19 . 5/9 + -9/19 . 4/7
a: \(\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)
\(=\left(-\dfrac{5}{6}+\dfrac{2}{5}\right)\cdot\dfrac{8}{3}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right)\cdot\dfrac{8}{3}\)
\(=\dfrac{8}{3}\left(-\dfrac{5}{6}+\dfrac{2}{5}+\dfrac{4}{5}-\dfrac{11}{30}\right)\)
\(=\dfrac{8}{3}\cdot\dfrac{-25+36-11}{30}\)
=0
b: \(\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-1}{4}\right):\dfrac{3}{7}\)
\(=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right)\cdot\dfrac{7}{3}+\left(\dfrac{3}{5}-\dfrac{1}{4}\right)\cdot\dfrac{7}{3}\)
\(=\dfrac{7}{3}\left(-\dfrac{3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)\)
\(=\dfrac{7}{3}\cdot0=0\)
c: \(\dfrac{-13}{18}\cdot\dfrac{5}{8}+\dfrac{-5}{18}\cdot\dfrac{2}{9}+\dfrac{-13}{18}\cdot\dfrac{3}{8}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\)
\(=\left(-\dfrac{13}{18}\cdot\dfrac{5}{8}+\dfrac{-13}{18}\cdot\dfrac{3}{8}\right)+\left(-\dfrac{5}{18}\cdot\dfrac{2}{9}+\dfrac{-5}{18}\cdot\dfrac{7}{9}\right)\)
\(=-\dfrac{13}{18}\left(\dfrac{5}{8}+\dfrac{3}{8}\right)+\dfrac{-5}{18}\left(\dfrac{2}{9}+\dfrac{7}{9}\right)\)
\(=-\dfrac{13}{18}-\dfrac{5}{18}=-\dfrac{18}{18}=-1\)
d: Sửa đề: \(\dfrac{-11}{19}\cdot\dfrac{4}{9}+\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-11}{19}\cdot\dfrac{5}{9}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\)
\(=\left(-\dfrac{11}{19}\cdot\dfrac{4}{9}+\dfrac{-11}{19}\cdot\dfrac{5}{9}\right)+\left(\dfrac{-8}{19}\cdot\dfrac{3}{7}+\dfrac{-8}{19}\cdot\dfrac{4}{7}\right)\)
\(=-\dfrac{11}{19}\left(\dfrac{4}{9}+\dfrac{5}{9}\right)+\dfrac{-8}{19}\left(\dfrac{3}{7}+\dfrac{4}{7}\right)\)
\(=-\dfrac{11}{19}-\dfrac{8}{19}=-\dfrac{19}{19}=-1\)
\(a.\left(-\dfrac{5}{6}+\dfrac{2}{5}\right):\dfrac{3}{8}+\left(\dfrac{4}{5}-\dfrac{11}{30}\right):\dfrac{3}{8}\)
\(=\left(-\dfrac{13}{30}\right):\dfrac{3}{8}+\dfrac{13}{30}:\dfrac{3}{8}\)
\(=\left[\left(-\dfrac{13}{30}+\dfrac{13}{30}\right)\right]:\dfrac{3}{8}\)
\(=0:\dfrac{3}{8}=0\)
\(b.\left(-\dfrac{3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+-\dfrac{1}{4}\right):\dfrac{3}{7}\)
\(=\left(-\dfrac{7}{20}\right):\dfrac{3}{7}+\dfrac{7}{20}:\dfrac{3}{7}\)
\(=\left[\left(-\dfrac{7}{20}+\dfrac{7}{20}\right)\right]:\dfrac{3}{7}=0:\dfrac{3}{7}=0\)
\(c.-\dfrac{13}{18}.\dfrac{5}{8}+-\dfrac{5}{18}.\dfrac{2}{9}+-\dfrac{13}{18}.\dfrac{3}{8}+-\dfrac{5}{18}.\dfrac{7}{9}\)
\(=\left(\dfrac{5}{8}+\dfrac{3}{8}\right).-\dfrac{13}{18}+\left(\dfrac{2}{9}+\dfrac{7}{9}\right).-\dfrac{5}{18}\)
\(=1.-\dfrac{13}{18}+1.-\dfrac{5}{18}=-\dfrac{13}{18}+-\dfrac{5}{18}=-1\)
\(d.-\dfrac{11}{19}.\dfrac{4}{9}+\dfrac{-8}{19}.\dfrac{3}{7}+-\dfrac{11}{19}.\dfrac{5}{9}+-\dfrac{9}{19}.\dfrac{4}{7}\)
\(=\left(\dfrac{4}{9}+\dfrac{5}{9}\right).-\dfrac{11}{19}+-\dfrac{24}{133}+-\dfrac{36}{133}\)
\(=-\dfrac{11}{19}+-\dfrac{60}{133}=-\dfrac{137}{133}\)
Thực hiện phép tính:
1, -3/4+ ( 3- 1/4 ) - ( 5/4- 9/2 )
2, -5/7. 13/19+ -5/7. 6/19+ 5/7
3, 2/5- 2/5. 8/3- 2/5. 5/8
1: \(=-\dfrac{3}{4}+3-\dfrac{1}{4}-\dfrac{5}{4}+\dfrac{9}{2}=-\dfrac{9}{4}+3+\dfrac{9}{2}=\dfrac{-9+12+18}{4}=\dfrac{21}{4}\)
2: \(=\dfrac{-5}{7}\left(\dfrac{13}{19}+\dfrac{6}{19}\right)+\dfrac{5}{7}=\dfrac{-5}{7}+\dfrac{5}{7}=0\)
3: \(=\dfrac{2}{5}\left(1-\dfrac{8}{3}-\dfrac{5}{8}\right)=\dfrac{2}{5}\cdot\dfrac{-55}{24}=\dfrac{-11}{12}\)
Thực hiện phép tính:
1, -3/4+ ( 3- 1/4 ) - ( 5/4- 9/2 )
2, -5/7. 13/19+ -5/7. 6/19+ 5/7
3, 2/5- 2/5. 8/3- 2/5. 5/8
Thực hiện phép tính:
1, -3/4+ ( 3- 1/4 ) - ( 5/4- 9/2 )
2, -5/7. 13/19+ -5/7. 6/19+ 5/7
3, 2/5- 2/5. 8/3- 2/5. 5/8
Tính hợp lí:
g) \(\dfrac{-3}{4}+\dfrac{2}{7}+\dfrac{-1}{4}+\dfrac{3}{5}+\dfrac{5}{7}\)
h) \(\dfrac{7}{19}.\dfrac{8}{11}+\dfrac{7}{19}.\dfrac{3}{11}-\dfrac{12}{19}\)
i) \(19\dfrac{5}{8}:\dfrac{7}{2013}-26\dfrac{5}{8}:\dfrac{7}{2013}\)
k) \(\dfrac{-5}{12}.\dfrac{2}{11}+\dfrac{-5}{12}.\dfrac{9}{11}+\dfrac{5}{12}\)
g: \(=\dfrac{-3}{4}-\dfrac{1}{4}+\dfrac{5}{7}+\dfrac{2}{7}+\dfrac{3}{5}=\dfrac{3}{5}\)
h: \(=\dfrac{7}{19}\left(\dfrac{8}{11}+\dfrac{3}{11}\right)-\dfrac{12}{19}=\dfrac{7}{19}-\dfrac{12}{19}=-\dfrac{5}{19}\)
i: \(=\dfrac{2013}{7}\left(19+\dfrac{5}{8}-26-\dfrac{5}{8}\right)=\dfrac{2013}{7}\cdot\left(-7\right)=-2013\)