The right triangle FGH has mid-segment : 10cm ; 24cm 26cm . What is the area of the right triangle FGH ?
The right triangle FGH has mid-segments of length 10cm, 24cm and 26cm. What is the area of triangle FGH?
Dễ lắm ak nha!
Giả sử FG = 10 cm ; GH = 24 cm ; FH = 26 cm
Ta có: FG2 + GH2 = 102 + 242 = 676 cm2
FH2 = 262 = 676 cm2
=> FG2 + GH2 = FH2 ( vì 676 = 676)
=> Tam giác FGH vuông tại G
=> \(S_{FGH}\) = 10 x 24 = 240 (cm2)
Vậy ......................
À đáp án là 480 cm mới đúng nha .
Mid-segments là đường trung bình mà .
Vì đường trung bình của tam giác lần lượt là 10cm ; 24cm ; 26cm =)) Các canh của tam giác lần lượt là 20cm ; 48cm ; 52cm
Ta thấy : 52^2 = 48^2 + 20^2
Nên tam giác FGH là tâm giác vuông
Diện tích tam giác FGH là :
(20*48):2=480(cm2)
The right triangle FGH has mid-segments of length 10 cm, 24cm and 26cm. What is the area of triangle FGH
The triangle ABC has \(AB=24cm\). If D is on the line segment AC such that \(\widehat{ABC}=\widehat{BDC}\)and \(AD=7cm;DC=9cm\)then what is the length of BD?
Note: You must write your answer in English.
vtui,yvtnytifn tfmt rtdnhx gh yhf g fgxh
We have \(\Delta CAB\sim\Delta CDB\left(g.g\right)\Rightarrow\dfrac{CB}{CD}=\dfrac{CA}{CB}\) \(\Rightarrow CB^2=CD\cdot CA\) We have \(CA=CD+DA=16\left(cm\right)\) \(\Rightarrow CB^2=9\cdot16=144\Rightarrow CB=12\left(cm\right)\) We have \(\dfrac{DB}{BA}=\dfrac{CB}{CA}=\dfrac{12}{16}=\dfrac{3}{4}\) \(\Rightarrow DB=\dfrac{3}{4}AB=18\left(cm\right)\)
Given a square with the length of one side is 8 cm and a isosceles triangle with the length of its base is 12 cm. If the area of the square is equal to the area of the isosceles triangle then what is the length of the height of the isosceles triangle, in cm?
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
I don't know English very much so i can't answere your question. Sory about that :(
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Mới học lớp 7 thôi, ko làm được bài nhưng để mk dịch đề thử nhá:
Cho tam giác ABC (A^= 90o), BD là tia phân giác của góc B (D thuộc AC). Nếu AD= 6cm, AB= 12cm thì diện tích của tam giác ABC là .....cm2.
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Dịch bài toán sau và giải :
"Give a right triangle ABC (Â=90) with B =40 and the line d is a the midperpendicular of the segment BC . Suppose that d AB = {E} , E of the segment BC . If BE=16 cm then the area of ABC is ... cm^2.
(round to three demical places in each step)
A . 256
B . 147,95
C . 128
D . 295,9
the area of an equilateral triangle is \(8\sqrt{12}cm^2\)
What is the perimeter of the triangle