a) 1024⁹=(2¹⁰)⁹=2⁹⁰

vì 2¹⁰⁰>2⁹⁰ nên 2¹⁰⁰>1024⁹

b)9¹²=(3²)¹²=3²⁴

   27⁷=(3³)⁷=3²¹

vì 3²⁴ > 3²¹ nên 9¹²>27⁷

c)125⁸⁰=(5³)⁸⁰=5²⁴⁰

   25¹¹⁸=(5²)¹¹⁸=5²³⁶

vì 5²⁴⁰>5²³⁶ nên 125⁸⁰>25¹¹⁸

d)1000²⁰=(10³)²⁰=10⁶⁰

vì 10³⁰<10⁶⁰ nên 10³⁰<1000²⁰

e)107⁵⁰=(107²)²⁵=11449²⁵

   73⁷⁵=(73³)²⁵=389017²⁵

vì 11449²⁵<389017²⁵ nên 107⁵⁰<73⁷⁵

http://dethi.violet.vn/present/showprint/entry_id/11136600

bạn muốn học tiếng anh thi bn có thể thông qua ứng dụng từ điển TFAT trên google hoặc appstron nhé

27/92 < 26/75

5^18  

5^16

=> >

Trả lời

125⁶ > 25⁸

3⁵⁰ > 2⁷⁵

Học tốt nha !

trả lời 

\(125^6>25^8\)

\(3^{50}>2^{75}\)

hc tốt

36²⁵ =6⁵⁰=7776¹⁰< 78125¹⁰=(5⁷)¹⁰=5⁷⁰<5⁷² =25³⁶

lấy 1 trừ đi p/s nhé 

a/ \(2^{100}=\left(2^3\right)^{100}=8^{100}>8^{30}\)

b/ \(3^{75}=\left(3^3\right)^{25}=27^{25}\)

\(4^{50}=\left(4^2\right)^{25}=16^{25}\)

\(\Rightarrow3^{75}>4^{50}\)

c/ \(9^{199}=\left(3^2\right)^{199}=3^{398}\)

\(27^{121}=\left(3^3\right)^{121}=3^{363}\)

\(\Rightarrow9^{199}>27^{121}\)

d/ \(26^{38}>16^{38}=\left(2^4\right)^{38}=2^{152}\)

\(64^{25}=\left(2^6\right)^{25}=2^{150}\)

\(\Rightarrow26^{38}>64^{25}\)

Bài 1:

a: \(10^{10}=\left(2\cdot5\right)^{10}=2^{10}\cdot5^{10}=2^9\cdot5^{10}\cdot2\)

\(48\cdot50^5=2^4\cdot3\cdot\left(2\cdot5^2\right)^5=2^4\cdot3\cdot2^5\cdot5^{10}=2^9\cdot5^{10}\cdot3\)

mà 2<3

nên \(10^{10}<48\cdot50^5\)

b: \(1990^{10}+1990^9=1990^9\left(1990+1\right)=1990^9\cdot1991\)

\(1991^{10}=1991^9\cdot1991\)

mà 1990<1991

nên \(1990^{10}+1990^9<1991^{10}\)

c: \(107^{50}<108^{50}=\left(2^2\cdot3^3\right)^{50}=2^{100}\cdot3^{150}\)

\(73^{75}>72^{75}=\left(2^3\cdot3^2\right)^{75}=2^{225}\cdot3^{150}\)

mà \(2^{225}\cdot3^{150}>2^{100}\cdot3^{150}=108^{50}>107^{50}\)

nên \(73^{75}>107^{50}\)

d: \(2^{91}=\left(2^{13}\right)^7=8192^7\)

\(5^{35}=\left(5^5\right)^7=3125^7\)

mà 8192>3125

nên \(2^{91}>5^{35}\)

e: \(A=72^{45}-72^{44}=72^{44}\left(72-1\right)=72^{44}\cdot71\)

\(B=72^{44}-72^{43}=72^{43}\left(72-1\right)=72^{43}\cdot71\)

mà 44>43

nên A>B

Bài 2:

a:

ĐKXĐ: x<>2023

\(\frac{x-2023}{4}=\frac{1}{x-2023}\)

=>\(\left(x-2023\right)\left(x-2023\right)=4\cdot1\)

=>\(\left(x-2023\right)^2=4\)

=>\(\left[\begin{array}{l}x-2023=2\\ x-2023=-2\end{array}\right.\Rightarrow\left[\begin{array}{l}x=2+2023=2025\left(nhận\right)\\ x=-2+2023=2021\left(nhận\right)\end{array}\right.\)

b: \(\left(2x+1\right)^4=\left(2x+1\right)^6\)

=>\(\left(2x+1\right)^6-\left(2x+1\right)^4=0\)

=>\(\left(2x+1\right)^4\cdot\left\lbrack\left(2x+1\right)^2-1\right\rbrack=0\)

=>\(\left(2x+1\right)^4\cdot\left(2x+1-1\right)\left(2x+1+1\right)=0\)

=>\(2x\left(2x+1\right)^4\cdot\left(2x+2\right)=0\)

=>\(\left[\begin{array}{l}2x=0\\ 2x+1=0\\ 2x+2=0\end{array}\right.\Rightarrow\left[\begin{array}{l}x=0\\ x=-\frac12\\ x=-1\end{array}\right.\)

c: \(\left(3x-1\right)^{10}=\left(3x-1\right)^{20}\)

=>\(\left(3x-1\right)^{20}-\left(3x-1\right)^{10}=0\)

=>\(\left(3x-1\right)^{10}\cdot\left\lbrack\left(3x-1\right)^{10}-1\right\rbrack=0\)

=>\(\left[\begin{array}{l}\left(3x-1\right)^{10}=0\\ \left(3x-1\right)^{10}-1=0\end{array}\right.\Rightarrow\left[\begin{array}{l}3x-1=0\\ \left(3x-1\right)^{10}=1\end{array}\right.\)

=>\(\left[\begin{array}{l}3x-1=0\\ 3x-1=1\\ 3x-1=-1\end{array}\right.\Rightarrow\left[\begin{array}{l}x=\frac13\\ x=\frac23\\ x=0\end{array}\right.\)

d: Sửa đề \(2^{x+1}\cdot3^{y}=12^{x}\)

=>\(2^{x+1}\cdot3^{y}=\left(2^2\cdot3\right)^{x}=2^{2x}\cdot3^{x}\)

=>\(\begin{cases}2x=x+1\\ y=x\end{cases}\Rightarrow\begin{cases}x=1\\ y=x=1\end{cases}\)

\(\dfrac{5}{9}-\dfrac{1}{4}=\dfrac{20}{36}-\dfrac{9}{36}=\dfrac{11}{36}\)

\(\dfrac{49}{50}-\dfrac{4}{25}=\dfrac{49}{50}-\dfrac{8}{50}=\dfrac{41}{50}\)

help help !!

11/36

41/50