Tính.
1, ( 1 + \(\frac{2}{3}\)- \(\frac{1}{4}\)) . ( 0,8 - \(\frac{3}{4}\))2
2, \(\left(\frac{1}{3}\right)^{50}\). 925 - \(\frac{2}{3}\): 4
3. \(\frac{2^4.2^6}{\left(2^5\right)^2}\)- \(\frac{2^5.15^3}{6^3.10^2}\)
Thực hiện phép tính:
a) \(\left(\frac{1}{3}\right)^{50}.\left(-9\right)^{25}.\frac{2}{3}:4\)
b) \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
a) (1/3)50 . (-9)25 .2/3:4
= (1/3)50 . [-(3)50] . 2/3 . 1/4
= - (1/3.3)50 . 1/6
= -1 . 1/6 = -1/6
b) (24.26)/(25)2 - (25.153)/(63.102)
= 210/210 - (25.33.53)/(23.33.22.52)
= 1- (25.33.53)/(25.33.52)
= 1- 5
= -4
Thực hiện phép tính:
a) A=\(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}\) b)B=\(\left(-\frac{2}{3}+1\right)-\left(\frac{7}{5}-0,2\right)+\left(\frac{7}{15}-1+\frac{4}{3}\right)\)
c) C=\(\frac{^{^{2^4.2^6}}}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
Thực hiện phép tính (Tính hợp lý nếu có thể)
g) \(\frac{3}{5}:\left(\frac{-1}{15}-\frac{1}{6}\right)+\frac{3}{5}:\left(\frac{-1}{3}-1\frac{1}{15}\right)\)
h) \(10.\sqrt{0,01}.\sqrt{\frac{16}{9}+3\sqrt{49}-\frac{1}{6}\sqrt{4}}\)
i) \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
k) \((2\frac{1}{3}+3\frac{1}{2}):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7\frac{1}{2}\)
n) \(4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):\frac{-27}{8}\)
m) \([1,5+2\frac{1}{2}-\left(2\sqrt{2}\right)^2]:[4\frac{1}{2}-\sqrt{1,96}+0,9]\)
o) \(\frac{5}{21}.\left(4\frac{1}{5}.7\frac{3}{4}+5\frac{1}{4}.4,2\right)\)
p) \(\left(\frac{2}{5}+\frac{2}{7}-\frac{2}{11}\right):\left(\frac{3}{7}-\frac{3}{11}+\frac{3}{5}\right)\)
Làm nhanh làm đúng mình Tick nha :))
TÍNH:
a)\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
b)\(\frac{1}{2}.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0\)
Bài 1:Thực hiện phép tính:
1,\(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
2,\(-12:(\frac{3}{4}-\frac{5}{6})^2\)
3,\(\frac{7}{23}.[(-\begin{matrix}8\\6\end{matrix})-\frac{45}{18}]\)
4,\(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
5,\((1+\frac{2}{3}-\frac{1}{4})(0,8-\frac{3}{4})^2\)
6,\(16\frac{2}{7}:(\frac{-3}{5})+28\frac{2}{7}:\frac{3}{5}\)
7,\((2^2:\frac{4}{3}-\frac{1}{2}).\frac{6}{5}-17\)
8,\((\frac{1}{3})^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)
9,\(\frac{3}{5}:(\frac{-1}{15}-\frac{1}{6})+\frac{3}{5}:(\frac{-1}{3}-1\frac{1}{15})\)
10,\(\left(-6,5\right).5,7+5,7.\left(-3,5\right)\)
11,\(10.\sqrt{0,01.\frac{16}{9}+3\sqrt{49}-\frac{1}{6}\sqrt{ }4}\)
12,\(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}\)
Tính
a) \(\left( {\frac{4}{5} - 1} \right):\frac{3}{5} - \frac{2}{3}.0,5\)
b) \(1 - {\left( {\frac{5}{9} - \frac{2}{3}} \right)^2}:\frac{4}{{27}}\)
c)\(\left[ {\left( {\frac{3}{8} - \frac{5}{{12}}} \right).6 + \frac{1}{3}} \right].4\)
d) \(0,8:\left\{ {0,2 - 7.\left[ {\frac{1}{6} + \left( {\frac{5}{{21}} - \frac{5}{{14}}} \right)} \right]} \right\}\)
a)
\(\begin{array}{l}\frac{1}{9} - 0,3.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{10}}.\frac{5}{9} + \frac{1}{3}\\ = \frac{1}{9} - \frac{3}{{2.5}}.\frac{5}{{3.3}} + \frac{1}{3}\\ = \frac{1}{9} - \frac{1}{6} + \frac{1}{3}\\ = \frac{2}{{18}} - \frac{3}{{18}} + \frac{6}{{18}}\\ = \frac{5}{{18}}\end{array}\)
b)
\(\begin{array}{l}{\left( {\frac{{ - 2}}{3}} \right)^2} + \frac{1}{6} - {\left( { - 0,5} \right)^3}\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{2}} \right)^3\\ = \frac{4}{9} + \frac{1}{6} - \left( {\frac{{ - 1}}{8}} \right)\\ = \frac{4}{9} + \frac{1}{6} + \frac{1}{8}\\ = \frac{{32}}{{72}} + \frac{{12}}{{72}} + \frac{9}{{72}}\\ = \frac{{53}}{{72}}\end{array}\)
a)\(\frac{2^7.9^3}{6^5.8^2}\); \(\frac{6^3+3.6^2+3^3}{-13}\)
b)\(\left(\frac{3}{7}+\frac{1}{2}\right)^2\); \(\left(\frac{3}{4}-\frac{5}{6}\right)^2\); \(\left(-\frac{10}{3}\right)^5.\left(-\frac{6}{5}\right)^4\)
c)\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(\frac{4}{5}-\frac{3}{4}\right)^2\); \(2:\left(\frac{1}{2}-\frac{2}{3}\right)^3\); \(9.9.\left(-\frac{1}{3}\right)^3+\frac{1}{3}\); \(\left(4.2^5\right):\left(2^3.\frac{1}{16}\right)\)
Bài 1 : Tính toán
a. \(\left(-\frac{2}{3}\right)^4\): 24 d. \(\frac{3^3-\left(0,9\right)^5}{\left(2,7\right)^4}\)
b. \(\left(\frac{3}{4}\right)^3\). \(4^4\)
c. \(\frac{3.\left(0,8\right)^5}{\left(2,4\right)^4}\)
e. \(\left(\frac{-7}{2^{ }}\right)^2\)+ \(\left(\frac{-3}{4}\right)^3.64\)-\(\left(\frac{-61}{5}\right)\)
f. \(\frac{2^4.2^6}{\left(2^5\right)^2}\)- \(\frac{2^5.15^3}{6^3.10^2}\)
a/ \(\left(\frac{-2}{3}\right)^4:24=\frac{16}{81}:24=\frac{2}{243}\)
b/ \(\left(\frac{3}{4}\right)^3.4^4=\frac{27}{64}.256=108\)
c/ \(\frac{3.0,8^5}{2,4^4}=\frac{3.0,32768}{33,1776}=\frac{0,98304}{33,1776}=\frac{4}{135}\)
d/ \(\frac{3^3-0,9^5}{2,7^4}=\frac{27-0,59049}{53,1441}=\frac{26,40951}{53,1441}=0,4969415231\)
e/\(\left(\frac{-7}{2}\right)^2+\left(\frac{-3}{4}\right)^3.64-\left(\frac{-61}{5}\right)\)
\(=\frac{49}{4}+\frac{-27}{64}.64+\frac{61}{5}\)
\(=12,25-27+12,2\)
\(=-2,55\)
f/ \(\frac{2^4.2^6}{\left(2^5\right)^2}-\frac{2^5.15^3}{6^3.10^2}=\frac{2^{10}}{2^{10}}-\frac{2^5.5^3.3^3}{2^3.3^3.5^2.2^2}\)
\(=1-\frac{2^5.5^3.3^3}{2^5.3^3.5^2}=1-\frac{5}{1}=-4\)
\(\)
chúc bạn học tốt
Thực hiện phép tính (hợp lí nếu có thể):
\(1,\frac{-1}{3}-\frac{-3}{5}-\frac{1}{6}+\frac{1}{43}-\frac{-3}{7}+\frac{-1}{2}-\frac{1}{35}\\ \\ 2,\left(-\frac{1}{3}+\frac{7}{13}\right)-\left(\frac{-16}{24}+\frac{6}{26}+\frac{9}{13}\right)\)\(3,\frac{-7}{3}-\left[\frac{2}{5}-\left(\frac{1}{3}+\frac{-5}{25}\right)\right]\\ 4,\left(2\frac{1}{4}-3\frac{1}{5}\right)-\left[\frac{-3}{4}+\left(\frac{4}{5}-2019\right)\right]\)