khó quá , không biết làm

\(3x^n\left(6x^{n-3}+1\right)-2n^x\left(9x^{n-3}-1\right)=\) \(18x^{2n-3}+3x^n-\)

ở chỗ -2n^x(9x^n-3-1) đề đúng ko vậy?

đề đúng 

a: \(=\dfrac{3}{4}\cdot\dfrac{4}{5}\cdot\dfrac{5}{6}\cdot x^{n-1+2n+1+1}\cdot y^{2n+1+n+1}=\dfrac{1}{2}x^{3n+1}y^{3n+2}\)

Hệ số: 1/2

Bậc: 6n+3

b: \(=\dfrac{6}{5}\cdot\dfrac{4}{2}\cdot\dfrac{2}{6}\cdot x^{3-n+4-n}\cdot y^{5-n+6-n}=\dfrac{4}{5}x^{7-2n}y^{11-2n}\)

Hệ số: 4/5

bậc: 18-4n

c: \(=\dfrac{4}{7}x^{2-n+2n-3+1}y^{1+n-1+1}=\dfrac{4}{7}x^{n-1}y^{n+1}\)

Hệ số: 4/7

Bậc: 2n

d: =4/7x^(2n+2)*y^(2n+2)

Hệ số: 4/7

Bậc: 4n+4

a) \(15x^ny^{2n}-3x^{n+1}\left(-y\right)^{2n}\)

\(=x^ny^{2n}\left(15-3x\right)\)

\(=3x^ny^{2n}\left(5-x\right)\)

b) \(4x^{2n}y^{n-1}+2\left(-x\right)^{2n+1}y^n\)

\(=4x^{2n}y^{n-1}-2x^{2n+1}y^n\)

\(=2x^{2n}y^{n-1}\left(2-xy\right)\)

thi violimpic đúng không

a) xⁿ + xⁿ = 2xⁿ

b) x²ⁿ + (-x)²ⁿ = x²ⁿ + x²ⁿ = 2x²ⁿ

c) x^{2n + 1} + (-x)^{2n + 1} = x^{2n + 1} - x^{2n + 1} = 0

\(\left(x^{2n}+x^ny^n+y^{2n}\right)\left(x^{3n}+y^{3n}\right)\)

\(=x^{5n}+x^{2n}y^{3n}+x^{4n}y^n+x^ny^{4n}+x^{3n}y^{2n}+y^{5n}\)