a) 40 và 24

Ta có: 40 = 2³ . 5

          24 = 2³ . 3

=> ƯCLN(40; 24) = 2³ = 8

=> ƯC(40; 24) \(\in\) Ư(8)

=> ƯC(40; 24) \(\in\) Ư(8) = { 1; 2; 4; 8 }

   Các câu còn lại tương tự nha bạn

ƯCLN(24,40)=8

=>ƯC(24,40)=Ư(8)=(1,2,4,8)

các cau khac tuong tu nhe ban

tìm ƯC(24, 40)

3:

a: \(40=2^3\cdot5;24=2^3\cdot3\)

=>\(ƯCLN\left(40;24\right)=2^3=8\)

=>\(ƯC\left(40;24\right)=Ư\left(8\right)=\left\{1;-1;2;-2;4;-4;8;-8\right\}\)

b: \(12=2^2\cdot3;52=2^2\cdot13\)

=>\(ƯCLN\left(12;52\right)=2^2=4\)

=>\(ƯC\left(12;52\right)=\left\{1;-1;2;-2;4;-4\right\}\)

c: \(36=2^2\cdot3^2;990=2\cdot3^2\cdot5\cdot11\)

=>\(ƯCLN\left(36;990\right)=3^2\cdot2=18\)

=>\(ƯC\left(36;990\right)=\left\{1;-1;2;-2;3;-3;6;-6;9;-9;18;-18\right\}\)

2:

a: \(12=2^2\cdot3;18=3^2\cdot2\)

=>\(ƯCLN\left(12;18\right)=2\cdot3=6\)

b: \(12=2^2\cdot3;10=2\cdot5\)

=>\(ƯCLN\left(12;10\right)=2\)

c: \(24=2^3\cdot3;48=2^4\cdot3\)

=>\(ƯCLN\left(24;48\right)=2^3\cdot3=24\)

d: \(300=2^2\cdot3\cdot5^2;280=2^3\cdot5\cdot7\)

=>\(ƯCLN\left(300;280\right)=2^2\cdot5=20\)

g) Ta có: 54 = 2 . 3³

            36 = 2².3²

=>ƯCLN(54; 36) = 2.3² = 18

=> ƯC(54;36) = Ư(18) = {1; 2; 3; 6; 9; 18}

j) Ta có: 9 = 3²

          18 = 2.3²

        72 = 2³ . 3²

=> ƯCLN(9; 18; 72) = 3² = 9

=> ƯC(9; 18; 72) = Ư(9) = {1; 3; 9}

h) Ta có: 10 = 2.5

          20 = 2² . 5

        60 = 2² . 3.5

=> ƯCLN(10; 20; 60) = 2.5 = 10

=> ƯC(10; 20; 60) = Ư(10) = {1; 2; 5; 10}

g) Ta có : 54 = 2.3³

             36 = 2².3²

=> ƯCLN ( 54; 36 ) = 2.3² = 18

=> ƯC ( 54;36 ) = Ư(18) = ( 1; 2; 3; 6; 9; 18 )

j) Ta có : 9 = 3²

18 = 2.3²

72 = 2³.3²

=> ƯCLN ( 9; 18; 72 ) = 3² = 9

h) Ta có : 10 = 2.5

20 = 2².5

60 = 2².3.5

=> ƯCLN ( 10; 20; 60 ) = 2.5 = 10

=> ƯC ( 10; 20; 60 ) = Ư ( 10 ) - { 1; 2; 5; 10 }

a= 4

b = 4

c= 6

d=6

tick đuê!!!!

câu b,c bài này thì sao

a) Ta có :

40 = 2³ . 5

24 = 2³ . 3

=> ƯCLN ( 40 ; 24 ) = 2³ = 8

=> ƯC ( 40 ; 24 ) = Ư ( 8 ) = { 1 ; 2 ; 4 ; 8 }

b) Ta có :

12 = 2² . 3

52 = 2² . 13

=> ƯCLN ( 12 ; 52 ) = 2² = 4

=> ƯCLN ( 12 ; 52 ) = Ư ( 4 ) = { 1 ; 2 ; 4 }

c) Ta có :

36 = 2² . 3²

990 = 2 . 3² . 5 . 11

=> ƯCLN ( 36 ; 990 ) = 2 . 3² = 18

=> ƯC ( 36 ; 990 ) = Ư ( 18 ) = { 1 ; 2 ; 3 ; 6 ; 9 ; 18 }

d) Ta có :

54 = 2 . 3³

36 = 2² . 3²

=> ƯCLN ( 54 ; 36 ) = 2² . 3³ = 18

=> ƯC ( 54 ; 36 ) = Ư ( 18 ) = { 1 ; 2 ; 3 ; 6 ; 9 ; 18 }

a)40 và 24

ta có:

40=2^3*5

24=2^3*3

=> ƯCLN(40;24) =2^3=8

=>ƯC(40;24)=Ư(8)={1;2;4;8}

những câu còn lại tương tự bn nhé

a: ƯCLN(40;24)=8

ƯC(40;24)=Ư(8)={1;2;4;8}

b: UCLN(80;144)=16

UCLN(80;144)={1;2;4;8;16}

c: UCLN(9;18;72)=9

ƯC(9;18;72)={1;3;9}

d: ƯCLN(25;55;75)=5

ƯC(25;55;75)={1;5}

\(a,40=2^3.5\\ 24=2^3.3\\ \Rightarrow UCLN_{\left(24;40\right)}=2^3=8\\ \RightarrowƯC_{\left(40;24\right)}=Ư_{\left(8\right)}=\left\{1;2;4;8\right\}\\ b,80=2^4.5\\ 144=2^4.3^2\\ \Rightarrow UCLN_{\left(80;144\right)}=2^4=16\\ \RightarrowƯC_{\left(80;144\right)}=Ư_{\left(16\right)}=\left\{1;2;4;8;16\right\}\\ c,9=3^2\\ 18=2.3^2\\ 72=3^2.2^3\\ \Rightarrow UCLN_{\left(8;18;72\right)}=3^2=9\\ \RightarrowƯC_{\left(9;18;72\right)}=Ư_{\left(9\right)}=\left\{1;3;9\right\}\\ d,25=5^2\\ 55=5.11\\ 75=5^2.3\\ \Rightarrow UCLN_{\left(25;55;75\right)}=5\\ \RightarrowƯC_{\left(25;55;75\right)}=Ư_{\left(5\right)}=\left\{1;5\right\}\)

\(a,ƯC\left(40,24\right)=Ư\left(8\right)=\left\{...\right\}\\ b,ƯC\left(12,52\right)=Ư\left(4\right)=\left\{...\right\}\\ c,ƯC\left(36,990\right)=Ư\left(18\right)=\left\{...\right\}\\ d,ƯC\left(54,36\right)=Ư\left(9\right)=\left\{...\right\}\\ e,ƯC\left(10,20,70\right)=Ư\left(10\right)=\left\{...\right\}\\ f,ƯC\left(25,55,75\right)=Ư\left(5\right)=\left\{...\right\}\\ g,ƯC\left(80,144\right)=Ư\left(16\right)=\left\{...\right\}\\ h,ƯC\left(63,2970\right)=Ư\left(9\right)=\left\{...\right\}\\ i,ƯC\left(65,125\right)=Ư\left(5\right)=\left\{...\right\}\\ j,ƯC\left(9,18,72\right)=Ư\left(9\right)=\left\{...\right\}\\ k,ƯC\left(24,36,60\right)=Ư\left(12\right)=\left\{...\right\}\\ l,ƯC\left(16,42,86\right)=Ư\left(2\right)=\left\{..\right\}\)

a:UC(40;24)=Ư(8)

b: UC(12;52)=Ư(4)

TL :

\(40=2^3.5.\)

\(24=2^2.3.2\)

UCLN (40;24) = \(2^3=8\)

BC (8) = \(\left\{1;8;16;24;32;40.....\right\}\)

b) \(48=2^4.3\)

\(120=2^3.5\)

UCLN (48;120 ) = \(2^2.3=12\)