a: \(100+98+96+...+2-97-95-...-1\)

\(=100+\left(98-97\right)+\left(96-95\right)+...+\left(2-1\right)\)

\(=100+1+...+1\)

\(=100+49=149\)

b: \(1+2-3-4+5+6-7-8+9+10-11-12+...+...-299-300+301+302\)

\(=\left(1+2-3-4\right)+\left(5+6-7-8\right)+...+\left(297+298-299-300\right)+603\)

\(=603+\left(-4\right)+\left(-4\right)+...+\left(-4\right)\)

\(=603-4\cdot75=603-300=303\)

ta có : x+3/5+x+4/5=x+5/3+x+6/2

   => (x+x)+(3/5+4/4)=(x+x)+(5/3+6/2)

   => 2x+8/5=2x+14/3  ( vô lí ) 

Ta có: \(x+\frac{3}{5}+x+\frac{4}{4}=x+\frac{5}{3}+x+\frac{6}{2}\)

=> \(x+\frac{3}{5}+x+1=x+\frac{5}{3}+x+3\)

=> \(x+1+x+3=x+\frac{5}{3}-x-\frac{3}{5}\)

=> \(2x+4=\frac{25-9}{15}\)

=> \(2x+4=\frac{16}{15}\)

=> \(2x+4=1+\frac{1}{15}\)

=> \(2x+4-1=\frac{1}{15}\)

=> \(2x+3=\frac{1}{15}\)

=> \(2x=\frac{1}{15}-3\)

=> \(2x=\frac{1-45}{15}\)

=> \(2x=-\frac{44}{15}\)

=> \(x=\frac{\left(-\frac{44}{15}\right)}{2}\)

=> \(x=-\frac{44}{15}.\frac{1}{2}\)

=> \(x=-\frac{22}{15}\)

Cách đây 5 năm , tuổi mẹ gấp 5 lần tuổi con . Tính tuổi mẹ và tuổi con hiện nay , biết rằng tổng số tuổi mẹ và tuổi con hiện nay là 46 tuổi

\(\frac{3}{5}+\frac{5}{1}+\frac{7}{13}+\frac{2}{5}+\frac{16}{11}+\frac{19}{13}\)

\(\left(\frac{3}{5}+\frac{2}{5}\right)+\left(\frac{5}{11}+\frac{16}{11}\right)+\left(\frac{7}{13}+\frac{19}{13}\right)\)

\(=1+\frac{21}{11}+\frac{26}{13}\)

\(=1+\frac{273}{143}+\frac{286}{143}\)

\(=\frac{54}{11}\)

ai cứu với ạ

ko 

có chết đâu mà phải cứu

a) 1/2x(3/4+2/5)                               

1/2x23/20                                         

23/40                                               

b) 3/4:(8/9+16/3)

3/4:56/9

27/224

c) 1/5:1/10-1/3

2-1/3

5/3

d) 3/4x(20/9-8/15)

3/4x76/45

19/15

e) 1/7:5/14-3/2

=2/5-3/2

-11/10 ( Chị nghĩ lớp 4 chưa học đến số âm nên em xem lại đề nhé)

g) 3/2x(11/6-5/12)

3/2x17/12

17/8

a)\(\frac{1}{2}x\left(\frac{3}{4}+\frac{2}{5}\right)\)

\(=\frac{1}{2}x\left(\frac{15}{20}+\frac{8}{20}\right)\)

\(=\frac{1}{2}x\frac{23}{20}\)

\(=\frac{23}{40}\)

b)\(\frac{3}{4}:\left(\frac{8}{9}+\frac{16}{3}\right)\)

\(=\frac{3}{4}:\left(\frac{8}{9}+\frac{48}{9}\right)\)

\(=\frac{3}{4}:\frac{56}{9}\)

\(=\frac{3}{4}x\frac{9}{56}\)

\(=\frac{27}{224}\)

c) \(\frac{1}{5}:\frac{1}{10}-\frac{1}{3}\)

\(=\frac{1}{5}x10-\frac{1}{3}\)

\(=2-\frac{1}{3}\)

\(=\frac{6}{3}-\frac{1}{3}=\frac{5}{3}\)

d) \(\frac{3}{4}x\left(\frac{20}{9}-\frac{8}{15}\right)\)

\(=\frac{3}{4}x\left(\frac{100}{45}-\frac{24}{45}\right)\)

\(=\frac{3}{4}x\frac{76}{45}\)

\(=\frac{19}{5}\)

e) \(\frac{1}{7}:\frac{5}{14}-\frac{3}{2}\)

\(=\frac{1}{7}x\frac{14}{5}-\frac{3}{2}\)

\(=\frac{2}{5}-\frac{3}{2}\)

\(=\frac{4}{10}-\frac{15}{10}\)

\(=\frac{-11}{10}\)

g) \(\frac{3}{2}x\left(\frac{11}{6}-\frac{5}{12}\right)\)

\(=\frac{3}{2}x\left(\frac{22}{12}-\frac{5}{12}\right)\)

\(=\frac{3}{2}x\frac{17}{12}\)

=\(=\frac{17}{8}\)

\(\frac{5}{6}+\frac{1}{12}+\frac{2}{3}+\frac{2}{7}+\frac{1}{25}+\frac{1}{4}-\frac{5}{42}\)

\(=\left(\frac{5}{6}+\frac{2}{7}-\frac{5}{42}\right)+\left(\frac{1}{12}+\frac{2}{3}+\frac{1}{4}\right)+\frac{1}{25}\)

\(=\left(\frac{35}{42}+\frac{12}{42}-\frac{5}{42}\right)+\left(\frac{1}{12}+\frac{8}{12}+\frac{3}{12}\right)+\frac{1}{25}\)

\(=\frac{42}{42}+\frac{12}{12}+\frac{1}{25}=1+1+\frac{1}{25}=2\frac{1}{25}\)

51/25