cho bieu thuc p=(2007- 2005) + (2003-2001)+...+( 7-5) + (3-1).ket qua gia tri cua p la bao nhieu
tinh gia tri cua bieu thuc :
a] (18 1/2 + 5 3/8 - 7 5/24) : 16 2/3
b] 2005 x 2007 -1 / 2004 + 2005 x 2006
a) chắc bạn cũng biết
b) \(\frac{2005.2007-1}{2004+2005.2006}=\frac{2005.\left(2006+1\right)-1}{2004+2005.2006}=\frac{2005.2006+2005.1-1}{2004+2005.2006}=\frac{2005.2006+2004}{2004+2005.2006}=1\)
Cho bieu thuc: A= 2,25 ×( a-12,5)+4,35
a) Tim gia tri cua bieu thuc A khi a= 112,5
b) Tin gia tri cua a de bieu thuc A co gia tri be nhat, gia tri be nhat la bao nhieu?
A = 2,25 x ( 112,5 -12,5 ) + 4,35
= 2,25 x 100 + 4,35
= 225 + 4,35
= 229,35
CHO bieu thuc
B=17,58*43+57*17,58/293*A
a)tim gia tri cua bieu thuc Bkhi a=2
b)tinh gia tri a khi B=2
c)tim gia tri so tu nhien ad biet bieu thuc B co gia tri lon nhat ,gia tri lon do la bao nhieu
bai 1
cho bieu thuc A = 5/n+1 voi N THUOC Z
a, de A la phan so thi n co dieu kien gi ?
b , tim tat ca cac gia tri nguyen cua n de gia tri A la 1 so nguyen ?
bai 2
cho bieu thuc M = 6/n-3 voi n thuoc Z .Co bao nhieu gia tri cua n de :
a, M ko phai la phan so
b , M la phan so va cp gia tri nguyen ?
bai 3 viet tap hop cacs so nguyen sao cho :
-12/4 < x <6/3
Bài 1:
a: Để A là phân số thì n+1<>0
hay n<>-1
b: Để A là số nguyên thì \(n+1\in\left\{1;-1;5;-5\right\}\)
hay \(n\in\left\{0;-2;4;-6\right\}\)
1. cho x+y=7 va xy=8 gia tri cua bieu thuc x3+y3 = ?
2. gia tri lon nhat cua bieu thuc B= 1+3x-x2 la ?
1. cho x+y=7 va xy=8 gia tri cua bieu thuc x3+y3 = ?
2. gia tri lon nhat cua bieu thuc B= 1+3x-x2 la ?
tinh gia tri cua bieu thuc B={1(1/5).[4.(3+1/3-3/7-3/53)]/[3+1/3-3/7-3/53]}:{[4+4/17+4/19+4/2003]/5+5/17+519+5/2003]}
Cho bieu thuc 125 + a x b, neu a = 5 thi b bang bao nhieu de bieu thuc tren co gia tri la 1000 ?
Cho bieu thuc 125 + a x b, neu a = 5 thi b bang bao nhieu de bieu thuc tren co gia tri la 1000 ?
Ta có: 125+ab
=> 125+5b=1000
=>5b=1000-125
=>5b=875
=>b=875:5
=>b=175
mk nha :)
ta có: 125+ab
=> 125+5b=1000
=>5b=875
=>b=175
bai2: tinh gia tri cua bieu thuc: 5/6+1/3*2 bang bao nhieu
giup minh voi
`5/6 + 1/3 xx 2`
`= 5/6 + 2/3`
`= 5/6 + 4/6`
`=9/6`
`=3/2`