a) 6/7 = 120/ 140

Vì 120/140 < 120/137 nên 6/7 < 120/137

b)18/75 = 6/25 ; 28/112 = 1/4

Vì 6/25 : 1/4 = 24/25 nên 18/75 < 28/112

c)Ta có: 1 - 17/20 = 3/20  ;     1 - 22/25 = 3/25

Vì 3/20 > 3/25 nên 17/20 < 22/25

mik nha

bài này cũng phải đăng đúng là loại chó có khác

a)

\(\frac{64}{85}< \frac{64}{81}< \frac{73}{81}\)

=>\(\frac{64}{85}< \frac{73}{81}\)

b)

\(\frac{25}{26}=\frac{25.1010}{26.1010}=\frac{25250}{26260}\)

Ta có: \(1-\frac{25250}{26260}=\frac{1010}{26260}\)

         \(1-\frac{25251}{26261}=\frac{1010}{26261}\)

Vì \(\frac{1010}{26260}>\frac{1010}{26261}\) nên \(\frac{25}{26}< \frac{25251}{26261}\)

a)\(\frac{64}{85}\)<\(\frac{64}{81}\)<\(\frac{73}{81}\)

b)\(\frac{25}{26}\)=\(\frac{25250}{26260}\)=\(1\)- \(\frac{1010}{26260}\)< \(1\)- \(\frac{1010}{26261}\)= \(\frac{25251}{26261}\)

Cần nhớ:

\(\frac{a}{b}< 1\Rightarrow\frac{a}{b}< \frac{a+n}{b+n}\left(n\inℕ^∗\right)\)

\(\frac{a}{b}>1\Rightarrow\frac{a}{b}>\frac{a+n}{b+n}\left(n\inℕ^∗\right)\)

Ta thấy:

\(\frac{19}{29}< 1\Rightarrow\frac{19}{29}< \frac{19+1}{29+1}=\frac{20}{30}=\frac{2}{3}\)

Ta lại có:

\(\frac{2}{3}=\frac{2.7}{3.7}=\frac{14}{21}< 1\Rightarrow\frac{14}{21}< \frac{14+6}{21+6}=\frac{20}{27}=\frac{20.3}{27.3}=\frac{60}{81}\)

\(\Rightarrow\frac{19}{29}< \frac{60}{81}\)     (1)

Ta có:

\(\frac{60}{81}=\frac{20}{27}< 1\Rightarrow\frac{20}{27}< \frac{20+1}{27+1}=\frac{21}{28}< \frac{21}{25}\)

=>\(\frac{60}{81}< \frac{21}{25}\)     (2)

Từ (1) và (2) => \(\frac{19}{29}< \frac{60}{81}< \frac{21}{25}\)

\(\frac{21}{25}=\frac{49329}{58725}\)

\(\frac{60}{81}=\frac{43500}{58725}\)

\(\frac{19}{29}=\frac{38475}{58725}\)

\(\)vì \(\frac{49329}{58725}>\frac{43500}{58725}>\frac{38475}{58725}\)nên\(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)

\(\frac{21}{25};\frac{60}{81};\frac{19}{29}\)

Ta có : \(\frac{60}{81}=\frac{60:3}{81:3}=\frac{20}{27}\); giữ nguyên \(\frac{21}{25};\frac{19}{29}\).

Vì \(\frac{21}{25}>\frac{20}{25}>\frac{20}{27}\)nên \(\frac{21}{25}>\frac{20}{27}\)

Vì  \(\frac{20}{27}>\frac{20}{29}>\frac{19}{29}\)nên \(\frac{20}{27}>\frac{19}{29}\). Vậy :

\(\frac{21}{25}>\frac{20}{27}>\frac{19}{29}\)hay  \(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)

\(\frac{18}{75}=\frac{6}{25}\)

\(\frac{28}{112}=\frac{1}{4}=\frac{6}{24}\)

Vì 25>24 nên \(\frac{6}{25}< \frac{6}{24}\Leftrightarrow\frac{18}{75}>\frac{28}{112}\)

\(\frac{18}{75}=\frac{6}{25}\)

\(\frac{28}{112}=\frac{1}{4}\)

MÀ : \(\frac{1}{4}=\frac{6}{24}>\frac{6}{25}\)

\(\Rightarrow\frac{18}{75}< \frac{28}{112}\)

A.4/3 > 95/96

B.25/68 > 20/99

C. 9/50 <11/42

> 

> 

 <

A.4/3 > 95/96

B.25/68 >20/99

C. 9/50  <11/42

So sánh: \(\frac{23}{48}< \frac{47}{92}\)(Nhân chéo tử này với mẫu kia bên nào có kết quả lớn hơn thì bên đó lớn hơn bạn nhekk)

Ta có \(\frac{23}{48}< \frac{23}{46}=\frac{46}{92}< \frac{47}{92}\)

Vậy \(\frac{23}{48}< \frac{47}{92}\)

Bài làm

Ta có :

\(\frac{23}{48}=\frac{46}{96}\)

Mà \(\frac{46}{96}< \frac{47}{96}\)

Lại có \(\frac{47}{96}< \frac{47}{92}\)

\(\Rightarrow\)\(\frac{23}{48}< \frac{47}{92}\)

\(\dfrac{12}{17}>\dfrac{1}{2};\dfrac{5}{36}< \dfrac{1}{2}\\ \Rightarrow\dfrac{12}{17}>\dfrac{5}{36}\)

\(\dfrac{12}{17}\) \(>\) \(\dfrac{5}{36}\)