Bài 1:

a) \(\frac{x}{-15}=\frac{-60}{x}\Rightarrow x^2=\left(-60\right).\left(-15\right)=900\Rightarrow x=\orbr{\begin{cases}30\\-30\end{cases}}\)

Bài 2: Đặt \(\frac{x}{4}=\frac{y}{7}=k\Rightarrow x=4k;y=7k\)

\(\Rightarrow xy=4k.7k=28k^2=112\)

\(\Rightarrow k^2=4\Rightarrow k=\pm2\)

\(\Rightarrow\orbr{\begin{cases}x=4.2=8\\x=-4.2=-8\end{cases}}\)

Và \(\orbr{\begin{cases}y=7.2=14\\y=-7.2=-14\end{cases}}\)

Bài 3: \(1\frac{1}{3}:0,8=\frac{2}{3}:\left(0,1x\right)\)

\(\Rightarrow\frac{4}{3}:\frac{4}{5}=\frac{2}{3}:\frac{1}{10}x\Rightarrow\frac{5}{3}=\frac{2}{3}:\frac{1}{10}x\)

\(\Rightarrow\frac{1}{10}x=\frac{2}{5}\Rightarrow x=4\)

Mk trả lời nốt bài 4 hộ bn MMS_Hồ Khánh Châu nha:
Bài 4:
Gọi x là giá trị chung của 2 phân số trên.
Ta có: \(\frac{a}{b}=\frac{c}{d}=x\)
\(\Rightarrow a=x.b \)
      \(c=x.d\)
Ta lại có: 
\(\frac{a+c}{b+d}=\frac{x.b+x.d}{b+d}=\frac{x.\left(b+d\right)}{b+d}=x\)
Và \(\frac{a}{b}=x\)
\(\Rightarrow\frac{a}{b}=\frac{a+c}{b+d}\)
Vậy \(\frac{a}{b}=\frac{a+c}{b+d}\)
Hk tốt nha

\(\frac{x}{-15}=\frac{-60}{x}\Leftrightarrow\frac{x}{-1}=\frac{-4}{x}\Leftrightarrow x\cdot x=4\)

\(\Leftrightarrow x^2=4\Leftrightarrow x=\pm2\)

\(\frac{-2}{x}=\frac{-x}{\frac{8}{25}}\)

\(\Leftrightarrow x\cdot(-x)=-2\cdot\frac{8}{25}\)

\(\Leftrightarrow-x^2=-\frac{16}{25}\)

\(\Leftrightarrow x^2=\frac{16}{25}\Leftrightarrow x=\pm\frac{4}{5}\)

\(\frac{x}{-15}=\frac{-60}{x}\)

\(\Rightarrow x^2=900\)

\(\Rightarrow x=\pm30\)

\(\frac{-2}{x}=\frac{-x}{\frac{8}{25}}\)

\(\Rightarrow-\left(x^2\right)=-\frac{16}{25}\)

\(\Rightarrow-\left(x^2\right)=-\left(\frac{4}{5}\right)^2\)

\(\Rightarrow x=\frac{4}{5}\)

a) - 0,52 : x = - 9,36 : 16,38

- 0,52 : x = \(-\frac{4}{7}\)

\(x=\left(-0,52\right):\left(-\frac{4}{7}\right)=\frac{91}{100}=0,91\)

b) \(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)

\(\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\)

\(\frac{x}{1,61}=\frac{34}{23}\)

\(x=\frac{34}{23}.1,61=2,38\)

\(\frac{-12}{x}=\frac{4}{13}\)

\(\Rightarrow4x=13.\left(-12\right)=-156\)

\(\Rightarrow x=-156:4=-39\)

\(\frac{-15}{72}=\frac{125}{-3y}\)

\(\Rightarrow\frac{-15}{72}=\frac{-3000}{72y}\)

\(\Rightarrow-15y=-3000\)

\(\Rightarrow y=-3000:-15=200\)

\(\frac{49}{21}=\frac{-14z}{-7}\)

\(\Rightarrow\frac{49}{21}=\frac{42z}{21}\)

\(\Rightarrow49=42z\)

\(\Rightarrow z=\frac{49}{42}\)

x=-39 

y=200

z=1,167

x= -12 x 13 : 4 = -39

y= 125 x 72 : (-15) = 600

z= ... mình không biết

\(\frac{4\frac{1}{4}}{2\frac{7}{8}}=\frac{x}{1,61}\)

\(\Leftrightarrow\frac{\frac{17}{4}}{\frac{23}{8}}=\frac{x}{1,61}\)

\(\Leftrightarrow\frac{34}{23}=\frac{x}{1,61}\)

\(\Leftrightarrow x=\frac{34}{23}.1,61\)

\(\Leftrightarrow x=\frac{119}{50}\)

a) \(\frac{3x-2}{1\frac{2}{5}}=\frac{2\frac{3}{7}}{2\frac{3}{5}}\Rightarrow3x-2=1.\frac{2}{5}.\frac{2\frac{3}{7}}{2\frac{3}{5}}=\frac{7}{5}.\frac{17}{7}.\frac{5}{13}\)

\(3x-2=\frac{17}{13}\Rightarrow3x=2+\frac{17}{13}=\frac{43}{13}\Rightarrow x=\frac{43}{39}.\)

b) \(\frac{x}{0,16}=\frac{9}{x}\Rightarrow x^2=9.0,16=1,44\Rightarrow x=\pm1,2\)

b) Áp dụng t/c dãy tỉ số bằng nhau,ta có:

\(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}=\frac{1+3y+1+5y+1+7y}{12+5x+4x}=\frac{3+15y}{12+5x+4x}=\frac{3\left(1+5y\right)}{2.3.2+5x+4x}=\frac{1+5y}{4+9x}=\frac{1+5y}{5x}\)<=> 4 + 9x = 5x

....

a/ Từ giả thiêt ta có \(\frac{x-9}{15}=\frac{y-12}{20}=\frac{z-24}{40}\Leftrightarrow\frac{x}{15}-\frac{3}{5}=\frac{y}{20}-\frac{3}{5}=\frac{z}{40}-\frac{3}{5}\)

\(\Leftrightarrow\frac{x}{15}=\frac{y}{20}=\frac{z}{40}\). Đặt \(\frac{x}{15}=\frac{y}{20}=\frac{z}{40}=k\)

\(\Rightarrow\begin{cases}x=15k\\y=20k\\z=40k\end{cases}\)

Theo đề bài : \(xy=1200\Leftrightarrow15k.20k=1200\Leftrightarrow k^2=4\Leftrightarrow k=\pm2\)

Tới đây dễ rồi nhé :)

b/ \(\frac{1+5y}{5x}=\frac{1+7y}{4x}\Leftrightarrow\frac{1+5y}{5}=\frac{1+7y}{4}\Leftrightarrow\frac{7+35y}{35}=\frac{5+35y}{20}=\frac{7+35y-5-35y}{35-20}=\frac{2}{15}\)

\(\Rightarrow y=-\frac{1}{15}\)

Thay y vào \(\frac{1+3y}{12}=\frac{1+5y}{5x}\) tìm được x = 2

Bài a) :)) Làm không ra. Tính mãi x.y vẫn không bằng 1200

a.

\(x\div\frac{11}{4}=-2,5\div\frac{5}{8}\)

\(x\div\frac{11}{4}=-2,5\times\frac{8}{5}\)

\(x\div\frac{11}{4}=-4\)

\(x=-4\times\frac{11}{4}\)

\(x=-11\)

b.

\(\frac{18}{5x+21}=\frac{27}{34}\)

\(5x+21=\frac{18\times34}{27}\)

\(5x+21=\frac{68}{3}\)

\(5x=\frac{68}{3}-21\)

\(5x=\frac{5}{3}\)

\(x=\frac{5}{3}\div5\)

\(x=\frac{5}{3}\times\frac{1}{5}\)

\(x=\frac{1}{3}\)

Chúc bạn học tốt ^^

tks bn nha

kcj ^^