Question

Tìm x trong mỗi tỉ lệ thức sau:

a) x:\(\frac{11}{4}=-2,5:\frac{5}{8}\)

b) \(\frac{18}{5x+21}=\frac{27}{34}\)

Answer 1

a.

\(x\div\frac{11}{4}=-2,5\div\frac{5}{8}\)

\(x\div\frac{11}{4}=-2,5\times\frac{8}{5}\)

\(x\div\frac{11}{4}=-4\)

\(x=-4\times\frac{11}{4}\)

\(x=-11\)

b.

\(\frac{18}{5x+21}=\frac{27}{34}\)

\(5x+21=\frac{18\times34}{27}\)

\(5x+21=\frac{68}{3}\)

\(5x=\frac{68}{3}-21\)

\(5x=\frac{5}{3}\)

\(x=\frac{5}{3}\div5\)

\(x=\frac{5}{3}\times\frac{1}{5}\)

\(x=\frac{1}{3}\)

Chúc bạn học tốt ^^

Answer 2

tks bn nha

Answer 3

kcj ^^