\(a,\dfrac{3^{43}+3^4}{3^{39}+1}\)

\(=\dfrac{3^4\cdot\left(3^{39}+1\right)}{3^{39}+1}\)

\(=3^4\)

\(=81\)

\(b,\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\)

\(=\dfrac{3^{10}\left(11+5\right)}{3^9.2^4}\)

\(=\dfrac{3^{10}.16}{3^9.2^4}\)

\(=\dfrac{3^{10}.2^4}{3^9.2^4}=3\)

\(4^{10}.8^{15}=2^{20}.2^{45}=2^{65}\)

\(4^{15}.5^{30}=2^{30}.5^{30}=10^{30}\)

\(27^{16}:9^{10}=3^{48}:3^{20}=3^{28}\)

\(72^3.54^2=2^9.3^6.2^2.3^6=2^{11}.3^{12}\)

\(108^4=2^8.3^{12}\)

\(3^{10}.11+3^{10}.5=3^{10}.\left(11+5\right)=3^{10}.16\)

\(3^9.2^4=3^9.2^4\)

`@` `\text {Ans}`

`\downarrow`

`4^10*8^15`

`= (2^2)^10 * (2^3)^15`

`= 2^20 * 2^45`

`=`\(2^{20+45}=2^{65}\)

`4^15 * 5^30`

`= (2^2)^15 * 5^30`

`= 2^30 * 5^30`

`= (2*5)^30`

`= 10^30`

`27^16 \div 9^10`

`= (3^3)^16 \div (3^2)^10`

`= 3^48 \div 3^20`

`=`\(3^{48-20}=3^{28}\)

`A = `\(72^3\cdot54^2\cdot108^4\)

`= 2^9 * 3^6 * 3^4 * 3^2 * 2^2 * 3^8 * 3^4 * 2^4 * 2^4`

`=`\(\left(2^9\cdot2^2\cdot2^4\cdot2^4\right)\cdot\left(3^6\cdot3^4\cdot3^2\cdot3^8\cdot3^4\right)\)

`= 2^19 * 3^24`

`B = 3^10 * 11 + 3^10 * 5 + 3^9 * 2^4`

`= 3^9 * (11*3 + 5*3 + 2^4)`

`= 3^9 * (33 + 15 + 16)`

`= 3^9 * 64`

`= 27^3 * 4^3`

`= (27 * 4)^3`

`= 108^3`

ok để mình

3,44591034

    3¹⁰.10+3^10.6:3⁹.2⁴

=59049.(4,23911582.10²⁸) : 19683 . 16

= 5647820046352,9488 : 1227,375

=4601543983,18

Trả lời

a)(1+3+2+...10).(1²+2³+3²+...+100²).(65.111-13.15.37)

=(1+3+2+...10).(1²+2²+3³+...+100²).0

=0

310,5 - x = 135

x = 310,5 - 135

x = 175,5

mình chỉ làm được phần a thôi k cho mình đó!!!!