a)(2^4.7^3+7^4.36) : (7^3.20-7^3.16)
b)(8^4.13+4^6.27):(2^13.15-2^12.6
Những câu hỏi liên quan
Tính giá trị của biểu thức sau:
A=11 3/13-(2 4/7+5 3/13)
B=-1/13.15/17+-1/13.2/17+4 5/9
C=(-5/24+0.75+7/12)÷(-2 1/8)
D= 3./1.4+ 3/4.7+3/7.10+...+3/40.43
Mong mọi người hiểu và làm được cho mình
BÀI 1: a, M = \(\frac{4^6.9^5+120.6^9}{8^4.13^{12}-6^{11}}\)
b, N = \(\left(-\frac{3}{4}+\frac{5}{13}\right):\frac{2}{7}-\left(2\frac{1}{4}+\frac{8}{13}\right):\frac{2}{7}\)
a) A= ( 28.4.13+ 27.8.65) : ( 29.3)
Ta có
\(2^8.4.13=2^9.26\)
\(2^7.8.65=2^9.130\)
Nên \(2^8.4.13+2^7.8.65=2^9.156\)
Mà \(2^9:2^9=1\)
\(156:3=52\)
Do đó A = 52
Bài 1 : a) -5/11.4/7+-5/11.3/7-8/11
b) (2/9:5/3+1/3:5/3)^2-(1/3-5/8)
c) 14-|-3/4|-(1/3-5/8)
Bài 2:
A= 2/1.4+2/4.7+2/7.9+...+2/196.199
1)
a)
\(\dfrac{-5}{11}\cdot\dfrac{4}{7}+\dfrac{-5}{11}\cdot\dfrac{3}{7}-\dfrac{8}{11}\\ =\dfrac{-5}{11}\cdot\left(\dfrac{4}{7}+\dfrac{3}{7}\right)-\dfrac{8}{11}\\ =\dfrac{-5}{11}\cdot1-\dfrac{8}{11}\\ =\dfrac{-5}{11}-\dfrac{8}{11}\\ =\dfrac{-5}{11}+\dfrac{-8}{11}\\ =\dfrac{-13}{11}\)
b)
\(\left(\dfrac{2}{9}:\dfrac{5}{3}+\dfrac{1}{3}:\dfrac{5}{3}\right)^2-\left(\dfrac{1}{3}-\dfrac{5}{8}\right)\\ =\left(\dfrac{2}{9}\cdot\dfrac{3}{5}+\dfrac{1}{3}\cdot\dfrac{3}{5}\right)^2-\left(\dfrac{-7}{24}\right)\\ =\left[\dfrac{3}{5}\cdot\left(\dfrac{2}{9}+\dfrac{1}{3}\right)\right]^2+\dfrac{7}{24}\\ =\left[\dfrac{3}{5}\cdot\dfrac{5}{9}\right]^2+\dfrac{7}{24}\\ =\left[\dfrac{1}{3}\right]^2+\dfrac{7}{24}\\ =\dfrac{1}{9}+\dfrac{7}{24}\\ =\dfrac{29}{72}\)
c) \(14-\left|\dfrac{-3}{4}\right|-\left(\dfrac{1}{3}-\dfrac{5}{8}\right)\\ =14-\dfrac{3}{4}-\left(\dfrac{-7}{24}\right)\\ =14+\dfrac{-3}{4}+\dfrac{7}{24}\\ =13\dfrac{13}{24}\)
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a, Rút gọn: 2^7.6^5-4^4.36^2/12^6+8^4.3^5
b,Tìm dư trong phép chia 1+2+2^2+2^3+...+2^2013 cho 3
c,Tìm STN a, biết: a chia 3 dư 2, chia 5 dư 3, chia 7 dư 4 và 4600=<a=<4700
1,tìm x
a, 4/7+5/7:x=1
b,(2/11. 2/13.15+...+2/19.21) - x + 221/231=4/3
a)\(\frac{5}{7}:X=1-\frac{4}{7}=\frac{3}{7}\)
\(X=\frac{5}{7}:\frac{3}{7}=\frac{5}{3}\)
b)
\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{14}+...+\frac{1}{19}-\frac{1}{21}\right)-X=\frac{4}{3}-\frac{221}{231}=\frac{29}{77}\)
\(\left(\frac{1}{11}-\frac{1}{21}\right)-X=\frac{29}{77}\)
\(X=\frac{10}{231}-\frac{29}{77}=-\frac{1}{3}\)
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25 tháng 10 2023 lúc 13:39
1) Tính:
a) \(\sqrt{4.36}\)
b) (\(\sqrt{8}\) - 3\(\sqrt{2}\)) . \(\sqrt{2}\)
c)\(\dfrac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}\)
d) \(\dfrac{2}{\sqrt{5}+2}\) + \(\dfrac{2}{\sqrt{5}-2}\)
a: \(\sqrt{4\cdot36}=\sqrt{144}=12\)
b: \(\left(\sqrt{8}-3\sqrt{2}\right)\cdot\sqrt{2}\)
\(=\left(2\sqrt{2}-3\sqrt{2}\right)\cdot\sqrt{2}\)
\(=-\sqrt{2}\cdot\sqrt{2}=-2\)
c: \(\dfrac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}=\dfrac{-\sqrt{7}\left(1-\sqrt{2}\right)}{1-\sqrt{2}}=-\sqrt{7}\)
d: \(\dfrac{2}{\sqrt{5}+2}+\dfrac{2}{\sqrt{5}-2}\)
\(=\dfrac{2\left(\sqrt{5}-2\right)+2\left(\sqrt{5}+2\right)}{5-4}\)
\(=2\sqrt{5}-4+2\sqrt{5}+4=4\sqrt{5}\)
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-12:(3/4-5/6)^2
7/23.((-8/6)-45/18)
23/1/4.7/5-13/1/4:5/7
(1+2/3-1/4)(0,8-3/4)
16/2/7:(-3/5)+28/2/7:3/5
xấp xỉ -113595,7577
Rút gọn
\(A=\frac{a^2.a^7.b^2.c^8}{a^5.b^3.\left(-c\right)^4}\)
B=\(\left(\frac{3}{7}\right)^{5.}\frac{\left(25\right)^4.7^5}{15^4.20^2}\)
\(A=\frac{a^2.a^7.b^2.c^8}{a^5.b^3.\left(-c\right)^4}=\frac{a^9.b^2.c^8}{a^5.b^3.c^4}=\frac{a^4.c^4}{b}\)
\(B=\left(\frac{3}{7}\right)^5.\frac{\left(25\right)^4.7^5}{15^4.20^2}=\frac{3^5.\left(5^2\right)^4.7^5}{7^5.\left(3.5\right)^4.\left(4.5\right)^2}=\frac{3^5.5^8.7^5}{7^5.3^4.5^4.4^2.5^2}\)
\(=\frac{3^5.5^8.7^5}{7^5.3^4.5^6.4^2}=\frac{3.5^2}{4^2}=\frac{75}{16}\)
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