\(\frac{-90}{189}\)+\(\frac{45}{84}\)-\(\frac{75}{126}\)
Tính:
a) \(\frac{-90}{189}+\frac{45}{84}-\frac{78}{126}\)
b) \(11\frac{7}{21}+8\frac{16}{24}-10\frac{21}{35}\)
c) \(\frac{37}{43}\cdot\frac{17}{29}-\frac{21}{41}\cdot\frac{1}{2}+\frac{9}{58}:1\frac{6}{37}-\frac{6}{2}:1\frac{29}{21}\)
d) \(\sqrt{\left(-5\right)^2}+\sqrt{5^2}-\sqrt{\left(-5\right)^2}-\sqrt{3^2}\)
a) -90/189 + 45/84 - 78/126
= -10/21 + 15/28 - 13/21
= (-10/21 - 13/21) + 15/28
= -24/21 + 15/28
= -17/28
\(\frac{90}{60}-\frac{189}{126}=\)
\(\frac{90}{60}-\frac{189}{126}=\frac{3}{2}-\frac{3}{2}=0\)
\(\frac{90}{60}-\frac{189}{126}=\frac{3}{2}-\frac{3}{2}=0\)
\(\frac{90}{60}-\frac{189}{126}=\frac{3}{2}-\frac{3}{2}=0\)
Tính nhanh
\(\frac{1}{15}+\frac{4}{30}+\frac{9}{45}+\frac{16}{60}+\frac{25}{75}+\frac{36}{90}+\frac{49}{105}+\frac{64}{120}+\frac{81}{135}\)
#)Giải :
\(\frac{1}{15}+\frac{4}{30}+\frac{9}{45}+\frac{16}{60}+...+\frac{81}{135}=\frac{1}{15}+\frac{2}{15}+\frac{3}{15}+...+\frac{9}{15}=\frac{45}{15}=3\)
Dễ ẹc ak :v rút gọn là ra
=(\(\frac{1}{15}\)+\(\frac{4}{30}\)+\(\frac{16}{60}\)+\(\frac{64}{120}\))+(\(\frac{9}{45}\)+\(\frac{36}{90}\))+(\(\frac{25}{75}\)+\(\frac{81}{135}\))
=(\(\frac{8}{120}\)+\(\frac{16}{120}\)+\(\frac{32}{120}\)+\(\frac{64}{120}\))+(\(\frac{18}{90}\)+\(\frac{36}{90}\))+\(\frac{14}{15}\).
=1+\(\frac{3}{5}\)+\(\frac{14}{15}\).
=\(\frac{8}{5}\)+\(\frac{14}{15}\).
=\(\frac{15}{38}\)
Tính nhanh:
a)\(\frac{5}{30}+\frac{15}{90}+\frac{25}{150}+\frac{35}{210}+\frac{45}{270}\)
b)\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{56}\)
c)\(\frac{1}{15}+\frac{4}{30}+\frac{2}{45}+\frac{16}{60}+\frac{25}{75}+\frac{36}{90}+\frac{49}{105}+\frac{64}{120}+\frac{81}{135}\)
a) 5/30+15/90+25/150+35/210+45/270
=1/6+1/6+1/6+1/6+1/6
=1/6 x 5
=5/6
b) 1/2+1/6+1/12+1/20+....+1/56
=1/1x2+1/2x3+1/3x4+1/4x5+.....1/7x8
=1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+.......-1/7+1/7-1/8
=1/1-1/8
=7/8
c) mình chịu
chịu,khó quá,nhất là câu c ý
P=\(1+\frac{9}{45}+\frac{9}{105}+\frac{9}{189}+.........+\frac{9}{29997}\)
#)Giải :
\(P=1+\frac{9}{45}+\frac{9}{105}+\frac{9}{189}+...+\frac{9}{29997}\)
\(P=\frac{3}{1.3}+\frac{3}{3.5}+\frac{3}{5.7}+...+\frac{3}{99.101}\)
\(P=\frac{3}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101} \right)\)
\(P=\frac{3}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{101}\right)\)
\(P=\frac{3}{2}\left(1-\frac{1}{101}\right)\)
\(P=\frac{3}{2}\times\frac{100}{101}\)
\(P=\frac{150}{101}\)
trả lời
=150/101
chúc bn
hc tốt
trả lời
=150/101
chúc bn
hc tốt
Tìm S =\(\frac{1}{9}+\frac{1}{45}+\frac{1}{105}+\frac{1}{189}+\frac{1}{297}\)
S = \(\frac{1}{9}+\frac{1}{45}+\frac{1}{105}+\frac{1}{189}+\frac{1}{297}\)
S = 1/9 + 1/45 + 1/105 + 1/189 + 1/297
=> S = 1/2 ( 6/27 + 6/135 + 6/315 + 6/567 + 6/891 )
=> S = 1/2 ( 6/3.9 + 6/9.15 + 6/15.21 + 6/21.27 + 6/27.33 )
=> S = 1/2 ( 1/3 - 1/9 + 1/9 - 1/15 + ... + 1/27 - 1/33 )
=> S = 1/2 ( 1/3 - 1/33 )
=> S = 1/2 . 10/33
=> S = 5/33
\(S=\frac{1}{9}+\frac{1}{45}+\frac{1}{105}+\frac{1}{189}+\frac{1}{297}\)
\(S=\frac{1}{1.9}+\frac{1}{9.5}+\frac{1}{5.21}+\frac{1}{21.9}+\frac{1}{9.33}\)
\(5S=\frac{5}{1.9}+\frac{5}{9.5}+\frac{5}{5.21}+\frac{5}{21.9}+\frac{5}{9.33}\)
\(5S=1-\frac{1}{9}+\frac{1}{9}-\frac{1}{5}+\frac{1}{5}+\frac{1}{21}+\frac{1}{21}-\frac{1}{9}+\frac{1}{9}-\frac{1}{33}\)
\(5S=1-\frac{1}{33}\)
\(5S=\frac{32}{33}\)
\(S=\frac{32}{33}:5\)
\(S=\frac{32}{165}\)
Cậu Bé Tiến Pro sai rồi nhé!
\(\frac{5}{1.9}=1-\frac{1}{9}\Leftrightarrow9-1=5\)
-.-
TÍNH
S + \(\frac{1}{9}+\frac{1}{45}+\frac{1}{105}+\frac{1}{189}+\frac{1}{297}\)
\(A=\frac{1}{18}+\frac{1}{36}+\frac{1}{60}+\frac{1}{90}+\frac{1}{126}+\frac{1}{168}\)
\(A=\frac{1}{18}+\frac{1}{36}+\frac{1}{60}+...+\frac{1}{168}\)
\(\frac{1}{3}A=\frac{1}{54}+\frac{1}{108}+...+\frac{1}{504}\)
\(\frac{1}{3}A=\frac{1}{6.9}+\frac{1}{9.12}+...+\frac{1}{21.24}\)
\(=\frac{1}{6}-\frac{1}{9}+\frac{1}{9}-\frac{1}{12}+...+\frac{1}{21}-\frac{1}{24}\)
\(=\frac{1}{6}-\frac{1}{24}\)
\(=\frac{4-1}{24}=\frac{3}{24}=\frac{1}{8}\)
=> \(A=\frac{1}{8}:\frac{1}{3}\)\(=\frac{3}{8}\)