b)2^300=(2^3)^100=8^100

  3^200=(3^2)^100=9^100

vi 8<9nen 2^300<3^200

Ta có \(3^{21}=\left(3^3\right)^7=27^7\)

\(2^{31}=2147483648\)

Mà \(27>2_{ }\)\(\Rightarrow3^{21}>2^{31}\)

c)

\(32^9>18^{13}\)(chứng minh tương tự) 

a. >

b. =

c. <

32⁹ = (2⁵)⁹ = 2⁴⁵ = (2³)¹⁵ = 8¹⁵  = 8¹³ . 8² = 8¹³ . 2⁶

18¹³ = 9¹³ . 2¹³ 

Vì 9¹³ > 8¹³

     2¹³ > 2⁶

\(\Rightarrow\)32⁹ < 18¹³

\(\Rightarrow\)\(\left(-32\right)^9>\left(-18\right)^{13}\)

Ta có: 32⁹ = (2⁵)⁹ = 2⁴⁵

18¹³ > 16¹³ = (2⁴)¹³ = 2⁵² (⁴)

Ta thấy : 2⁴⁵ < 2⁵² < 18¹³

=> 32⁹ < 18¹³

Ta có: 32⁹ = (2⁵)⁹ = 2⁴⁵

18¹³ > 16¹³ = (2⁴)¹³ = 2⁵² (⁴)

Ta thấy : 2⁴⁵ < 2⁵² < 18¹³

=> 32⁹ < 18¹³

a)\(2^{100}=\left(2^{10}\right)^{10}=1024^{10}>1024^9\)

b) \(9^{12}=\left(3^2\right)^{12}=3^{24}\) và \(27^7=\left(3^3\right)^7=3^{21}\)

=> \(9^{12}>27^7\)

a, 1024 mũ 9 = 2 mũ 10 .9 = 2 mũ 90 < 2 mũ 100

b,  27 mũ 7 = 3 mũ 3.7 =3 mũ 21 < 3 mũ 24 = 3 mũ 2.12 = 9 mũ 12

c,2 mũ 161 > 2 mũ 160 = 2 mũ 4.40 = 16 mũ 40 > 13 mũ 40

A) 2¹⁰⁰ = (2¹⁰)¹⁰ = 1024¹⁰ > 1024⁹

=> 2¹⁰⁰ > 1024⁹

B) 9¹² = (3²)¹² = 3²⁴ ; 27⁷ = (3³)⁷ = 3²¹

Vì 3²⁴ > 3²¹

=> 9¹² > 27⁷

C) 13⁴⁰ < 16⁴⁰ = (2⁴)⁴⁰ = 2¹⁶⁰ < 2¹⁶¹

=> 13⁴⁰ < 2¹⁶¹

a) 2x . 4 = 128

2x = 128 : 4

2x = 32

x = 32 : 2

x = 16

b)x . 17 = x

=> x = 0

a) \(2^{300}=\left(2^3\right)^{100}=8^{100}\)

\(3^{200}=\left(3^2\right)^{100}=9^{100}>8^{100}\)

\(\Rightarrow2^{300}< 3^{200}\)

b) \(99^{20}=\left(99^2\right)^{10}=9801^{10}< 9999^{10}\Rightarrow99^{20}< 9999^{10}\)

c) \(3^{500}=\left(3^5\right)^{100}=243^{100}\)

\(7^{300}=\left(7^3\right)^{100}=343^{100}>243^{100}\)

\(\Rightarrow3^{500}< 7^{300}\)

Giải chi tiết giúp mình ạ~

\(\left(d\right):202^{303}=\left(202^3\right)^{101}=8242408^{101}>303^{202}=\left(303^2\right)^{101}=91809^{101}\)

\(\left(e\right):107^{50}=\left(107^2\right)^{25}=11449^{25}< 73^{75}=\left(73^3\right)^{25}=389017^{25}\)