\(\frac{17}{6}-\left(x-\frac{7}{6}\right)=\frac{7}{4}\)

\(x-\frac{7}{6}=\frac{13}{12}\)

\(x=\frac{9}{4}\)

17/6 - ( x - 7/6 ) = 7/4

          ( x - 7/6 ) = 17/6 - 7/4

         ( x - 7/6 ) = 13/12

            x         = 13/12 + 7/6

            x          = 9/4

\(\frac{17}{6}-\left(x-\frac{7}{6}\right)=\frac{7}{4}\)

                 \(x-\frac{7}{6}=\frac{17}{6}-\frac{7}{4}\)

                 \(x-\frac{7}{6}=\frac{13}{12}\)

                 \(x=\frac{13}{12}+\frac{7}{6}\)

                 \(x=\frac{9}{4}\)

\(-\frac{4}{9}+\left(-\frac{5}{6}\right)-\frac{17}{4}=-\frac{199}{36}\)

\(-x-\frac{2}{3}=-\frac{6}{7}\)

\(\Rightarrow-x=-\frac{6}{7}+\frac{2}{3}\)

\(\Rightarrow-x=-\frac{4}{21}\)

\(\Rightarrow x=\frac{4}{21}\)

\(\frac{4}{7}-x=\frac{1}{3}\)

\(\Rightarrow x=\frac{4}{7}-\frac{1}{3}\)

\(\Rightarrow x=\frac{5}{21}\)

1. -4/9 + ( -5/6) -17/4

     = -23/18 - 17/4 = -199/36

  2.tìm x

   a. -x - 2/3 = -6/7

       -x = -6/7 +2/3

       -x = -4/21

        x=4/21

   b. 4/7 - x = 1/3

          x = 4/7 - 1/3

          x =5/21 

-4/9 + ( -5/6 ) - 17/4

= -23/54 - 17/4

= -199/36

Tìm x :

-x - 2/3 = -6/7

        -x  = -6/7 + 2/3

       - x  = -4/21

         x  = 4/21

4/7 - x = 1/3

         x = 4/7 - 1/3

         x = 5/21

Mình trả lời hai câu đầu trước nha!

1)

x= -6+2

x= -4

2)

=-5 x = 13 + (-3)

= -5 .x =10

x = 10 ÷ -5

x = -2

Bài 1:

a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)

b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)

c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)

d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)

hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)

e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)

hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)

dad

Bài 1: 

a) Ta có: \(\dfrac{17}{6}-x\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)

\(\Leftrightarrow\dfrac{17}{6}-x^2+\dfrac{7}{6}x-\dfrac{7}{4}=0\)

\(\Leftrightarrow-x^2+\dfrac{7}{6}x+\dfrac{13}{12}=0\)

\(\Leftrightarrow-12x^2+14x+13=0\)

\(\Delta=14^2-4\cdot\left(-12\right)\cdot13=196+624=820\)

Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:

\(\left\{{}\begin{matrix}x_1=\dfrac{14-2\sqrt{205}}{-24}=\dfrac{-7+\sqrt{205}}{12}\\x_2=\dfrac{14+2\sqrt{2015}}{-24}=\dfrac{-7-\sqrt{205}}{12}\end{matrix}\right.\)

b) Ta có: \(\dfrac{3}{35}-\left(\dfrac{3}{5}-x\right)=\dfrac{2}{7}\)

\(\Leftrightarrow\dfrac{3}{5}-x=\dfrac{3}{35}-\dfrac{10}{35}=\dfrac{-7}{35}=\dfrac{-1}{5}\)

hay \(x=\dfrac{3}{5}-\dfrac{-1}{5}=\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)

ai giúp mik vs

Bài 3: 

a) Ta có: \(2x-3=x+\dfrac{1}{2}\)

\(\Leftrightarrow2x-x=\dfrac{1}{2}+3\)

\(\Leftrightarrow x=\dfrac{7}{2}\)

b) Ta có: \(4x-\left(x+\dfrac{1}{2}\right)=2x-\left(\dfrac{1}{2}-5\right)\)

\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{1}{2}-5=0\)

\(\Leftrightarrow x=5\)

a) \(435-\left(x+16\right)=425:17\)

\(435-\left(x+16\right)=25\)

\(x+16=435-25\)

\(x+16=410\)

\(x=410-16\)

\(x=394\)

b) \(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)

\(x+\frac{3}{4}=\frac{23}{6}:\frac{7}{4}\)

\(x+\frac{3}{4}=\frac{46}{21}\)

\(x=\frac{46}{21}-\frac{3}{4}\)

\(x=\frac{121}{84}\)

435 - ( x + 16 ) = 425 : 17

435 - ( x + 16 ) = 25

           x + 16   = 435 - 25

           x + 16   = 410

           x           = 410 - 16

           x           = 394

\(435-\left(x+16\right)=425\div17\)

\(435-\left(x+16\right)=25\)

\(x+16=435-25\)

\(x+16=410\)

\(x=410-16\)

\(x=394\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}+\frac{7}{6}=5\)

\(\left(x+\frac{3}{4}\right)\times\frac{7}{4}=5-\frac{7}{6}\)

\(\left(x\times\frac{3}{4}\right)\times\frac{7}{4}=\frac{23}{6}\)

\(x+\frac{3}{4}=\frac{23}{6}\div\frac{7}{4}\)

\(x\times\frac{3}{4}=\frac{46}{21}\)

\(x=\frac{46}{21}-\frac{3}{4}\)

\(x=\frac{121}{84}\)

\(\)