đáp án là: 6174

ban Thu Trang lam dung do

Đặt \(2000=a\)

\(A=a^9\\ B=\left(a-4\right)\left(a-3\right)\left(a-2\right)\left(a-1\right)a\left(a+1\right)\left(a+2\right)\left(a+3\right)\left(a+4\right)\\ B=\left(a^2-16\right)\left(a^2-9\right)\left(a^2-4\right)\left(a^2-1\right)a< a.a^2.a^2.a^2.a^2=a^9\\ B=\left(a-8\right)\left(a-6\right)\left(a-4\right)\left(a-2\right)a\left(a+2\right)\left(a+4\right)\left(a+6\right)\left(a+8\right)\\ C=\left(a^2-64\right)\left(a^2-36\right)\left(a^2-16\right)\left(a^2-4\right)a\\ C< \left(a^2-9\right)\left(a^2-4\right)\left(a^2-1\right)a< a.a^2.a^2.a^2=a^9\\ D=\left(a-20\right)\left(a-15\right)\left(a-10\right)\left(a-5\right)a\left(a+5\right)\left(a+10\right)\left(a+15\right)\left(a+20\right)\\ D=\left(a^2-400\right)\left(a^2-225\right)\left(a^2-100\right)\left(a^2-25\right)a\\ D< \left(a^2-64\right)\left(a^2-36\right)\left(a^2-16\right)\left(a^2-4\right)a< a.a^2.a^2.a^2=9\)

Vậy \(D< C< B< A\)

a) -72, -42, -30, -5, 0, 1

b) 0, -1, -5, -30, -42, -72

c) 0: 0, -1: 1, -5: 5, -30: 30, -42: 42, -72: 72

d) 0 + 1 + (-5) + (-30) + (-42) + (-72) = -148

Tick cho mình nghen

uses crt;

var a:array[1..100]of integer;

i,n,t,min,tam,j:integer;

begin

clrscr;

write('Nhap n='); readln(n);

for i:=1 to n do 

begin

write('A[',i,']='); readln(a[i]);

end;

for i:=1 to n do 

  write(a[i]:4);

writeln;

t:=0;

for i:=1 to n do 

  t:=t+a[i];

writeln(t);

min:=a[1];

for i:=1 to n do 

if min>a[i] then min:=a[i];

writeln(min);

for i:=1 to n-1 do 

  for j:=i+1 to n do

if a[i]<a[j] then

begin

tam:=a[i];

a[i]:=a[j];

a[j]:=tam;

end;

for i:=1 to n do 

  write(a[i]:4);

readln;

end.

//Thủ tục nhập mảng
void NhapMang(int A[], int n){
   for(int i = 0; i<n ; i++)
   {
      printf("Phan tu %d =",i);
      scanf("%d", &A[i]);
   }
}
// Thủ tục xuất mảng
void XuatMang(int A[], int n){
   printf("\n");
   for(int i = 0; i<n ; i++)
   {
      printf("%d\t",A[i]);
   }
}