Tự lm đ

\(\left(x+2\right)\left(x+3\right)\left(x+4\right)\left(x+5\right)-8=\left(x^2+7x+10\right)\left(x^2+7x+12\right)-8\)

Đặt \(x^2+7x=t\)

\(\left(t+10\right)\left(t+12\right)-8=t^2+22t+120-8\)

\(=t^2+22t+112=\left(t+8\right)\left(t+14\right)\)

Theo cách đặt \(=\left(x^2+7x+8\right)\left(x^2+7x+14\right)\)

CHAO BAN

1+1bang may

\(x^2\left(x-3\right)^2-\left(x-3\right)^2-x^2+1=\left(x-3\right)^2\left(x^2-1\right)-\left(x^2-1\right)=\left(x^2-1\right)\left(x-3\right)^2=\left(x-1\right)\left(x+1\right)\left(x-3\right)^2\)

7(x - 3) - x(3 - x)

= (x - 3)(7 + x)

chỉ bt có v mà k bt có đúng k 

1 ) 7 ( x - 3 ) - x ( 3 - x ) 

= 7 ( x - 3 ) + x ( x - 3 )

= ( x - 3 ) ( 7 + x )

2 ) 4x² - 6x + 3 - 2x

= 4x² - 2x - 6x + 3

= 2x ( 2x - 1 ) - 3 ( 2x - 1 )

= ( 2x - 1 ) ( 2x - 3 )

3 ) ( 4 - x ) - 4x + x²

= ( 4 - x ) - x ( 4 - x )

= ( 4 - x ) (  1 - x )

4 ) x² - 2xy + y²

= ( x - y )²

1, \(7\left(x-3\right)-x\left(3-x\right)=7\left(x-3\right)+x\left(x-3\right)\)

\(=\left(x-3\right)\left(x+7\right)\)

2,\(4x^2-6x+\left(3-2x\right)=4x^2-8x+3\)

\(=4x^2-6x-2x+3=2x\left(2x-3\right)-\left(2x-3\right)\)

\(=\left(2x-3\right)\left(2x-1\right)\)

3,\(\left(4-x\right)-4x+x^2=x^2-5x+4\)

\(=x^2-x-4x+4=x\left(x-1\right)-4\left(x-1\right)=\left(x-1\right)\left(x-4\right)\)

4,\(x^2-2xy+y^2=\left(x-y\right)^2\)

A=x¹⁴+x⁷+1

   =(x¹⁴+x¹³+x¹²)-(x¹³+x¹²+x¹¹)+(x¹¹+x¹⁰+x⁹)-(x¹⁰+x⁹+x⁸)+(x⁸+x⁷+x⁶)-(x⁶+x⁵+x⁴)+(x⁵+x⁴+x³)-(x³⁺x²+x)+(x²+x+1)

Đặt B=x²+x+1

=>A=x¹²B-x¹¹B+x⁹B-x⁸B+x⁶B-x⁴B+x³B-xB+B

=>A=B(x¹²-x¹¹+x⁹-x⁸+x⁶-x⁴+x³-x+1)

Thay B=x²+x+1 vào A là xong

dùng bơ du là ra chư mấy

Do lười đánh máy nên tớ mới đặt B khi làm khỏi đặt cũng dc cái này là toán lớp 8

x⁸ + 2500

= (x⁴)² + 2.x⁴.50 + (50)² - 2.x⁴.50

= (x⁴ + 50)² - (10x²)²

= (x⁴ + 50 - 10x²)(x⁴ + 50 + 10x²)