Tìm số đó :
\(\dfrac { 4^6 . 9^5 + 6^9 . 120 } { 8^4 . 3^{12} - 6^{11}}\)
\(\dfrac { 4^6 . 9^5 + 6^9 . 120 } { 8^4 . 3^{12} - 6^{11}}\)
=(22)6.(32)5+(2.3)9.23.3.5/(23)4.312-(2.3)11
=212.310+29.39.23.3.5/212.312-211.311
=212.310+212.310.5/211.311(2.3-1)
=212.310(1+5)/211.311.5
=2.6/3.5
=4/5
tính: \(\dfrac{4^{6} . 9^{5} + 6^{9} . 120}{-8^{4} . 3^{12} - 6^{11}}\)
\(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{-\left(2^{12}\cdot3^{12}+2^{11}\cdot3^{11}\right)}\)
\(=-\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\left(2\cdot3+1\right)}=\dfrac{-4}{7}\)
4^6*9^5+6^9*120/8^4*3^12-6^11
`Answer:`
`(4^6 . 9^5 + 6^9 . 120)/(8^4 . 3^12 - 6^11)`
`= (2^12 . 3^10 + 2^9 . 3^9 . 2^3 . 3 . 5)/(2^12 . 3^12 - 2^11 . 3^11)`
`= (2^12 . 3^10 + 2^12 . 3^10 . 5)/(2^11 . 3^11(2 . 3 - 1))`
`= (2^12 . 3^10 (1 + 5))/(2^11 . 3^11 . 5)`
`= (2 . 6)/(3 . 5)`
`= 4/5`
4^6 . 9^5 + 6^9 .120 / 8^4 . 3^12 - 6^11
\(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\) đề là như thế này à hay là sao ???
4^6 . 9^5 +6^9 . 120 / 8^4 . 3^12 - 6^11
4^6 . 4^5 + 6^9 . 120 / 8^4 . 3^12 - 6^11
10×4^6×9^5+6^9×120
8^4×3^12-6^11
\(\frac{10.4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}=\frac{2.5.\left(2.2\right)^6.\left(3.3\right)^5+\left(2.3\right)^9.3.40}{\left(2.2.2\right)^4.3^{12}-\left(2.3\right)^{11}}=\frac{2.5.2^6.2^6.3^5.3^5+2^9.3^9.3.40}{2^4.2^4.2^4.3^{12}-2^{11}.3^{11}}\)
\(=\frac{2^{13}.5.3^{10}+2^{12}.5.3^{10}}{2^{12}.3^{12}-2^{11}.3^{11}}=\frac{2^{12}.5.3^{10}.\left(2+1\right)}{2^{11}.3^{11}\left(2.3-1\right)}=\frac{2^{12}.5.3^{11}}{2^{11}.5.3^{11}}=2\)
tìm x thuộc Z
4^6 . 9^5 + 6^9 . 120 / 8^4 . 3^12 - 6^11 [phân số] + x = 1
ai làm được tui tick cho
46 .95 +69.120−84.312−611
=212 .310+29.39.23.3.5−212.312−211.311
=212.310+210.310.5−212.312−311.211
=211.310.(2+2.5)211.310.(−2.32−3)
=−47 +x=1
=>x=48
(4^6 nhân 9^5 +6^9 nhân 120) : (8^4 nhân 3^12 - 6^11)