Nguyễn Quỳnh Như

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Nguyễn Quỳnh Như
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Linh Nguyễn
11 tháng 8 2017 lúc 6:58

1. Vicky (1)said she (2)didn't know (3)where Michael (4)is => was

2. The womam (1)is => bỏ ''is'' standing next (2)to our teacher (3)is (4)my mother

3. He (1)is (2)proud (3)of his (4)wise=> wisdom

4. I (1)was so (2)excitement => excited (3)about the football match (4)last night

5. She (1)lives =>lived (2)in Rome (3)when she (4)was a little girl

6. He (1)will be (2)back (3)from => between 5:25 (4)and 6:20

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ÁcΦ┼Quỷ♪
11 tháng 8 2017 lúc 8:15

1. Vicky (1)said she (2)didn't know (3)where Michael (4)was

2. The womam (1) bỏ "is" standing next (2)to our teacher (3)is (4)my mother

3. He (1)is (2)proud (3)of his (4)wisdom

4. I (1)was so (2)excited (3)about the football match (4)last night

5. She (1) lived (2)in Rome (3)when she (4)was a little girl

6. He (1)will be (2)back (3) between 5:25 (4)and 6:20

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Tịnh y
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nhi lê
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Tịnh y
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Diệp Anh Hạ
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Super idol
19 tháng 12 2022 lúc 19:12

1. Could you tell me what are the problems on the delivery?

=> Could you tell me what are the problems with the delivery?         

2. who should we talk to about this broke TV?
=> who should we talk to about this broken TV

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nguyễn thư
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Hoàng Minh Ngọc
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Nguyễn Quỳnh Như
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Trần Nguyễn Bảo Quyên
4 tháng 8 2017 lúc 7:29

III/ rewrite each of the sentences by using the adverb clauses of result "SO"

1. We decided to leave early because the party was boring

-> The party was boring so we decided to leave early.

2. She phoned the police because she saw she wanted man in a small coffee shop

-> She saw she wanted man in a small coffee shop so she phoned the police.

3. She walked slowly because her leg was injured

-> Her leg was injured so she walked slowly.

4. Mary looked happy because she has just got good marks

-> Mary has just got good marks so she looked happy.

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Huỳnh Tấn Khải
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𝓓𝓾𝔂 𝓐𝓷𝓱
19 tháng 8 2021 lúc 10:46

PTHH: \(Al_2O_3+3H_2SO_4\rightarrow Al_2\left(SO_4\right)_3+3H_2O\)

Ta có: \(\left\{{}\begin{matrix}m_{H_2SO_4}=588\cdot5\%=29,4\left(g\right)\Rightarrow n_{H_2SO_4}=\dfrac{29,4}{98}=0,3\left(mol\right)\\n_{Al_2O_3}=\dfrac{20,4}{102}=0,2\left(mol\right)\end{matrix}\right.\)

Xét tỉ lệ: \(\dfrac{0,2}{1}>\dfrac{0,3}{3}\) \(\Rightarrow\) Al2O3 còn dư

\(\Rightarrow n_{Al_2\left(SO_4\right)_3}=0,1\left(mol\right)=n_{Al_2O_3\left(dư\right)}\)

\(\Rightarrow C\%_{Al_2\left(SO_4\right)_3}=\dfrac{0,1\cdot342}{20,4+588-0,1\cdot102}\cdot100\%\approx5,72\%\)

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