(5x-2).6^3=3.6^5 toan 6
Những câu hỏi liên quan
a) (2x-3).12=6^2
b) (5x-2).6^3=3.6^5
a: \(\left(2x-3\right)\cdot12=6^2\)
\(\Leftrightarrow2x-3=3\)
hay x=3
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a) (2x-3).12=62
=> (2x-3).12= 36
=> ( 2x-3)= 36 : 12
=> 2x-3 = 3
=> 2x = 3+3
=> 2x = 6
=> x = 6:2
=> x= 3
b)( 5x - 2 ) . 63= 3. 65
=> ( 5x - 2 ). 216= 23328
=> ( 5x - 2 ) = 23328 : 216
=> ( 5x - 2) = 108
=> 5x = 108 + 2
=> 5x = 110
=> x = 110 : 5
=> x = 22
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2 tháng 10 2021 lúc 16:00
Câu 2: Tính
C = \(\dfrac{6^3+3.6^2+3^3}{13}\)
D = \(\dfrac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
\(C=\dfrac{6^3+3\cdot6^2+3^3}{13}=\dfrac{3^3\cdot8+3^3\cdot4+3^3}{13}=27\)
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2 tháng 10 2021 lúc 19:39
BÀI 2 TÍNH :
A = \(\dfrac{6^3+3.6^2+3^3}{13}\)
B = \(\dfrac{4^6.9^5+6^9.120}{8^4-3^{12}.6^{11}}\)
\(A=\dfrac{6^3+3\cdot6^2+3^3}{13}\)
\(=\dfrac{3^3\cdot8+3^3\cdot4+3^3}{13}\)
=27
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6^3+3.6^2+3^5/-13
\(\dfrac{6^3+3\cdot6^2+3^5}{-13}=\dfrac{3^3\cdot2^3+3\cdot2^2\cdot3^2+3^5}{-13}\)
\(=\dfrac{3^3\left(2^3+2^2+3^2\right)}{-13}=\dfrac{3^3\cdot21}{-13}=\dfrac{-567}{13}\)
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a) \(\dfrac{6^3+3.6^2+3^3}{-13}\)
b) \(\dfrac{5^4.20^4}{24^5.4^5}\)
Tính giá trị biểu thức: 20^5.5^10/100^5. b)(0.9)^5/(0.3)^6. c)6^3+3.6^2+3^3/-13.
Tính giá trị biểu thức:
a)(0.6)^5/(0.2)^6
b)6^3+3.6+3^2
(0.6)^5/(0.2)^6
= [(0.2)^5. 3^5]/(0.2)^6
= 3^5/0.2
=243/0.2
= 1215
6^3+3.6^2+3^3/-13
= 2^3.3^3+3.2^2.3^2+3^3/-13
=3^3(2^3+2^2+1)/-13
=3^3.13/-13
=-27
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\(\frac{6^3+3\cdot6^2+3^3}{-13}=\frac{\left(3\cdot2\right)^3+3\cdot\left(3\cdot2\right)^2+3^3}{-13}=\frac{3^3\cdot2^3+3\cdot3^2\cdot2^2+3^3}{-13}=\frac{3^3\cdot\left(2^3+2^2+1\right)}{-13}=\frac{27\cdot13}{-13}=-27\)
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Tính giá trị của biểu thức: 20^5.5^10/100^5. b)(0.9)^5/(0.3)^6. c)6^3+3.6^2+3^3/-13.
Thực hiện phép tính:
a.0,3-4/9:4/3.6/5+1
b.1+2:(2/3-1/6).(-2,25)
c.[(1/4-0,5).2+8/3]:2
d.[(3/8-5/12).6+1/3].4
e.(4/5-1):3/5-2/3.0,5
f.0,8:{0,2-7.[1/6+(5/21-5/14)]}
`@` `\text {Ans}`
`\downarrow`
`a.`
\(0,3-\dfrac{4}{9}\div\dfrac{4}{3}\cdot\dfrac{6}{5}+1\)
`=`\(0,3-\dfrac{1}{3}\cdot\dfrac{6}{5}+1\)
`=`\(0,3-0,4+1\)
`= -0,1 + 1`
`= 0,9`
`b.`
\(1+2\div\left(\dfrac{2}{3}-\dfrac{1}{6}\right)\cdot\left(-2,25\right)\)
`=`\(1+2\div\dfrac{1}{2}\cdot\left(-2,25\right)\)
`=`\(1+4\cdot\left(-2,25\right)\)
`= 1+ (-9) = -8`
`c.`
\(\left[\left(\dfrac{1}{4}-0,5\right)\cdot2+\dfrac{8}{3}\right]\div2\)
`=`\(\left(-\dfrac{1}{4}\cdot2+\dfrac{8}{3}\right)\div2\)
`=`\(\left(-\dfrac{1}{2}+\dfrac{8}{3}\right)\div2\)
`=`\(\dfrac{13}{6}\div2\)
`=`\(\dfrac{13}{12}\)
`d.`
\(\left[\left(\dfrac{3}{8}-\dfrac{5}{12}\right)\cdot6+\dfrac{1}{3}\right]\cdot4\)
`=`\(\left(-\dfrac{1}{24}\cdot6+\dfrac{1}{3}\right)\cdot4\)
`=`\(\left(-\dfrac{1}{4}+\dfrac{1}{3}\right)\cdot4\)
`=`\(\dfrac{1}{12}\cdot4=\dfrac{1}{3}\)
`e.`
\(\left(\dfrac{4}{5}-1\right)\div\dfrac{3}{5}-\dfrac{2}{3}\cdot0,5\)
`=`\(-\dfrac{1}{5}\div\dfrac{3}{5}-\dfrac{1}{3}\)
`=`\(-\dfrac{1}{3}-\dfrac{1}{3}=-\dfrac{2}{3}\)
`f.`
\(0,8\div\left\{0,2-7\left[\dfrac{1}{6}+\left(\dfrac{5}{21}-\dfrac{5}{14}\right)\right]\right\}\)
`=`\(0,8\div\left[0,2-7\left(\dfrac{1}{6}-\dfrac{5}{42}\right)\right]\)
`=`\(0,8\div\left(0,2-7\cdot\dfrac{1}{21}\right)\)
`=`\(0,8\div\left(0,2-\dfrac{1}{3}\right)\)
`= 0,8 \div (-2/15)`
`=-6`
`@` `yHGiangg.`
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