Tính :
a) \(17+\left(-3\right)\)
b) \(\left(-96\right)+64\)
c) \(75+\left(-325\right)\)
Tính :
a) \(0+\left(-36\right)\)
b) \(\left|-29\right|+\left(-11\right)\)
c) \(75+\left(-325\right)\)
a ) thực hiện phép tính bằng cách nhanh nhất
\(\left(-\frac{40}{51}.0,32.\frac{17}{20}\right):\frac{64}{75}\)
\(-1\frac{5}{7}.15+\frac{2}{7}.\left(-15\right)+\left(-105\right).\left(\frac{2}{3}-\frac{4}{5}+\frac{1}{7}\right)\)
1. Thực hiện phép tính
a) \(25-\left(-75\right)+32-\left(32+75\right)\)
b) \(\left|-127\right|-18.\left(5-6\right)\)
c) \(17-25+55-17\)
a,\(25-\left(-75\right)+32-\left(32+75\right)\))
=\(25+75+32-32-75\)
=\(\left(75-75\right)+\left(32-32\right)+25\)
=\(0+0+25=25\)
\(b,\left|-127\right|-18.\left(5-6\right)\)
\(=127-18.\left(-1\right)\)
\(=127-\left(-18\right)\)
\(=145\)
\(c,17-25+55-17\)
\(=\left(17-17\right)+\left(55-25\right)\)
\(=0+30\)
\(=30\)
a)
25 - (-75) + 32 - ( 32 + 75 )
= 25 + 75 + 32 - 107
=100+32 - 107
=132 - 107
=25
b)
| - 127| - 18 . ( 5 - 6)
=127 - 18 . ( -1)
=127 - (-18)
=145
thực hiện cách hợp lí
a) \(\left(-\frac{40}{5}.0,32.\frac{17}{20}\right):\frac{64}{75}\)
b) \(-1\frac{5}{7}.15+\frac{2}{7}.\left(-15\right)+\left(-105\right).\left(\frac{2}{3}-\frac{4}{5}+\frac{1}{7}\right)\)
Tính
a, A=\(\left(\frac{-40}{51}.0,32.\frac{17}{20}\right).\frac{64}{75}\)
b, B=\(4\frac{5}{9}:\left(\frac{-5}{7}\right)-5\frac{4}{9}:\frac{5}{7}\)
c, C= \(1\frac{5}{7}.15+\frac{2}{9}.\left(-15\right)+105.\left(\frac{-2}{3}+\frac{4}{5}-\frac{1}{7}\right)\)
Rút gọn :
\(a,A=\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\\ b,B=-1^2+2^2-3^2+4^2-...-99^2+100^2\\ c,C=-1^2+2^2-3^2+4^2-...+\left(-1\right)^n\cdot n^2\\ d,D=3\cdot\left(2^2+1\right)\left(2^4+1\right)...\left(2^{64}+1\right)+1\\ e,E=\left(a+b+c\right)^2+\left(a+b-c\right)^2-2\left(a+b\right)^2\\ g,G=\left(a+b+c+d\right)^2+\left(a+b-c-d\right)^2+\left(a+c-b-d\right)^2+\left(a+d-b-c\right)^2\\ h,H=\left(a+b+c\right)^3-\left(b+c-a\right)^3-\left(a+c-b\right)^3+\left(a+b-c\right)^3\\ i,I=\left(a+b\right)^3+\left(b+c\right)^3+\left(c+a\right)^3-3\left(a+b\right)\left(c+b\right)\left(c+a\right)\)
Mọi người ơi, giúp mk vs, đc câu nào hay câu ấy ! Help me!!!!!!!!!!!!!!!!!!
a/ \(A=\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(2A=2\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(2A=\left(3-1\right)\left(3+1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(2A=\left(3^2-1\right)\left(3^2+1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(2A=\left(3^4-1\right)\left(3^4+1\right)...\left(3^{64}+1\right)\)
\(\Rightarrow2A=3^{128}-1\Rightarrow A=\dfrac{3^{128}-1}{2}\)
e) ta dể dàng thấy được : \(a^2+b^2=\left(a+b\right)^2-2ab\)
\(\Rightarrow E=\left(a+b+c\right)^2+\left(a+b-c\right)^2-2\left(a+b\right)^2\)
\(=\left(2a+2b\right)^2-2\left(a+b+c\right)\left(a+b-c\right)-2\left(a+b\right)^2\)
\(=4\left(a+b\right)^2-2\left(\left(a+b\right)^2-c^2\right)-2\left(a+b\right)^2\)
\(=4\left(a+b\right)^2-2\left(a+b\right)^2+2c^2-2\left(a+b\right)^2=2c^2\)
g) củng sử dụng cái trên ta có : \(G=\left(a+b+c+d\right)^2+\left(a+b-c-d\right)^2+\left(a+c-b-d\right)^2+\left(a+d-b-c\right)^2\)
\(=\left(2a+2b\right)^2-2\left(a+b+c+d\right)\left(a+b-c-d\right)+\left(2a-2b\right)^2-2\left(a+c-b-d\right)\left(a+d-b-c\right)\)
\(=4\left(a+b\right)^2+4\left(a-b\right)^2-2\left(\left(a+b\right)^2-\left(c+d\right)^2\right)-2\left(\left(a-b\right)^2-\left(c-d\right)^2\right)\)
\(=4\left(\left(a+b\right)^2+\left(a-b\right)^2\right)-2\left(\left(a+b\right)^2+\left(a-b\right)^2\right)+2\left(\left(c+d\right)^2+\left(c-d\right)^2\right)\)
\(=2\left(\left(a+b\right)^2+\left(a-b\right)^2\right)+2\left(\left(c+d\right)^2+\left(c-d\right)^2\right)\)\(=2\left(\left(2a\right)^2-2\left(a+b\right)\left(a-b\right)\right)+2\left(\left(2c\right)^2-2\left(c+d\right)\left(c-d\right)\right)\)
\(=2\left(4a^2-2\left(a^2-b^2\right)\right)+2\left(4c^2-2\left(c^2-d^2\right)\right)\)
\(=2\left(2a^2+2b^2\right)+2\left(2c^2+2d^2\right)=4\left(a^2+b^2+c^2+d^2\right)\)
bn đăng nhiều quá nên mk làm câu nào hay câu đó nha
mà nè mấy câu a;b;c;d hình như trên mạng có bn lên đó tìm nha .
Tính nhanh
a,\(A=100^2-99^2+98^2-97^2+...+2^2-1^2\)
b,\(B=\left(20^2+18^2+...+2^2\right)-\left(19^2+17^2+....+3^2+1^2\right)\)
c,\(C=\frac{780^2-220^2}{125^2+150.125+75^2}\)
d,\(D=2.\left(a+5\right).\left(a+4\right)-\left(a+5\right)^2-\left(a^2-9a-17\right)\)với a=99
a/ A = 1002 - 992 + 982 -...+22 - 12
= (1002 - 992) + (982 - 972) +...+ (22 - 12)
= 199 + 195 + 191 + ... + 1
= (\(\frac{199-1}{4}+1\))(\(\frac{199+1}{2}\)) = 5050
b/ Y chang câu a luôn nha
c/ \(C=\frac{780^2-220^2}{125^2+150.125+75^2}=\frac{\left(780-220\right)\left(780+220\right)}{\left(125+75\right)^2}\)
\(=\frac{560.1000}{200^2}=14\)
d/ 2(a + 4)(a + 5) - (a + 5)2 - (a2 - 9a - 17)
= 17a + 32 = 17(a + 1) + 15 = 1700 + 15 = 1715
Tính nhanh:
a) \(\left(-37-17\right)\cdot\left(-9\right)+35\cdot\left(-9-11\right)\)
b) \(\left(-25\right)\cdot\left(75-45\right)-75\cdot\left(45-25\right)\)
Dùng máy tính bỏ túi để tính :
a) \(\left(-1356\right).17\)
b) \(39.\left(-152\right)\)
c) \(\left(-1909\right).\left(-75\right)\)
Sử dụng máy tính bỏ túi
a) (-1356).17 = -23052
b) 39.(-152) = -5928
c) (-1909).(-75) = 143175
a) (-1356).17 = -23052
b) 39.(-152) = -5928
c) (-1909).(-75) = 143175